是否有一种方法可以在swift中打印变量的运行时类型?例如:
var now = NSDate()
var soon = now.dateByAddingTimeInterval(5.0)
println("\(now.dynamicType)")
// Prints "(Metatype)"
println("\(now.dynamicType.description()")
// Prints "__NSDate" since objective-c Class objects have a "description" selector
println("\(soon.dynamicType.description()")
// Compile-time error since ImplicitlyUnwrappedOptional<NSDate> has no "description" method
在上面的例子中，我正在寻找一种方法来显示变量“soon”的类型是ImplicitlyUnwrappedOptional<NSDate>，或至少NSDate!
当前回答
斯威夫特3.0
let string = "Hello"
let stringArray = ["one", "two"]
let dictionary = ["key": 2]
print(type(of: string)) // "String"
// Get type name as a string
String(describing: type(of: string)) // "String"
String(describing: type(of: stringArray)) // "Array<String>"
String(describing: type(of: dictionary)) // "Dictionary<String, Int>"
// Get full type as a string
String(reflecting: type(of: string)) // "Swift.String"
String(reflecting: type(of: stringArray)) // "Swift.Array<Swift.String>"
String(reflecting: type(of: dictionary)) // "Swift.Dictionary<Swift.String, Swift.Int>"
其他回答
请看看下面的代码片段，让我知道你是否在寻找下面这样的东西。
var now = NSDate()
var soon = now.addingTimeInterval(5.0)
var nowDataType = Mirror(reflecting: now)
print("Now is of type: \(nowDataType.subjectType)")
var soonDataType = Mirror(reflecting: soon)
print("Soon is of type: \(soonDataType.subjectType)")
在Swift 3.0中，你可以使用type(of:)，因为dynamicType关键字已被删除。
根据上面Klass和Kevin Ballard给出的答案和评论，我认为:
println(_stdlib_getDemangledTypeName(now).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(soon).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(soon?).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(soon!).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(myvar0).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(myvar1).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(myvar2).componentsSeparatedByString(".").last!)
println(_stdlib_getDemangledTypeName(myvar3).componentsSeparatedByString(".").last!)
这将打印出:
"NSDate"
"ImplicitlyUnwrappedOptional"
"Optional"
"NSDate"
"NSString"
"PureSwiftClass"
"Int"
"Double"
不完全是你想要的，但你也可以检查Swift类型的变量类型，像这样:
let object: AnyObject = 1
if object is Int {
}
else if object is String {
}
为例。
您仍然可以通过className(返回String)访问该类。
实际上有几种方法来获取类，例如classForArchiver, classForCoder, classForKeyedArchiver(都返回AnyClass!)
无法获取原语的类型(原语不是类)。
例子:
var ivar = [:]
ivar.className // __NSDictionaryI
var i = 1
i.className // error: 'Int' does not have a member named 'className'
如果你想获取一个原语的类型，你必须使用bridgetooobjecvec()。例子:
var i = 1
i.bridgeToObjectiveC().className // __NSCFNumber
