有没有更好的方法来使用glob。Glob在python中获取多个文件类型的列表，如.txt， .mdown和.markdown?现在我有这样的东西:
projectFiles1 = glob.glob( os.path.join(projectDir, '*.txt') )
projectFiles2 = glob.glob( os.path.join(projectDir, '*.mdown') )
projectFiles3 = glob.glob( os.path.join(projectDir, '*.markdown') )
当前回答
链接结果:
import itertools as it, glob
def multiple_file_types(*patterns):
return it.chain.from_iterable(glob.iglob(pattern) for pattern in patterns)
然后:
for filename in multiple_file_types("*.txt", "*.sql", "*.log"):
# do stuff
其他回答
链接结果:
import itertools as it, glob
def multiple_file_types(*patterns):
return it.chain.from_iterable(glob.iglob(pattern) for pattern in patterns)
然后:
for filename in multiple_file_types("*.txt", "*.sql", "*.log"):
# do stuff
从前面的答案
glob('*.jpg') + glob('*.png')
这是一个较短的问题，
from glob import glob
extensions = ['jpg', 'png'] # to find these filename extensions
# Method 1: loop one by one and extend to the output list
output = []
[output.extend(glob(f'*.{name}')) for name in extensions]
print(output)
# Method 2: even shorter
# loop filename extension to glob() it and flatten it to a list
output = [p for p2 in [glob(f'*.{name}') for name in extensions] for p in p2]
print(output)
如果你使用pathlib，试试这个:
import pathlib
extensions = ['.py', '.txt']
root_dir = './test/'
files = filter(lambda p: p.suffix in extensions, pathlib.Path(root_dir).glob('**/*'))
print(list(files))
最简单的方法是使用itertools.chain
from pathlib import Path
import itertools
cwd = Path.cwd()
for file in itertools.chain(
cwd.rglob("*.txt"),
cwd.rglob("*.md"),
):
print(file.name)
import os
import glob
import operator
from functools import reduce
types = ('*.jpg', '*.png', '*.jpeg')
lazy_paths = (glob.glob(os.path.join('my_path', t)) for t in types)
paths = reduce(operator.add, lazy_paths, [])
https://docs.python.org/3.5/library/functools.html#functools.reduce https://docs.python.org/3.5/library/operator.html#operator.add
