有没有比下面的pausecomp函数(取自此处)更好的方法来设计JavaScript中的睡眠?

function pausecomp(millis)
{
    var date = new Date();
    var curDate = null;
    do { curDate = new Date(); }
    while(curDate-date < millis);
}

这不是JavaScript中的Sleep的重复-动作之间的延迟;我希望在函数的中间有一个真正的睡眠,而不是在代码执行之前有一段延迟。


当前回答

我在JavaScript sleep/wait上搜索了很多网页。。。如果你想让JavaScript“RUN,DELAY,RUN”。。。大多数人得到的要么是“RUN,RUN(无用的东西),RUN”,要么是“RUN,RUN+延迟RUN”。。。

我想:这是一个有效的解决方案。。。但你必须把你的跑步代码切碎…:是的,我知道,这只是一个更容易理解的重构。。。还

示例1:

<html>
<body>
<div id="id1">DISPLAY</div>

<script>
// JavaScript sleep by "therealdealsince1982"; copyrighted 2009
// setInterval
var i = 0;

function run() {
    // Pieces of codes to run
    if (i == 0){document.getElementById("id1").innerHTML= "<p>code segment " + i + " is ran</p>"; }
    if (i == 1){document.getElementById("id1").innerHTML= "<p>code segment " + i + " is ran</p>"; }
    if (i == 2){document.getElementById("id1").innerHTML= "<p>code segment " + i + " is ran</p>"; }
    if (i >2){document.getElementById("id1").innerHTML= "<p>code segment " + i + " is ran</p>"; }
    if (i == 5){document.getElementById("id1").innerHTML= "<p>all code segment finished running</p>"; clearInterval(t); } // End interval, stops run
    i++; // Segment of code finished running, next...
}

run();
t = setInterval("run()", 1000);

</script>
</body>
</html>

示例2:

<html>
<body>
<div id="id1">DISPLAY</div>

<script>
// JavaScript sleep by "therealdealsince1982"; copyrighted 2009
// setTimeout
var i = 0;

function run() {
    // Pieces of codes to run, can use switch statement
    if (i == 0){document.getElementById("id1").innerHTML= "<p>code segment " + i + " ran</p>"; sleep(1000);}
    if (i == 1){document.getElementById("id1").innerHTML= "<p>code segment " + i + " ran</p>"; sleep(2000);}
    if (i == 2){document.getElementById("id1").innerHTML= "<p>code segment " + i + " ran</p>"; sleep(3000);}
    if (i == 3){document.getElementById("id1").innerHTML= "<p>code segment " + i + " ran</p>";} //stops automatically
    i++;
}

function sleep(dur) {t=setTimeout("run()", dur);} // Starts flow control again after 'dur'

run(); // Starts
</script>
</body>
</html>

示例3:

<html>
<body>
<div id="id1">DISPLAY</div>

<script>
// JavaScript sleep by "therealdealsince1982"; copyrighted 2009
// setTimeout
var i = 0;

function flow() {
    run(i);
    i++; // Code segment finished running, increment i; can put elsewhere
    sleep(1000);
    if (i == 5) {clearTimeout(t);} // Stops flow, must be after sleep()
}

function run(segment) {
    // Pieces of codes to run, can use switch statement
    if (segment == 0){document.getElementById("id1").innerHTML= "<p>code segment " + segment + " is ran</p>"; }
    if (segment == 1){document.getElementById("id1").innerHTML= "<p>code segment " + segment + " is ran</p>"; }
    if (segment == 2){document.getElementById("id1").innerHTML= "<p>code segment " + segment + " is ran</p>"; }
    if (segment >2){document.getElementById("id1").innerHTML= "<p>code segment "+ segment +" is ran</p>"; }
}

function sleep(dur) {t=setTimeout("flow()", dur);} // Starts flow control again after 'dur'

flow(); // Starts flow
</script>
</body>
</html>

示例4:

