最简单的方法是包含gem 'activesupport'(或gem 'active_support')。

参数个数。切片(:choice1，:choice2，:choice3)

与散列::选择:

params = params.select { |key, value| /^choice\d+$/.match(key.to_s) }

params = { :irrelevant => "A String",
           :choice1 => "Oh look, another one",
           :choice2 => "Even more strings",
           :choice3 => "But wait",
           :irrelevant2 => "The last string" }

choices = params.select { |key, value| key.to_s[/^choice\d+/] }
#=> {:choice1=>"Oh look, another one", :choice2=>"Even more strings", :choice3=>"But wait"}

关于奖金问题:

If you have output from #select method like this (list of 2-element arrays): [[:choice1, "Oh look, another one"], [:choice2, "Even more strings"], [:choice3, "But wait"]] then simply take this result and execute: filtered_params.join("\t") # or if you want only values instead of pairs key-value filtered_params.map(&:last).join("\t") If you have output from #delete_if method like this (hash): {:choice1=>"Oh look, another one", :choice2=>"Even more strings", :choice3=>"But wait"} then: filtered_params.to_a.join("\t") # or filtered_params.values.join("\t")

在Ruby中，hash# select是一个正确的选项。如果你使用Rails，你可以使用Hash#slice和Hash#slice!例:(rails 3.2.13)

h1 = {:a => 1, :b => 2, :c => 3, :d => 4}

h1.slice(:a, :b)         # return {:a=>1, :b=>2}, but h1 is not changed

h2 = h1.slice!(:a, :b)   # h1 = {:a=>1, :b=>2}, h2 = {:c => 3, :d => 4}

如果你使用rails并且你在一个单独的列表中有键，你可以使用*符号:

keys = [:foo, :bar]
hash1 = {foo: 1, bar:2, baz: 3}
hash2 = hash1.slice(*keys)
=> {foo: 1, bar:2}

正如其他答案所述，你也可以使用slice!修改哈希(并返回擦除的键/值)。