我有一个包含对象数组的对象。

obj = {};

obj.arr = new Array();

obj.arr.push({place:"here",name:"stuff"});
obj.arr.push({place:"there",name:"morestuff"});
obj.arr.push({place:"there",name:"morestuff"});

我想知道从数组中删除重复对象的最佳方法是什么。例如,obj.arr将变成。。。

{place:"here",name:"stuff"},
{place:"there",name:"morestuff"}

当前回答

ES6一个衬垫在这里

设arr=[{id:1,名称:“sravan ganji”},{id:2,name:“pinky”},{id:4,名称:“mammu”},{id:3,名称:“avy”},{id:3,名称:“rashni”},];console.log(Object.values(arr.reduce((acc,cur)=>Object.assign(acc、{[cur.id]:cur}),{}

其他回答

使用ES6“reduce”和“find”数组助手方法的简单解决方案

工作效率高,非常好!

"use strict";

var things = new Object();
things.thing = new Array();
things.thing.push({
    place: "here",
    name: "stuff"
});
things.thing.push({
    place: "there",
    name: "morestuff"
});
things.thing.push({
    place: "there",
    name: "morestuff"
});

// the logic is here

function removeDup(something) {
    return something.thing.reduce(function (prev, ele) {
        var found = prev.find(function (fele) {
            return ele.place === fele.place && ele.name === fele.name;
        });
        if (!found) {
            prev.push(ele);
        }
        return prev;
    }, []);
}
console.log(removeDup(things));

如果您只需要通过对象的一个字段进行比较,则可以使用Array迭代方法执行此操作:

    function uniq(a, param){
        return a.filter(function(item, pos, array){
            return array.map(function(mapItem){ return mapItem[param]; }).indexOf(item[param]) === pos;
        })
    }

    uniq(things.thing, 'place');

如果需要基于对象中的多个财产的唯一数组,可以通过映射和组合对象的财产来实现。

    var hash = array.map(function(element){
        var string = ''
        for (var key in element){
            string += element[key]
        }
        return string
    })
    array = array.filter(function(element, index){
        var string = ''
        for (var key in element){
            string += element[key]
        }
        return hash.indexOf(string) == index
    })

考虑lodash.uniqWith

const objects = [{ 'x': 1, 'y': 2 }, { 'x': 2, 'y': 1 }, { 'x': 1, 'y': 2 }];
 
_.uniqWith(objects, _.isEqual);
// => [{ 'x': 1, 'y': 2 }, { 'x': 2, 'y': 1 }]
const uniqueElements = (arr, fn) => arr.reduce((acc, v) => {
    if (!acc.some(x => fn(v, x))) { acc.push(v); }
    return acc;
}, []);

const stuff = [
    {place:"here",name:"stuff"},
    {place:"there",name:"morestuff"},
    {place:"there",name:"morestuff"},
];

const unique = uniqueElements(stuff, (a,b) => a.place === b.place && a.name === b.name );
//console.log( unique );

[{
    "place": "here",
    "name": "stuff"
  },
  {
    "place": "there",
    "name": "morestuff"
}]