给定此文档保存在MongoDB中

{
   _id : ...,
   some_key: { 
        param1 : "val1",
        param2 : "val2",
        param3 : "val3"
   }
}

需要保存具有来自外部世界的关于param2和param3的新信息的对象

var new_info = {
    param2 : "val2_new",
    param3 : "val3_new"
};

我想在对象的现有状态上合并/覆盖新字段,这样param1就不会被删除

这样做

db.collection.update(  { _id:...} , { $set: { some_key : new_info  } } 

将导致MongoDB完全按照要求执行,并将some_key设置为该值。更换旧的。

{
   _id : ...,
   some_key: { 
      param2 : "val2_new",
      param3 : "val3_new"
   }
}

如何让MongoDB只更新新字段(而不显式地逐个声明它们)?要得到这个:

{
   _id : ...,
   some_key: { 
        param1 : "val1",
        param2 : "val2_new",
        param3 : "val3_new"
   }
}

我正在使用Java客户端,但是任何示例都将受到欢迎


当前回答

如果你想更新一个对象的多个字段,你可以试试这个:-

 let fieldsToUpdate = {};
 for (const key in allFields) {
 const fieldName = `flags.${key}`;   // define field as string literal
     fieldsToUpdate[fieldName] = allFields[key];
 }
 db.collection.updateOne(query, { $set: { ...fieldsToUpdate } } );

其他回答

您可以在基于聚合的更新中使用$mergeObjects。类似的

db.collection.update(
   { _id:...},
   [{"$set":{
      "some_key":{
        "$mergeObjects":[
          "$some_key",
          new info or { param2 : "val2_new", param3 : "val3_new"}
       ]
      }
   }}]
)

这里有更多的例子

我尝试了findmodify()来更新一个预先存在的对象中的特定字段。

https://docs.mongodb.com/manual/reference/method/db.collection.findAndModify/

从Mongo 4.2开始,db.collection.updateMany()(或db.collection.update())可以接受一个聚合管道,它允许使用聚合操作符,如$addFields,它输出输入文档中所有现有的字段和新添加的字段:

var new_info = { param2: "val2_new", param3: "val3_new" }

// { some_key: { param1: "val1", param2: "val2", param3: "val3" } }
// { some_key: { param1: "val1", param2: "val2"                 } }
db.collection.updateMany({}, [{ $addFields: { some_key: new_info } }])
// { some_key: { param1: "val1", param2: "val2_new", param3: "val3_new" } }
// { some_key: { param1: "val1", param2: "val2_new", param3: "val3_new" } }

The first part {} is the match query, filtering which documents to update (in this case all documents). The second part [{ $addFields: { some_key: new_info } }] is the update aggregation pipeline: Note the squared brackets signifying the use of an aggregation pipeline. Since this is an aggregation pipeline, we can use $addFields. $addFields performs exactly what you need: updating the object so that the new object will overlay / merge with the existing one: In this case, { param2: "val2_new", param3: "val3_new" } will be merged into the existing some_key by keeping param1 untouched and either add or replace both param2 and param3.

看起来你可以设置isPartialObject,这可能完成你想要的。

如果你想更新一个对象的多个字段,你可以试试这个:-

 let fieldsToUpdate = {};
 for (const key in allFields) {
 const fieldName = `flags.${key}`;   // define field as string literal
     fieldsToUpdate[fieldName] = allFields[key];
 }
 db.collection.updateOne(query, { $set: { ...fieldsToUpdate } } );