我有一个Person对象列表。我想转换为Dictionary，其中键是第一个和最后一个名字(连接)，值是Person对象。
问题是我有一些重复的人，所以这爆炸如果我使用以下代码:
private Dictionary<string, Person> _people = new Dictionary<string, Person>();
_people = personList.ToDictionary(
e => e.FirstandLastName,
StringComparer.OrdinalIgnoreCase);
我知道这听起来很奇怪，但我现在真的不关心重复的名字。如果有多个名字，我只想取一个。有没有什么方法可以让上面的代码只取其中一个名字而不会重复?
当前回答
要处理消除重复，实现一个IEqualityComparer<Person>，可以在Distinct()方法中使用，然后获取字典就很容易了。 考虑到:
class PersonComparer : IEqualityComparer<Person>
{
public bool Equals(Person x, Person y)
{
return x.FirstAndLastName.Equals(y.FirstAndLastName, StringComparison.OrdinalIgnoreCase);
}
public int GetHashCode(Person obj)
{
return obj.FirstAndLastName.ToUpper().GetHashCode();
}
}
class Person
{
public string FirstAndLastName { get; set; }
}
拿出你的字典:
List<Person> people = new List<Person>()
{
new Person() { FirstAndLastName = "Bob Sanders" },
new Person() { FirstAndLastName = "Bob Sanders" },
new Person() { FirstAndLastName = "Jane Thomas" }
};
Dictionary<string, Person> dictionary =
people.Distinct(new PersonComparer()).ToDictionary(p => p.FirstAndLastName, p => p);
其他回答
LINQ的解决方案:
// Use the first value in group
var _people = personList
.GroupBy(p => p.FirstandLastName, StringComparer.OrdinalIgnoreCase)
.ToDictionary(g => g.Key, g => g.First(), StringComparer.OrdinalIgnoreCase);
// Use the last value in group
var _people = personList
.GroupBy(p => p.FirstandLastName, StringComparer.OrdinalIgnoreCase)
.ToDictionary(g => g.Key, g => g.Last(), StringComparer.OrdinalIgnoreCase);
如果你更喜欢非linq解决方案，那么你可以这样做:
// Use the first value in list
var _people = new Dictionary<string, Person>(StringComparer.OrdinalIgnoreCase);
foreach (var p in personList)
{
if (!_people.ContainsKey(p.FirstandLastName))
_people[p.FirstandLastName] = p;
}
// Use the last value in list
var _people = new Dictionary<string, Person>(StringComparer.OrdinalIgnoreCase);
foreach (var p in personList)
{
_people[p.FirstandLastName] = p;
}
下面是一个明显的非linq解决方案:
foreach(var person in personList)
{
if(!myDictionary.ContainsKey(person.FirstAndLastName))
myDictionary.Add(person.FirstAndLastName, person);
}
如果你不介意总是添加最后一个，你可以避免这样的双重查找:
foreach(var person in personList)
{
myDictionary[person.FirstAndLastName] = person;
}
要处理消除重复，实现一个IEqualityComparer<Person>，可以在Distinct()方法中使用，然后获取字典就很容易了。 考虑到:
class PersonComparer : IEqualityComparer<Person>
{
public bool Equals(Person x, Person y)
{
return x.FirstAndLastName.Equals(y.FirstAndLastName, StringComparison.OrdinalIgnoreCase);
}
public int GetHashCode(Person obj)
{
return obj.FirstAndLastName.ToUpper().GetHashCode();
}
}
class Person
{
public string FirstAndLastName { get; set; }
}
拿出你的字典:
List<Person> people = new List<Person>()
{
new Person() { FirstAndLastName = "Bob Sanders" },
new Person() { FirstAndLastName = "Bob Sanders" },
new Person() { FirstAndLastName = "Jane Thomas" }
};
Dictionary<string, Person> dictionary =
people.Distinct(new PersonComparer()).ToDictionary(p => p.FirstAndLastName, p => p);
大多数其他答案的问题是，他们使用Distinct, GroupBy或ToLookup，这在底层创建了一个额外的字典。同样ToUpper创建额外的字符串。 这就是我所做的，除了一处更改外，几乎完全复制了微软的代码:
public static Dictionary<TKey, TSource> ToDictionaryIgnoreDup<TSource, TKey>
(this IEnumerable<TSource> source, Func<TSource, TKey> keySelector, IEqualityComparer<TKey> comparer = null) =>
source.ToDictionaryIgnoreDup(keySelector, i => i, comparer);
public static Dictionary<TKey, TElement> ToDictionaryIgnoreDup<TSource, TKey, TElement>
(this IEnumerable<TSource> source, Func<TSource, TKey> keySelector, Func<TSource, TElement> elementSelector, IEqualityComparer<TKey> comparer = null)
{
if (keySelector == null)
throw new ArgumentNullException(nameof(keySelector));
if (elementSelector == null)
throw new ArgumentNullException(nameof(elementSelector));
var d = new Dictionary<TKey, TElement>(comparer ?? EqualityComparer<TKey>.Default);
foreach (var element in source)
d[keySelector(element)] = elementSelector(element);
return d;
}
因为索引器上的set会导致它添加键，所以它不会抛出，也只会进行一次键查找。你也可以给它一个IEqualityComparer，例如StringComparer。OrdinalIgnoreCase
使用LINQ等效的foldLeft功能
persons.Aggregate(new Dictionary<string,Person>(StringComparer.OrdinalIgnoreCase),
(acc, current) => {
acc[current.FirstAndLastName] = current;
return acc;
});
