有没有更好的方法来使用glob。Glob在python中获取多个文件类型的列表,如.txt, .mdown和.markdown?现在我有这样的东西:
projectFiles1 = glob.glob( os.path.join(projectDir, '*.txt') )
projectFiles2 = glob.glob( os.path.join(projectDir, '*.mdown') )
projectFiles3 = glob.glob( os.path.join(projectDir, '*.markdown') )
我也有同样的问题,这是我想到的
import os, sys, re
#without glob
src_dir = '/mnt/mypics/'
src_pics = []
ext = re.compile('.*\.(|{}|)$'.format('|'.join(['png', 'jpeg', 'jpg']).encode('utf-8')))
for root, dirnames, filenames in os.walk(src_dir):
for filename in filter(lambda name:ext.search(name),filenames):
src_pics.append(os.path.join(root, filename))
下面的函数_glob用于多个文件扩展名。
import glob
import os
def _glob(path, *exts):
"""Glob for multiple file extensions
Parameters
----------
path : str
A file name without extension, or directory name
exts : tuple
File extensions to glob for
Returns
-------
files : list
list of files matching extensions in exts in path
"""
path = os.path.join(path, "*") if os.path.isdir(path) else path + "*"
return [f for files in [glob.glob(path + ext) for ext in exts] for f in files]
files = _glob(projectDir, ".txt", ".mdown", ".markdown")
from glob import glob
files = glob('*.gif')
files.extend(glob('*.png'))
files.extend(glob('*.jpg'))
print(files)
如果你需要指定一个路径,循环匹配模式,并保持连接在循环中简单:
from os.path import join
from glob import glob
files = []
for ext in ('*.gif', '*.png', '*.jpg'):
files.extend(glob(join("path/to/dir", ext)))
print(files)
来这里寻求帮助后,我有了自己的解决方案,想和大家分享。它基于user2363986的答案,但我认为这更具可伸缩性。这意味着,即使您有1000个扩展,代码仍然看起来很优雅。
from glob import glob
directoryPath = "C:\\temp\\*."
fileExtensions = [ "jpg", "jpeg", "png", "bmp", "gif" ]
listOfFiles = []
for extension in fileExtensions:
listOfFiles.extend( glob( directoryPath + extension ))
for file in listOfFiles:
print(file) # Or do other stuff