<html>
<body>
<div id="id1">DISPLAY</div>

<script>
// JavaScript sleep by "therealdealsince1982"; copyrighted 2009
// setTimeout, switch
var i = 0;

function flow() {
    switch(i)
    {
        case 0:
            run(i);
            sleep(1000);
            break;
        case 1:
            run(i);
            sleep(2000);
            break;
        case 5:
            run(i);
            clearTimeout(t); // Stops flow
            break;
        default:
            run(i);
            sleep(3000);
            break;
    }
}

function run(segment) {
    // Pieces of codes to run, can use switch statement
    if (segment == 0){document.getElementById("id1").innerHTML= "<p>code segment " + segment + " is ran</p>"; }
    if (segment == 1){document.getElementById("id1").innerHTML= "<p>code segment " + segment + " is ran</p>"; }
    if (segment == 2){document.getElementById("id1").innerHTML= "<p>code segment " + segment + " is ran</p>"; }
    if (segment >2){document.getElementById("id1").innerHTML= "<p>code segment " + segment + " is ran</p>"; }
    i++; // Current segment of code finished running, next...
}

function sleep(dur) {t=setTimeout("flow()", dur);} // Starts flow control again after 'dur'

flow(); // Starts flow control for first time...
</script>
</body>
</html>

其他回答

没有任何依赖关系的最短解决方案:

await new Promise(resolve => setTimeout(resolve, 5000));

如果您想休眠一个匿名函数,就像您创建的处理程序一样,我建议您使用以下方法:

function()
{
    if (!wait_condition)
    {
        setTimeout(arguments.callee, 100, /* Comma-separated arguments here */);
    }
    // The rest of the function
}

这段代码表示“如果等待条件尚未满足,请使用这些参数再次调用此函数。”。

如果你写一个这样的睡眠函数

var sleep = function(period, decision, callback){
    var interval = setInterval(function(){
        if (decision()) {
            interval = clearInterval(interval);
            callback();
        }
    }, period);
}

你有一个异步函数可以多次调用,

var xhr = function(url, callback){
    // Make an Ajax request
    // Call a callback when the request fulfils
}

您的项目设置如下:

var ready = false;

function xhr1(){
    xhr(url1, function(){ ready = true;});
}
function xhr2(){
    xhr(url2, function(){ ready = true; });
}
function xhr3(){
    xhr(url3, function(){ ready = true; });
}

然后您可以执行以下操作:

xhr1();
sleep(100, function(){ return done; }, xhr2);
sleep(100, function(){ return done; }, xhr3);
sleep(100, function(){ return done; }, function(){
    // Do more
});

而不是像这样无休止的回调缩进:

xhr(url1, function(){
    xhr2(url2, function(){
        xhr3(url3, function(){
            // Do more
        });
    });
});

干得好。正如代码所说,不要做一个糟糕的开发人员,在网站上使用它。这是一个开发实用函数。

// Basic sleep function based on ms.
// DO NOT USE ON PUBLIC FACING WEBSITES.
function sleep(ms) {
    var unixtime_ms = new Date().getTime();
    while(new Date().getTime() < unixtime_ms + ms) {}
}

这里大多数解决方案的问题是它们倒带堆栈。在某些情况下,这可能是一个大问题。在这个例子中,我展示了如何以不同的方式使用迭代器来模拟真实的睡眠。

在本例中,生成器正在调用自己的next(),因此一旦它启动,它就自己运行了。

var h = a();
h.next().value.r = h; // That's how you run it. It is the best I came up with

// Sleep without breaking the stack!!!
function *a(){
    var obj = {};

    console.log("going to sleep....2s")

    setTimeout(function(){obj.r.next();}, 2000)
    yield obj;

    console.log("woke up");
    console.log("going to sleep no 2....2s")
    setTimeout(function(){obj.r.next();}, 2000)
    yield obj;

    console.log("woke up");
    console.log("going to sleep no 3....2s")

    setTimeout(function(){obj.r.next();}, 2000)
    yield obj;

    console.log("done");
}