如何在Ruby中编写switch语句?


当前回答

由于switch-case始终返回单个对象,因此我们可以直接打印其结果:

puts case a
     when 0
        "It's zero"
     when 1
        "It's one"
     end

其他回答

如果您需要“小于”或“大于”:

case x
when 1..5
  "It's between 1 and 5"
when 6
  "It's 6"
when 7..1.0/0
  "It's equal or greater than 7"
when -1.0/0..0
  "It's equal or less than 0"
end

1.0/0等于Float::INFINITY,因此您可以使用自己喜欢的。

在Ruby 2.6之后,您可以使用Endless Ranges,在Ruby 2.7之后,您还可以使用Beginless Ranges,例如:

case x
when 1..5
  "It's between 1 and 5"
when 6
  "It's 6"
when (7..)
  "It's equal or greater than 7"
when (..0)
  "It's equal or less than 0"
end

你可以用更自然的方式这样做,

case expression
when condtion1
   function
when condition2
   function
else
   function
end

可以使用正则表达式,例如查找字符串类型:

case foo
when /^(true|false)$/
   puts "Given string is boolean"
when /^[0-9]+$/ 
   puts "Given string is integer"
when /^[0-9\.]+$/
   puts "Given string is float"
else
   puts "Given string is probably string"
end

Ruby的情况将使用相等操作数==(感谢@JimDeville)。更多信息请访问“Ruby Operators”。这也可以使用@mmdemirbas示例(不带参数)来完成,只有这种方法对于这些类型的情况更干净。

它被称为case,它的工作方式与您预期的一样,加上实现测试的==提供的更多有趣的东西。

case 5
  when 5
    puts 'yes'
  else
    puts 'else'
end

现在来点乐趣吧:

case 5 # every selector below would fire (if first)
  when 3..7    # OK, this is nice
  when 3,4,5,6 # also nice
  when Fixnum  # or
  when Integer # or
  when Numeric # or
  when Comparable # (?!) or
  when Object  # (duhh) or
  when Kernel  # (?!) or
  when BasicObject # (enough already)
    ...
end

事实证明,你也可以用case替换任意的if/else链(也就是说,即使测试不涉及公共变量),方法是省去初始case参数,只编写第一个匹配的表达式。

case
  when x.nil?
    ...
  when (x.match /'^fn'/)
    ...
  when (x.include? 'substring')
    ...
  when x.gsub('o', 'z') == 'fnzrq'
    ...
  when Time.now.tuesday?
    ...
end

多值时和无值情况:

print "Enter your grade: "
grade = gets.chomp
case grade
when "A", "B"
  puts 'You pretty smart!'
when "C", "D"
  puts 'You pretty dumb!!'
else
  puts "You can't even use a computer!"
end

这里有一个正则表达式解决方案:

print "Enter a string: "
some_string = gets.chomp
case
when some_string.match(/\d/)
  puts 'String has numbers'
when some_string.match(/[a-zA-Z]/)
  puts 'String has letters'
else
  puts 'String has no numbers or letters'
end