我正在努力理解Python中的线程。我看过文档和示例,但坦率地说,许多示例过于复杂,我很难理解它们。

如何清楚地显示为多线程划分的任务?


当前回答

Python 3具有启动并行任务的功能。这使我们的工作更容易。

它有线程池和进程池。

以下内容提供了一个见解:

ThreadPoolExecutor示例(源代码)

import concurrent.futures
import urllib.request

URLS = ['http://www.foxnews.com/',
        'http://www.cnn.com/',
        'http://europe.wsj.com/',
        'http://www.bbc.co.uk/',
        'http://some-made-up-domain.com/']

# Retrieve a single page and report the URL and contents
def load_url(url, timeout):
    with urllib.request.urlopen(url, timeout=timeout) as conn:
        return conn.read()

# We can use a with statement to ensure threads are cleaned up promptly
with concurrent.futures.ThreadPoolExecutor(max_workers=5) as executor:
    # Start the load operations and mark each future with its URL
    future_to_url = {executor.submit(load_url, url, 60): url for url in URLS}
    for future in concurrent.futures.as_completed(future_to_url):
        url = future_to_url[future]
        try:
            data = future.result()
        except Exception as exc:
            print('%r generated an exception: %s' % (url, exc))
        else:
            print('%r page is %d bytes' % (url, len(data)))

ProcessPoolExecutor(源)

import concurrent.futures
import math

PRIMES = [
    112272535095293,
    112582705942171,
    112272535095293,
    115280095190773,
    115797848077099,
    1099726899285419]

def is_prime(n):
    if n % 2 == 0:
        return False

    sqrt_n = int(math.floor(math.sqrt(n)))
    for i in range(3, sqrt_n + 1, 2):
        if n % i == 0:
            return False
    return True

def main():
    with concurrent.futures.ProcessPoolExecutor() as executor:
        for number, prime in zip(PRIMES, executor.map(is_prime, PRIMES)):
            print('%d is prime: %s' % (number, prime))

if __name__ == '__main__':
    main()

其他回答

与其他提到的一样,由于GIL,CPython只能在I/O等待时使用线程。

如果您想从多个内核中获得CPU绑定任务的好处,请使用多处理:

from multiprocessing import Process

def f(name):
    print 'hello', name

if __name__ == '__main__':
    p = Process(target=f, args=('bob',))
    p.start()
    p.join()

使用线程/多处理的最简单方法是使用更多高级库,如autothread。

import autothread
from time import sleep as heavyworkload

@autothread.multithreaded() # <-- This is all you need to add
def example(x: int, y: int):
    heavyworkload(1)
    return x*y

现在,您可以为函数提供int列表。Autothread将为您处理所有事务,并只提供并行计算的结果。

result = example([1, 2, 3, 4, 5], 10)

这里有一个简单的示例:您需要尝试一些替代URL,并返回第一个URL的内容以进行响应。

import Queue
import threading
import urllib2

# Called by each thread
def get_url(q, url):
    q.put(urllib2.urlopen(url).read())

theurls = ["http://google.com", "http://yahoo.com"]

q = Queue.Queue()

for u in theurls:
    t = threading.Thread(target=get_url, args = (q,u))
    t.daemon = True
    t.start()

s = q.get()
print s

在这种情况下,线程被用作一种简单的优化:每个子线程都在等待URL解析和响应,以将其内容放入队列;每个线程都是一个守护进程(如果主线程结束,则不会保持进程运行——这比不结束更常见);主线程启动所有子线程,在队列中执行get以等待其中一个线程完成put,然后发出结果并终止(这将删除所有可能仍在运行的子线程,因为它们是守护进程线程)。

Python中线程的正确使用总是与I/O操作相关(因为CPython无论如何都不使用多个内核来运行CPU绑定的任务,线程的唯一原因是在等待一些I/O时不会阻塞进程)。顺便说一句,队列几乎总是将工作分配给线程和/或收集工作结果的最佳方式,而且它们本质上是线程安全的,因此它们使您不用担心锁、条件、事件、信号量和其他线程间协调/通信概念。

下面的代码可以运行10个线程同时打印0到99之间的数字:

from threading import Thread

def test():
    for i in range(0, 100):
        print(i)

thread_list = []

for _ in range(0, 10):
    thread = Thread(target=test)
    thread_list.append(thread)

for thread in thread_list:
    thread.start()

for thread in thread_list:
    thread.join()

下面的代码是上述代码循环版本的简写,运行10个线程,同时打印0到99之间的数字:

from threading import Thread

def test():
    [print(i) for i in range(0, 100)]

thread_list = [Thread(target=test) for _ in range(0, 10)]

[thread.start() for thread in thread_list]

[thread.join() for thread in thread_list]

结果如下:

...
99
83
97
84
98
99
85
86
87
88
...

只需注意:线程不需要队列。

这是我可以想象的最简单的例子,它显示了10个并发运行的进程。

import threading
from random import randint
from time import sleep


def print_number(number):

    # Sleeps a random 1 to 10 seconds
    rand_int_var = randint(1, 10)
    sleep(rand_int_var)
    print "Thread " + str(number) + " slept for " + str(rand_int_var) + " seconds"

thread_list = []

for i in range(1, 10):

    # Instantiates the thread
    # (i) does not make a sequence, so (i,)
    t = threading.Thread(target=print_number, args=(i,))
    # Sticks the thread in a list so that it remains accessible
    thread_list.append(t)

# Starts threads
for thread in thread_list:
    thread.start()

# This blocks the calling thread until the thread whose join() method is called is terminated.
# From http://docs.python.org/2/library/threading.html#thread-objects
for thread in thread_list:
    thread.join()

# Demonstrates that the main process waited for threads to complete
print "Done"