你可以用这个:

project_files = []
file_extensions = ['txt','mdown','markdown']
for file_extension in file_extensions:
    project_files.extend(glob.glob(projectDir  + '*.' + file_extension))

import os
import glob

projectFiles = [i for i in glob.glob(os.path.join(projectDir,"*")) if os.path.splitext(i)[-1].lower() in ['.txt','.markdown','.mdown']]

Os.path.splitext将返回filename & .extension

filename, .extension = os.path.splitext('filename.extension')

.lower()将字符串转换为小写

这么多的答案都建议全局替换和扩展的数量一样多，我更喜欢只替换一次:

from pathlib import Path

files = (p.resolve() for p in Path(path).glob("**/*") if p.suffix in {".c", ".cc", ".cpp", ".hxx", ".h"})

import os    
import glob
import operator
from functools import reduce

types = ('*.jpg', '*.png', '*.jpeg')
lazy_paths = (glob.glob(os.path.join('my_path', t)) for t in types)
paths = reduce(operator.add, lazy_paths, [])

https://docs.python.org/3.5/library/functools.html#functools.reduce https://docs.python.org/3.5/library/operator.html#operator.add

例如，*.mp3和*.mp3。Flac在多个文件夹上，你可以做:

mask = r'music/*/*.[mf][pl][3a]*'
glob.glob(mask)

这个想法可以扩展到更多的文件扩展名，但您必须检查这些组合是否与这些文件夹上可能存在的任何其他不需要的文件扩展名匹配。所以要小心。

要自动将任意扩展列表组合到一个glob模式中，您可以执行以下操作:

def multi_extension_glob_mask(mask_base, *extensions):
    mask_ext = ['[{}]'.format(''.join(set(c))) for c in zip(*extensions)]
    if not mask_ext or len(set(len(e) for e in extensions)) > 1:
        mask_ext.append('*')
    return mask_base + ''.join(mask_ext)

mask = multi_extension_glob_mask('music/*/*.', 'mp3', 'flac', 'wma')
print(mask)  # music/*/*.[mfw][pml][a3]*

也许有更好的办法，但是:

import glob
types = ('*.pdf', '*.cpp') # the tuple of file types
files_grabbed = []
for files in types:
    files_grabbed.extend(glob.glob(files))

# files_grabbed is the list of pdf and cpp files

也许还有其他的方法，所以等待别人提出更好的答案。