当在c++中覆盖一个类(使用虚析构函数)时，我在继承类上再次实现了虚析构函数，但我需要调用基析构函数吗?
如果是这样的话，我想应该是这样的……
MyChildClass::~MyChildClass() // virtual in header
{
// Call to base destructor...
this->MyBaseClass::~MyBaseClass();
// Some destructing specific to MyChildClass
}
我说的对吗?
当前回答
不，析构函数是按照构造的相反顺序自动调用的。(基类最后)。不要调用基类析构函数。
其他回答
不，你不需要调用基析构函数，基析构函数总是由派生析构函数调用。请参阅我的相关回答在这里的破坏顺序。
要理解为什么要在基类中使用虚析构函数，请参阅下面的代码:
class B
{
public:
virtual ~B()
{
cout<<"B destructor"<<endl;
}
};
class D : public B
{
public:
virtual ~D()
{
cout<<"D destructor"<<endl;
}
};
当你这样做时:
B *pD = new D();
delete pD;
然后，如果在B中没有虚析构函数，则只会调用~B()。但是由于您有一个虚析构函数，首先将调用~D()，然后是~B()。
c++中的析构函数只有在基类析构函数声明为虚时才会自动按其构造的顺序(先派生后基)调用。
如果不是，则在删除对象时只调用基类析构函数。
示例:没有虚析构函数
#include <iostream>
using namespace std;
class Base{
public:
Base(){
cout << "Base Constructor \n";
}
~Base(){
cout << "Base Destructor \n";
}
};
class Derived: public Base{
public:
int *n;
Derived(){
cout << "Derived Constructor \n";
n = new int(10);
}
void display(){
cout<< "Value: "<< *n << endl;
}
~Derived(){
cout << "Derived Destructor \n";
}
};
int main() {
Base *obj = new Derived(); //Derived object with base pointer
delete(obj); //Deleting object
return 0;
}
输出
Base Constructor
Derived Constructor
Base Destructor
示例:使用基本虚析构函数
#include <iostream>
using namespace std;
class Base{
public:
Base(){
cout << "Base Constructor \n";
}
//virtual destructor
virtual ~Base(){
cout << "Base Destructor \n";
}
};
class Derived: public Base{
public:
int *n;
Derived(){
cout << "Derived Constructor \n";
n = new int(10);
}
void display(){
cout<< "Value: "<< *n << endl;
}
~Derived(){
cout << "Derived Destructor \n";
delete(n); //deleting the memory used by pointer
}
};
int main() {
Base *obj = new Derived(); //Derived object with base pointer
delete(obj); //Deleting object
return 0;
}
输出
Base Constructor
Derived Constructor
Derived Destructor
Base Destructor
建议将基类析构函数声明为虚值，否则会导致未定义的行为。
参考:虚析构函数
不，析构函数是按照构造的相反顺序自动调用的。(基类最后)。不要调用基类析构函数。
不，你永远不会调用基类析构函数，它总是自动调用，就像其他人指出的那样，但这里是概念的证明和结果:
class base {
public:
base() { cout << __FUNCTION__ << endl; }
~base() { cout << __FUNCTION__ << endl; }
};
class derived : public base {
public:
derived() { cout << __FUNCTION__ << endl; }
~derived() { cout << __FUNCTION__ << endl; } // adding call to base::~base() here results in double call to base destructor
};
int main()
{
cout << "case 1, declared as local variable on stack" << endl << endl;
{
derived d1;
}
cout << endl << endl;
cout << "case 2, created using new, assigned to derive class" << endl << endl;
derived * d2 = new derived;
delete d2;
cout << endl << endl;
cout << "case 3, created with new, assigned to base class" << endl << endl;
base * d3 = new derived;
delete d3;
cout << endl;
return 0;
}
输出结果为:
case 1, declared as local variable on stack
base::base
derived::derived
derived::~derived
base::~base
case 2, created using new, assigned to derive class
base::base
derived::derived
derived::~derived
base::~base
case 3, created with new, assigned to base class
base::base
derived::derived
base::~base
Press any key to continue . . .
如果将基类析构函数设置为虚函数，那么情况3的结果将与情况1和2相同。
不。它会被自动调用。
