这应该有用:

import glob
extensions = ('*.txt', '*.mdown', '*.markdown')
for i in extensions:
    for files in glob.glob(i):
        print (files)

下面的函数_glob用于多个文件扩展名。

import glob
import os
def _glob(path, *exts):
    """Glob for multiple file extensions

    Parameters
    ----------
    path : str
        A file name without extension, or directory name
    exts : tuple
        File extensions to glob for

    Returns
    -------
    files : list
        list of files matching extensions in exts in path

    """
    path = os.path.join(path, "*") if os.path.isdir(path) else path + "*"
    return [f for files in [glob.glob(path + ext) for ext in exts] for f in files]

files = _glob(projectDir, ".txt", ".mdown", ".markdown")

也许我遗漏了一些东西但如果只是简单的glob也许你可以这样做?

projectFiles = glob.glob(os.path.join(projectDir, '*.{txt,mdown,markdown}'))

您可以尝试制作一个手动列表，将现有扩展与所需扩展进行比较。

ext_list = ['gif','jpg','jpeg','png'];
file_list = []
for file in glob.glob('*.*'):
  if file.rsplit('.',1)[1] in ext_list :
    file_list.append(file)

不是glob，这里是另一种使用列表理解的方式:

extensions = 'txt mdown markdown'.split()
projectFiles = [f for f in os.listdir(projectDir) 
                  if os.path.splitext(f)[1][1:] in extensions]

from glob import glob

files = glob('*.gif')
files.extend(glob('*.png'))
files.extend(glob('*.jpg'))

print(files)

如果你需要指定一个路径，循环匹配模式，并保持连接在循环中简单:

from os.path import join
from glob import glob

files = []
for ext in ('*.gif', '*.png', '*.jpg'):
   files.extend(glob(join("path/to/dir", ext)))

print(files)