我有;
List<String> stringList = new ArrayList<String>();
List<Integer> integerList = new ArrayList<Integer>();
是否有(简单)方法检索列表的泛型类型?
我有;
List<String> stringList = new ArrayList<String>();
List<Integer> integerList = new ArrayList<Integer>();
是否有(简单)方法检索列表的泛型类型?
当前回答
import org.junit.Assert;
import org.junit.Test;
import java.lang.reflect.Field;
import java.lang.reflect.ParameterizedType;
import java.util.ArrayList;
import java.util.Collection;
import java.util.List;
public class GenericTypeOfCollectionTest {
public class FormBean {
}
public class MyClazz {
private List<FormBean> list = new ArrayList<FormBean>();
}
@Test
public void testName() throws Exception {
Field[] fields = MyClazz.class.getFields();
for (Field field : fields) {
//1. Check if field is of Collection Type
if (Collection.class.isAssignableFrom(field.getType())) {
//2. Get Generic type of your field
Class fieldGenericType = getFieldGenericType(field);
//3. Compare with <FromBean>
Assert.assertTrue("List<FormBean>",
FormBean.class.isAssignableFrom(fieldGenericType));
}
}
}
//Returns generic type of any field
public Class getFieldGenericType(Field field) {
if (ParameterizedType.class.isAssignableFrom(field.getGenericType().getClass())) {
ParameterizedType genericType =
(ParameterizedType) field.getGenericType();
return ((Class)
(genericType.getActualTypeArguments()[0])).getSuperclass();
}
//Returns dummy Boolean Class to compare with ValueObject & FormBean
return new Boolean(false).getClass();
}
}
其他回答
通常不可能,因为List<String>和List<Integer>共享相同的运行时类。
不过,您可能能够反映包含列表的字段的声明类型(如果声明的类型本身并不引用您不知道其值的类型参数)。
如果这些实际上是某个类的字段,那么你可以通过反射来获得它们:
package test;
import java.lang.reflect.Field;
import java.lang.reflect.ParameterizedType;
import java.util.ArrayList;
import java.util.List;
public class Test {
List<String> stringList = new ArrayList<String>();
List<Integer> integerList = new ArrayList<Integer>();
public static void main(String... args) throws Exception {
Field stringListField = Test.class.getDeclaredField("stringList");
ParameterizedType stringListType = (ParameterizedType) stringListField.getGenericType();
Class<?> stringListClass = (Class<?>) stringListType.getActualTypeArguments()[0];
System.out.println(stringListClass); // class java.lang.String.
Field integerListField = Test.class.getDeclaredField("integerList");
ParameterizedType integerListType = (ParameterizedType) integerListField.getGenericType();
Class<?> integerListClass = (Class<?>) integerListType.getActualTypeArguments()[0];
System.out.println(integerListClass); // class java.lang.Integer.
}
}
对于参数类型和方法的返回类型也可以这样做。
但是如果它们在类/方法的相同范围内,而您需要知道它们,那么就没有必要知道它们,因为您已经自己声明了它们。
你也可以对方法参数做同样的事情:
Method method = someClass.getDeclaredMethod("someMethod");
Type[] types = method.getGenericParameterTypes();
//Now assuming that the first parameter to the method is of type List<Integer>
ParameterizedType pType = (ParameterizedType) types[0];
Class<?> clazz = (Class<?>) pType.getActualTypeArguments()[0];
System.out.println(clazz); //prints out java.lang.Integer
import org.junit.Assert;
import org.junit.Test;
import java.lang.reflect.Field;
import java.lang.reflect.ParameterizedType;
import java.util.ArrayList;
import java.util.Collection;
import java.util.List;
public class GenericTypeOfCollectionTest {
public class FormBean {
}
public class MyClazz {
private List<FormBean> list = new ArrayList<FormBean>();
}
@Test
public void testName() throws Exception {
Field[] fields = MyClazz.class.getFields();
for (Field field : fields) {
//1. Check if field is of Collection Type
if (Collection.class.isAssignableFrom(field.getType())) {
//2. Get Generic type of your field
Class fieldGenericType = getFieldGenericType(field);
//3. Compare with <FromBean>
Assert.assertTrue("List<FormBean>",
FormBean.class.isAssignableFrom(fieldGenericType));
}
}
}
//Returns generic type of any field
public Class getFieldGenericType(Field field) {
if (ParameterizedType.class.isAssignableFrom(field.getGenericType().getClass())) {
ParameterizedType genericType =
(ParameterizedType) field.getGenericType();
return ((Class)
(genericType.getActualTypeArguments()[0])).getSuperclass();
}
//Returns dummy Boolean Class to compare with ValueObject & FormBean
return new Boolean(false).getClass();
}
}
集合的泛型类型应该只在它实际上有对象时才重要,对吗?所以这样做不是更简单吗:
Collection<?> myCollection = getUnknownCollectionFromSomewhere();
Class genericClass = null;
Iterator it = myCollection.iterator();
if (it.hasNext()){
genericClass = it.next().getClass();
}
if (genericClass != null) { //do whatever we needed to know the type for
在运行时没有泛型类型这样的东西,但运行时内部的对象保证与声明的泛型是相同的类型,因此在处理它之前测试项的类非常容易。
您可以做的另一件事是简单地处理列表以获得正确类型的成员,忽略其他成员(或以不同的方式处理它们)。
Map<Class<?>, List<Object>> classObjectMap = myCollection.stream()
.filter(Objects::nonNull)
.collect(Collectors.groupingBy(Object::getClass));
// Process the list of the correct class, and/or handle objects of incorrect
// class (throw exceptions, etc). You may need to group subclasses by
// filtering the keys. For instance:
List<Number> numbers = classObjectMap.entrySet().stream()
.filter(e->Number.class.isAssignableFrom(e.getKey()))
.flatMap(e->e.getValue().stream())
.map(Number.class::cast)
.collect(Collectors.toList());
这将为您提供一个所有项目的列表,这些项目的类都是Number的子类,然后您可以根据需要对其进行处理。其余的项目被过滤到其他列表中。因为它们在地图中,所以您可以根据需要处理它们,或者忽略它们。
如果你想完全忽略其他类的项目,它会变得简单得多:
List<Number> numbers = myCollection.stream()
.filter(Number.class::isInstance)
.map(Number.class::cast)
.collect(Collectors.toList());
你甚至可以创建一个实用工具方法来确保列表只包含那些匹配特定类的项:
public <V> List<V> getTypeSafeItemList(Collection<Object> input, Class<V> cls) {
return input.stream()
.filter(cls::isInstance)
.map(cls::cast)
.collect(Collectors.toList());
}