第一个例子是，当使用上面投票最高的答案时，我得到的字符串长度大于1的单个字符。下面是我解决这个问题的方法。

var stringObject = ["", "some string yay", "", "", "Other string yay"];
stringObject = stringObject.filter(function(n){ return n.length > 0});

如果未定义，则不返回，如果长度大于0，则返回。希望这能帮助一些人。

退换商品

["some string yay", "Other string yay"]

“误用”。。。在（对象成员）循环中。=>循环体中仅显示真实值。

// --- Example ----------
var field = [];

field[0] = 'One';
field[1] = 1;
field[3] = true;
field[5] = 43.68;
field[7] = 'theLastElement';
// --- Example ----------

var originalLength;

// Store the length of the array.
originalLength = field.length;

for (var i in field) {
  // Attach the truthy values upon the end of the array. 
  field.push(field[i]);
}

// Delete the original range within the array so that
// only the new elements are preserved.
field.splice(0, originalLength);

我需要完成同样的任务，并遇到了这个线程。我最终使用数组“join”使用“_”分隔符创建字符串，然后使用正则表达式：-

1. replace "__" or more with just one "_",
2. replace preceding "_" with nothing "" and similarly 
3. replace and ending "_" with nothing ""

…然后使用数组“拆分”生成一个已清理的数组：-

var myArr = new Array("","","a","b","","c","","","","","","","","","e","");
var myStr = "";

myStr = myArr.join("_");

myStr = myStr.replace(new RegExp(/__*/g),"_");
myStr = myStr.replace(new RegExp(/^_/i),"");
myStr = myStr.replace(new RegExp(/_$/i),"");
myArr = myStr.split("_");

alert("myArr=" + myArr.join(","));

…或1行代码：-

var myArr = new Array("","","a","b","","c","","","","","","","","","e","");

myArr = myArr.join("_").replace(new RegExp(/__*/g),"_").replace(new RegExp(/^_/i),"").replace(new RegExp(/_$/i),"").split("_");

alert("myArr=" + myArr.join(","));

…或，扩展Array对象：-

Array.prototype.clean = function() {
  return this.join("_").replace(new RegExp(/__*/g),"_").replace(new RegExp(/^_/i),"").replace(new RegExp(/_$/i),"").split("_");
};

var myArr = new Array("","","a","b","","c","","","","","","","","","e","");

alert("myArr=" + myArr.clean().join(","));

几个简单的方法：

var arr = [1,2,,3,,-3,null,,0,,undefined,4,,4,,5,,6,,,,];

arr.filter(n => n)
// [1, 2, 3, -3, 4, 4, 5, 6]

arr.filter(Number) 
// [1, 2, 3, -3, 4, 4, 5, 6]

arr.filter(Boolean) 
// [1, 2, 3, -3, 4, 4, 5, 6]

或-（仅适用于“text”类型的单个数组项）

['','1','2',3,,'4',,undefined,,,'5'].join('').split(''); 
// output:  ["1","2","3","4","5"]

或-经典方式：简单迭代

var arr = [1,2,null, undefined,3,,3,,,0,,,[],,{},,5,,6,,,,],
    len = arr.length, i;

for(i = 0; i < len; i++ )
    arr[i] && arr.push(arr[i]);  // copy non-empty values to the end of the array

arr.splice(0 , len);  // cut the array and leave only the non-empty values
// [1,2,3,3,[],Object{},5,6]

jQuery：

var arr = [1,2,,3,,3,,,0,,,4,,4,,5,,6,,,,];
    
arr = $.grep(arr, n => n == 0 || n);
// [1, 2, 3, 3, 0, 4, 4, 5, 6]

由于没有其他人提到它，而且大多数人的项目中都包含下划线，因此您也可以使用_.without（array，*values）；。

_.without(["text", "string", null, null, null, "text"], null)
// => ["text", "string", "text"]

就地解决方案：

function pack(arr) { // remove undefined values
  let p = -1
  for (let i = 0, len = arr.length; i < len; i++) {
    if (arr[i] !== undefined) { if (p >= 0) { arr[p] = arr[i]; p++ } }
    else if (p < 0) p = i
  }
  if (p >= 0) arr.length = p
  return arr
}

let a = [1, 2, 3, undefined, undefined, 4, 5, undefined, null]
console.log(JSON.stringify(a))
pack(a)
console.log(JSON.stringify(a))