我如何在Swift中打印变量的类型或类?

是否有一种方法可以在swift中打印变量的运行时类型?例如:

var now = NSDate()
var soon = now.dateByAddingTimeInterval(5.0)

println("\(now.dynamicType)") 
// Prints "(Metatype)"

println("\(now.dynamicType.description()")
// Prints "__NSDate" since objective-c Class objects have a "description" selector

println("\(soon.dynamicType.description()")
// Compile-time error since ImplicitlyUnwrappedOptional<NSDate> has no "description" method

在上面的例子中，我正在寻找一种方法来显示变量“soon”的类型是ImplicitlyUnwrappedOptional<NSDate>，或至少NSDate!

当前回答

Swift 3.0, Xcode 8

使用下面的代码，您可以向实例请求其类。你也可以比较两个实例，是否具有相同的类。

// CREATE pure SWIFT class
class MySwiftClass {
    var someString : String = "default"
    var someInt    : Int = 5
}

// CREATE instances
let firstInstance = MySwiftClass()
let secondInstance = MySwiftClass()
secondInstance.someString = "Donald"
secondInstance.someInt = 24

// INSPECT instances
if type(of: firstInstance) === MySwiftClass.self {
    print("SUCCESS with ===")
} else {
    print("PROBLEM with ===")
}

if type(of: firstInstance) == MySwiftClass.self {
    print("SUCCESS with ==")
} else {
    print("PROBLEM with ==")
}

// COMPARE CLASS OF TWO INSTANCES
if type(of: firstInstance) === type(of: secondInstance) {
    print("instances have equal class")
} else {
    print("instances have NOT equal class")
}

2016-11-10 11:09:52

其他回答

上面的答案没有使用type(of:的新方法的工作示例。所以为了帮助像我这样的新手，这里有一个工作的例子，主要来自苹果的文档- https://developer.apple.com/documentation/swift/2885064-type

doubleNum = 30.1

func printInfo(_ value: Any) {
    let varType = type(of: value)
    print("'\(value)' of type '\(varType)'")
}

printInfo(doubleNum)
//'30.1' of type 'Double'

2017-09-06 05:17:05

根据上面Klass和Kevin Ballard给出的答案和评论，我认为:

println(_stdlib_getDemangledTypeName(now).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(soon).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(soon?).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(soon!).componentsSeparatedByString(".").last!)

println(_stdlib_getDemangledTypeName(myvar0).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(myvar1).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(myvar2).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(myvar3).componentsSeparatedByString(".").last!)

这将打印出:

"NSDate"
"ImplicitlyUnwrappedOptional"
"Optional"
"NSDate"

"NSString"
"PureSwiftClass"
"Int"
"Double"

2015-01-01 12:15:43

在Xcode 8, Swift 3.0

步骤:

1. 获取类型:

选项1:

let type : Type = MyClass.self  //Determines Type from Class

选项2:

let type : Type = type(of:self) //Determines Type from self

2. 转换类型为字符串:

let string : String = "\(type)" //String

2016-10-09 12:13:18

您仍然可以通过className(返回String)访问该类。

实际上有几种方法来获取类，例如classForArchiver, classForCoder, classForKeyedArchiver(都返回AnyClass!)

无法获取原语的类型(原语不是类)。

例子:

var ivar = [:]
ivar.className // __NSDictionaryI

var i = 1
i.className // error: 'Int' does not have a member named 'className'

如果你想获取一个原语的类型，你必须使用bridgetooobjecvec()。例子:

var i = 1
i.bridgeToObjectiveC().className // __NSCFNumber

2014-06-03 02:30:00

Xcode 8 Swift 3.0使用类型:

let className = "\(type(of: instance))"

2016-09-19 19:10:25

我如何在Swift中打印变量的类型或类?

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