如何在c++中转换大端值和小端值?
为了清晰起见,我必须将二进制数据(双精度浮点值以及32位和64位整数)从一个CPU架构转换到另一个CPU架构。这并不涉及网络,因此ntoh()和类似的函数在这里不能工作。
注意:我接受的答案直接适用于我的目标编译器(这就是我选择它的原因)。然而,这里还有其他非常好的、更方便的答案。
如何在c++中转换大端值和小端值?
为了清晰起见,我必须将二进制数据(双精度浮点值以及32位和64位整数)从一个CPU架构转换到另一个CPU架构。这并不涉及网络,因此ntoh()和类似的函数在这里不能工作。
注意:我接受的答案直接适用于我的目标编译器(这就是我选择它的原因)。然而,这里还有其他非常好的、更方便的答案。
当前回答
c++20无分支版本,现在std::endian已经存在,但在c++23之前增加了std::byteswap
#include <bit>
#include <type_traits>
#include <concepts>
#include <array>
#include <cstring>
#include <iostream>
#include <bitset>
template <int LEN, int OFF=LEN/2>
class do_swap
{
// FOR 8 bytes:
// LEN=8 (LEN/2==4) <H><G><F><E><D><C><B><A>
// OFF=4: FROM=0, TO=7 => [A]<G><F><E><D><C><B>[H]
// OFF=3: FROM=1, TO=6 => [A][B]<F><E><D><C>[G][H]
// OFF=2: FROM=2, TO=5 => [A][B][C]<E><D>[F][G][H]
// OFF=1: FROM=3, TO=4 => [A][B][C][D][E][F][G][H]
// OFF=0: FROM=4, TO=3 => DONE
public:
enum consts {FROM=LEN/2-OFF, TO=(LEN-1)-FROM};
using NXT=do_swap<LEN, OFF-1>;
// flip the first and last for the current iteration's range
static void flip(std::array<std::byte, LEN>& b)
{
std::byte tmp=b[FROM];
b[FROM]=b[TO];
b[TO]=tmp;
NXT::flip(b);
}
};
template <int LEN>
class do_swap<LEN, 0> // STOP the template recursion
{
public:
static void flip(std::array<std::byte, LEN>&)
{
}
};
template<std::integral T, std::endian TO, std::endian FROM=std::endian::native>
requires ((TO==std::endian::big) || (TO==std::endian::little))
&& ((FROM==std::endian::big) || (FROM==std::endian::little))
class endian_swap
{
public:
enum consts {BYTE_COUNT=sizeof(T)};
static T cvt(const T integral)
{
// if FROM and TO are the same -- nothing to do
if (TO==FROM)
{
return integral;
}
// endian::big --> endian::little is the same as endian::little --> endian::big
// the bytes have to be reversed
// memcpy seems to be the most supported way to do byte swaps in a defined way
std::array<std::byte, BYTE_COUNT> bytes;
std::memcpy(&bytes, &integral, BYTE_COUNT);
do_swap<BYTE_COUNT>::flip(bytes);
T ret;
std::memcpy(&ret, &bytes, BYTE_COUNT);
return ret;
}
};
std::endian big()
{
return std::endian::big;
}
std::endian little()
{
return std::endian::little;
}
std::endian native()
{
return std::endian::native;
}
long long swap_to_big(long long x)
{
return endian_swap<long long, std::endian::big>::cvt(x);
}
long long swap_to_little(long long x)
{
return endian_swap<long long, std::endian::little>::cvt(x);
}
void show(std::string label, long long x)
{
std::cout << label << "\t: " << std::bitset<64>(x) << " (" << x << ")" << std::endl;
}
int main(int argv, char ** argc)
{
long long init=0xF8FCFEFF7F3F1F0;
long long to_big=swap_to_big(init);
long long to_little=swap_to_little(init);
show("Init", init);
show(">big", to_big);
show(">little", to_little);
}
其他回答
我从这篇文章中得到了一些建议,并把它们放在一起形成了这个:
#include <boost/type_traits.hpp>
#include <boost/static_assert.hpp>
#include <boost/detail/endian.hpp>
#include <stdexcept>
#include <cstdint>
enum endianness
{
little_endian,
big_endian,
network_endian = big_endian,
#if defined(BOOST_LITTLE_ENDIAN)
