在我的应用程序的某些时候,我有一个突出显示的UIButton(例如当用户有他的手指在按钮上),我需要改变背景颜色,而按钮是突出显示的(所以当用户的手指仍然在按钮上)。

我尝试了以下方法:

_button.backgroundColor = [UIColor redColor];

但这并不奏效。颜色保持不变。当按钮没有高亮显示时,我尝试了同一段代码,它工作得很好。我还尝试在改变颜色后调用-setNeedsDisplay,它没有任何效果。

如何强制按钮改变背景颜色?


当前回答

class CustomButton: UIButton {

    override var isHighlighted: Bool {
        didSet {
            if (isHighlighted) {
                alpha = 0.5
            }
            else {
                alpha = 1
            }            
        }
    }

}

其他回答

Swift中一个方便的通用扩展:

extension UIButton {
    private func imageWithColor(color: UIColor) -> UIImage {
        let rect = CGRectMake(0.0, 0.0, 1.0, 1.0)
        UIGraphicsBeginImageContext(rect.size)
        let context = UIGraphicsGetCurrentContext()

        CGContextSetFillColorWithColor(context, color.CGColor)
        CGContextFillRect(context, rect)

        let image = UIGraphicsGetImageFromCurrentImageContext()
        UIGraphicsEndImageContext()

        return image
    }

    func setBackgroundColor(color: UIColor, forUIControlState state: UIControlState) {
        self.setBackgroundImage(imageWithColor(color), forState: state)
    }
}

斯威夫特3.0

extension UIButton {
    private func imageWithColor(color: UIColor) -> UIImage? {
        let rect = CGRect(x: 0.0, y: 0.0, width: 1.0, height: 1.0)
        UIGraphicsBeginImageContext(rect.size)
        let context = UIGraphicsGetCurrentContext()

        context?.setFillColor(color.cgColor)
        context?.fill(rect)

        let image = UIGraphicsGetImageFromCurrentImageContext()
        UIGraphicsEndImageContext()

        return image
    }

    func setBackgroundColor(_ color: UIColor, for state: UIControlState) {
        self.setBackgroundImage(imageWithColor(color: color), for: state)
    }
}

在Swift中,你可以重写高亮显示(或选中)属性的访问器,而不是重写setHighlighted方法

override var highlighted: Bool {
        get {
            return super.highlighted
        }
        set {
            if newValue {
                backgroundColor = UIColor.blackColor()
            }
            else {
                backgroundColor = UIColor.whiteColor()
            }
            super.highlighted = newValue
        }
    }

试试这个!!!!

TouchedDown事件设置一种颜色,TouchUpInside设置另一种颜色。

- (IBAction)touchedDown:(id)sender {
    NSLog(@"Touched Down");
    btn1.backgroundColor=[UIColor redColor];
}

- (IBAction)touchUpInside:(id)sender {
    NSLog(@"TouchUpInside");
    btn1.backgroundColor=[UIColor whiteColor];    
}

试试tintColor:

_button.tintColor = [UIColor redColor];

不确定这是否解决了你所追求的问题,或者是否符合你的总体开发环境,但我想尝试的第一件事是改变触地事件按钮的背景颜色。

选项1:

你需要捕捉两个事件,当用户按下按钮时UIControlEventTouchDown。UIControlEventTouchUpInside和UIControlEventTouchUpOutside将用于当它们释放按钮以返回正常状态时

UIButton *myButton =  [UIButton buttonWithType:UIButtonTypeCustom];
[myButton setFrame:CGRectMake(10.0f, 10.0f, 100.0f, 20.f)];
[myButton setBackgroundColor:[UIColor blueColor]];
[myButton setTitle:@"click me:" forState:UIControlStateNormal];
[myButton setTitle:@"changed" forState:UIControlStateHighlighted];
[myButton addTarget:self action:@selector(buttonHighlight:) forControlEvents:UIControlEventTouchDown];
[myButton addTarget:self action:@selector(buttonNormal:) forControlEvents:UIControlEventTouchUpInside];

选项2:

返回你想要的高亮颜色的图像。这也可以是一个类别。

+ (UIImage *)imageWithColor:(UIColor *)color {
   CGRect rect = CGRectMake(0.0f, 0.0f, 1.0f, 1.0f);
   UIGraphicsBeginImageContext(rect.size);
   CGContextRef context = UIGraphicsGetCurrentContext();

   CGContextSetFillColorWithColor(context, [color CGColor]);
   CGContextFillRect(context, rect);

   UIImage *image = UIGraphicsGetImageFromCurrentImageContext();
   UIGraphicsEndImageContext();

   return image;
}

然后更改按钮的高亮显示状态:

[myButton setBackgroundImage:[self imageWithColor:[UIColor greenColor]] forState:UIControlStateHighlighted];