如何在c# LINQ中执行左外连接到对象而不使用join-on-equal -into子句?有办法用where子句来实现吗? 正确的问题: 内连接很简单,我有一个这样的解决方案

List<JoinPair> innerFinal = (from l in lefts from r in rights where l.Key == r.Key
                             select new JoinPair { LeftId = l.Id, RightId = r.Id})

但是对于左外连接,我需要一个解决方案。我的是这样的,但它不工作

List< JoinPair> leftFinal = (from l in lefts from r in rights
                             select new JoinPair { 
                                            LeftId = l.Id, 
                                            RightId = ((l.Key==r.Key) ? r.Id : 0
                                        })

其中JoinPair是一个类:

public class JoinPair { long leftId; long rightId; }

当前回答

这是一般形式(已经在其他答案中提供了)

var c =
    from a in alpha
    join b in beta on b.field1 equals a.field1 into b_temp
    from b_value in b_temp.DefaultIfEmpty()
    select new { Alpha = a, Beta = b_value };

然而,这里有一个解释,我希望能澄清这实际上是什么意思!

join b in beta on b.field1 equals a.field1 into b_temp

本质上创建了一个单独的结果集b_temp,其中有效地包含了右边条目的空“rows”('b'中的条目)。

然后是下一行:

from b_value in b_temp.DefaultIfEmpty()

..遍历该结果集,为右侧的'row'设置默认空值,并将右侧的行连接的结果设置为'b_value'的值(即,如果有匹配的记录,则为右侧的值,如果没有则为'null')。

现在,如果右边是一个单独的LINQ查询的结果,它将由匿名类型组成,它只能是'something'或'null'。如果它是一个可枚举的对象(例如,一个List -其中MyObjectB是一个有2个字段的类),那么它可以具体说明它的属性使用什么默认的“null”值:

var c =
    from a in alpha
    join b in beta on b.field1 equals a.field1 into b_temp
    from b_value in b_temp.DefaultIfEmpty( new MyObjectB { Field1 = String.Empty, Field2 = (DateTime?) null })
    select new { Alpha = a, Beta_field1 = b_value.Field1, Beta_field2 = b_value.Field2 };

这确保了'b'本身不是空的(但它的属性可以是空的,使用您指定的默认空值),这允许您检查b_value的属性,而不会得到b_value的空引用异常。注意,对于可空的DateTime, (DateTime?)类型,即。'nullable DateTime'必须在'DefaultIfEmpty'的规范中指定为null的'Type'(这也适用于'原生'不为空的类型,例如double, float)。

您可以通过简单地链接上述语法来执行多个左外连接。

其他回答

下面是一个例子,如果你需要连接2个以上的表:

from d in context.dc_tpatient_bookingd
join bookingm in context.dc_tpatient_bookingm 
     on d.bookingid equals bookingm.bookingid into bookingmGroup
from m in bookingmGroup.DefaultIfEmpty()
join patient in dc_tpatient
     on m.prid equals patient.prid into patientGroup
from p in patientGroup.DefaultIfEmpty()

裁判:https://stackoverflow.com/a/17142392/2343

如“Perform left outer joins”中所述:

var q =
    from c in categories
    join pt in products on c.Category equals pt.Category into ps_jointable
    from p in ps_jointable.DefaultIfEmpty()
    select new { Category = c, ProductName = p == null ? "(No products)" : p.ProductName };

现在作为一个扩展方法:

public static class LinqExt
{
    public static IEnumerable<TResult> LeftOuterJoin<TLeft, TRight, TKey, TResult>(this IEnumerable<TLeft> left, IEnumerable<TRight> right, Func<TLeft, TKey> leftKey, Func<TRight, TKey> rightKey,
        Func<TLeft, TRight, TResult> result)
    {
        return left.GroupJoin(right, leftKey, rightKey, (l, r) => new { l, r })
             .SelectMany(
                 o => o.r.DefaultIfEmpty(),
                 (l, r) => new { lft= l.l, rght = r })
             .Select(o => result.Invoke(o.lft, o.rght));
    }
}

像平常使用join一样使用:

var contents = list.LeftOuterJoin(list2, 
             l => l.country, 
             r => r.name,
            (l, r) => new { count = l.Count(), l.country, l.reason, r.people })

希望这能为您节省一些时间。

下面是一个版本的扩展方法解决方案,使用IQueryable代替IEnumerable

public class OuterJoinResult<TLeft, TRight>
{
    public TLeft LeftValue { get; set; }
    public TRight RightValue { get; set; }
}

public static IQueryable<TResult> LeftOuterJoin<TLeft, TRight, TKey, TResult>(this IQueryable<TLeft> left, IQueryable<TRight> right, Expression<Func<TLeft, TKey>> leftKey, Expression<Func<TRight, TKey>> rightKey, Expression<Func<OuterJoinResult<TLeft, TRight>, TResult>> result)
{
    return left.GroupJoin(right, leftKey, rightKey, (l, r) => new { l, r })
          .SelectMany(o => o.r.DefaultIfEmpty(), (l, r) => new OuterJoinResult<TLeft, TRight> { LeftValue = l.l, RightValue = r })
          .Select(result);
}

有三个表:persons, schools和persons_schools,它将人与他们所学习的学校联系起来。表persons_schools中没有对id=6的person的引用。但是id=6的人显示在左连接的结果网格中。

List<Person> persons = new List<Person>
{
    new Person { id = 1, name = "Alex", phone = "4235234" },
    new Person { id = 2, name = "Bob", phone = "0014352" },
    new Person { id = 3, name = "Sam", phone = "1345" },
    new Person { id = 4, name = "Den", phone = "3453452" },
    new Person { id = 5, name = "Alen", phone = "0353012" },
    new Person { id = 6, name = "Simon", phone = "0353012" }
};

List<School> schools = new List<School>
{
    new School { id = 1, name = "Saint. John's school"},
    new School { id = 2, name = "Public School 200"},
    new School { id = 3, name = "Public School 203"}
};

List<PersonSchool> persons_schools = new List<PersonSchool>
{
    new PersonSchool{id_person = 1, id_school = 1},
    new PersonSchool{id_person = 2, id_school = 2},
    new PersonSchool{id_person = 3, id_school = 3},
    new PersonSchool{id_person = 4, id_school = 1},
    new PersonSchool{id_person = 5, id_school = 2}
    //a relation to the person with id=6 is absent
};

var query = from person in persons
            join person_school in persons_schools on person.id equals person_school.id_person
            into persons_schools_joined
            from person_school_joined in persons_schools_joined.DefaultIfEmpty()
            from school in schools.Where(var_school => person_school_joined == null ? false : var_school.id == person_school_joined.id_school).DefaultIfEmpty()
            select new { Person = person.name, School = school == null ? String.Empty : school.name };

foreach (var elem in query)
{
    System.Console.WriteLine("{0},{1}", elem.Person, elem.School);
}