host_endian = little_endian
#elif defined(BOOST_BIG_ENDIAN)
host_endian = big_endian
#else
#error "unable to determine system endianness"
#endif
};
namespace detail {
template<typename T, size_t sz>
struct swap_bytes
{
inline T operator()(T val)
{
throw std::out_of_range("data size");
}
};
template<typename T>
struct swap_bytes<T, 1>
{
inline T operator()(T val)
{
return val;
}
};
template<typename T>
struct swap_bytes<T, 2>
{
inline T operator()(T val)
{
return ((((val) >> 8) & 0xff) | (((val) & 0xff) << 8));
}
};
template<typename T>
struct swap_bytes<T, 4>
{
inline T operator()(T val)
{
return ((((val) & 0xff000000) >> 24) |
(((val) & 0x00ff0000) >> 8) |
(((val) & 0x0000ff00) << 8) |
(((val) & 0x000000ff) << 24));
}
};
template<>
struct swap_bytes<float, 4>
{
inline float operator()(float val)
{
uint32_t mem =swap_bytes<uint32_t, sizeof(uint32_t)>()(*(uint32_t*)&val);
return *(float*)&mem;
}
};
template<typename T>
struct swap_bytes<T, 8>
{
inline T operator()(T val)
{
return ((((val) & 0xff00000000000000ull) >> 56) |
(((val) & 0x00ff000000000000ull) >> 40) |
(((val) & 0x0000ff0000000000ull) >> 24) |
(((val) & 0x000000ff00000000ull) >> 8 ) |
(((val) & 0x00000000ff000000ull) << 8 ) |
(((val) & 0x0000000000ff0000ull) << 24) |
(((val) & 0x000000000000ff00ull) << 40) |
(((val) & 0x00000000000000ffull) << 56));
}
};
template<>
struct swap_bytes<double, 8>
{
inline double operator()(double val)
{
uint64_t mem =swap_bytes<uint64_t, sizeof(uint64_t)>()(*(uint64_t*)&val);
return *(double*)&mem;
}
};
template<endianness from, endianness to, class T>
struct do_byte_swap
{
inline T operator()(T value)
{
return swap_bytes<T, sizeof(T)>()(value);
}
};
// specialisations when attempting to swap to the same endianess
template<class T> struct do_byte_swap<little_endian, little_endian, T> { inline T operator()(T value) { return value; } };
template<class T> struct do_byte_swap<big_endian, big_endian, T> { inline T operator()(T value) { return value; } };
} // namespace detail
template<endianness from, endianness to, class T>
inline T byte_swap(T value)
{
// ensure the data is only 1, 2, 4 or 8 bytes
BOOST_STATIC_ASSERT(sizeof(T) == 1 || sizeof(T) == 2 || sizeof(T) == 4 || sizeof(T) == 8);
// ensure we're only swapping arithmetic types
BOOST_STATIC_ASSERT(boost::is_arithmetic<T>::value);
return detail::do_byte_swap<from, to, T>()(value);
}
然后你可以这样使用它:
// swaps val from host-byte-order to network-byte-order
auto swapped = byte_swap<host_endian, network_endian>(val);
反之亦然
// swap a value received from the network into host-byte-order
auto val = byte_swap<network_endian, host_endian>(val_from_network);
我有这个代码,允许我从HOST_ENDIAN_ORDER(无论它是什么)转换为LITTLE_ENDIAN_ORDER或BIG_ENDIAN_ORDER。我使用一个模板,所以如果我试图从HOST_ENDIAN_ORDER转换为LITTLE_ENDIAN_ORDER,他们恰好是相同的机器为我编译,不会生成任何代码。
下面是带有注释的代码:
// We define some constant for little, big and host endianess. Here I use
// BOOST_LITTLE_ENDIAN/BOOST_BIG_ENDIAN to check the host indianess. If you
// don't want to use boost you will have to modify this part a bit.
enum EEndian
{
LITTLE_ENDIAN_ORDER,
BIG_ENDIAN_ORDER,
#if defined(BOOST_LITTLE_ENDIAN)
HOST_ENDIAN_ORDER = LITTLE_ENDIAN_ORDER
#elif defined(BOOST_BIG_ENDIAN)
HOST_ENDIAN_ORDER = BIG_ENDIAN_ORDER
#else
#error "Impossible de determiner l'indianness du systeme cible."
#endif
};
// this function swap the bytes of values given it's size as a template
// parameter (could sizeof be used?).
template <class T, unsigned int size>
inline T SwapBytes(T value)
{
union
{
T value;
char bytes[size];
} in, out;
in.value = value;
for (unsigned int i = 0; i < size / 2; ++i)
{
out.bytes[i] = in.bytes[size - 1 - i];
out.bytes[size - 1 - i] = in.bytes[i];
}
return out.value;
}
// Here is the function you will use. Again there is two compile-time assertion
// that use the boost librarie. You could probably comment them out, but if you
// do be cautious not to use this function for anything else than integers
// types. This function need to be calles like this :
//
// int x = someValue;
// int i = EndianSwapBytes<HOST_ENDIAN_ORDER, BIG_ENDIAN_ORDER>(x);
//
template<EEndian from, EEndian to, class T>
inline T EndianSwapBytes(T value)
{
// A : La donnée à swapper à une taille de 2, 4 ou 8 octets
BOOST_STATIC_ASSERT(sizeof(T) == 2 || sizeof(T) == 4 || sizeof(T) == 8);
// A : La donnée à swapper est d'un type arithmetic
BOOST_STATIC_ASSERT(boost::is_arithmetic<T>::value);
// Si from et to sont du même type on ne swap pas.
if (from == to)
return value;
return SwapBytes<T, sizeof(T)>(value);
}
请注意,至少对于Windows, htonl()比它们的内在对应_byteswap_ulong()慢得多。前者是对ws2_32.dll的一个DLL库调用,后者是一条BSWAP汇编指令。因此,如果你正在编写一些依赖于平台的代码,为了提高速度,最好使用intrinsic:
#define htonl(x) _byteswap_ulong(x)
这对于。png图像处理尤其重要,其中所有整数都保存在大端格式中,并说明“One can use htonl()…”{用来降低典型Windows程序的速度,如果你没有准备好}。
在大多数POSIX系统中(虽然不是在POSIX标准中)有end .h,它可以用来确定系统使用的编码。然后是这样的:
unsigned int change_endian(unsigned int x)
{
unsigned char *ptr = (unsigned char *)&x;
return (ptr[0] << 24) | (ptr[1] << 16) | (ptr[2] << 8) | ptr[3];
}
这将交换顺序(从大端序到小端序):
如果你有数字0xDEADBEEF(在一个小端序系统中存储为0xEFBEADDE), ptr[0]将是0xEF, ptr[1]是0xBE,等等。
但是如果你想将它用于网络,那么htons, htonl和htonll(以及它们的逆ntohs, ntohl和ntohll)将有助于从主机顺序转换到网络顺序。
这是我想到的一个通用版本,用于在适当的位置交换值。如果性能存在问题,其他建议会更好。
template<typename T>
void ByteSwap(T * p)
{
for (int i = 0; i < sizeof(T)/2; ++i)
std::swap(((char *)p)[i], ((char *)p)[sizeof(T)-1-i]);
}
免责声明:我还没有尝试编译或测试它。