如何在c# LINQ中执行左外连接到对象而不使用join-on-equal -into子句?有办法用where子句来实现吗?
正确的问题:
内连接很简单,我有一个这样的解决方案
List<JoinPair> innerFinal = (from l in lefts from r in rights where l.Key == r.Key
select new JoinPair { LeftId = l.Id, RightId = r.Id})
但是对于左外连接,我需要一个解决方案。我的是这样的,但它不工作
List< JoinPair> leftFinal = (from l in lefts from r in rights
select new JoinPair {
LeftId = l.Id,
RightId = ((l.Key==r.Key) ? r.Id : 0
})
其中JoinPair是一个类:
public class JoinPair { long leftId; long rightId; }
这是一般形式(已经在其他答案中提供了)
var c =
from a in alpha
join b in beta on b.field1 equals a.field1 into b_temp
from b_value in b_temp.DefaultIfEmpty()
select new { Alpha = a, Beta = b_value };
然而,这里有一个解释,我希望能澄清这实际上是什么意思!
join b in beta on b.field1 equals a.field1 into b_temp
本质上创建了一个单独的结果集b_temp,其中有效地包含了右边条目的空“rows”('b'中的条目)。
然后是下一行:
from b_value in b_temp.DefaultIfEmpty()
..遍历该结果集,为右侧的'row'设置默认空值,并将右侧的行连接的结果设置为'b_value'的值(即,如果有匹配的记录,则为右侧的值,如果没有则为'null')。
现在,如果右边是一个单独的LINQ查询的结果,它将由匿名类型组成,它只能是'something'或'null'。如果它是一个可枚举的对象(例如,一个List -其中MyObjectB是一个有2个字段的类),那么它可以具体说明它的属性使用什么默认的“null”值:
var c =
from a in alpha
join b in beta on b.field1 equals a.field1 into b_temp
from b_value in b_temp.DefaultIfEmpty( new MyObjectB { Field1 = String.Empty, Field2 = (DateTime?) null })
select new { Alpha = a, Beta_field1 = b_value.Field1, Beta_field2 = b_value.Field2 };
这确保了'b'本身不是空的(但它的属性可以是空的,使用您指定的默认空值),这允许您检查b_value的属性,而不会得到b_value的空引用异常。注意,对于可空的DateTime, (DateTime?)类型,即。'nullable DateTime'必须在'DefaultIfEmpty'的规范中指定为null的'Type'(这也适用于'原生'不为空的类型,例如double, float)。
您可以通过简单地链接上述语法来执行多个左外连接。
如果需要连接和筛选某些东西,可以在连接之外完成。可以在创建集合之后进行筛选。
在这种情况下,如果我在连接条件中这样做,我减少了返回的行。
使用三元条件(= n == null ?"__": n.MonDayNote,)
如果对象为空(因此不匹配),则返回?后面的内容。__,在这种情况下。
否则,返回:,n.MonDayNote后面的内容。
感谢其他贡献者,这是我开始自己的问题。
var schedLocations = (from f in db.RAMS_REVENUE_LOCATIONS
join n in db.RAMS_LOCATION_PLANNED_MANNING on f.revenueCenterID equals
n.revenueCenterID into lm
from n in lm.DefaultIfEmpty()
join r in db.RAMS_LOCATION_SCHED_NOTE on f.revenueCenterID equals r.revenueCenterID
into locnotes
from r in locnotes.DefaultIfEmpty()
where f.LocID == nLocID && f.In_Use == true && f.revenueCenterID > 1000
orderby f.Areano ascending, f.Locname ascending
select new
{
Facname = f.Locname,
f.Areano,
f.revenueCenterID,
f.Locabbrev,
// MonNote = n == null ? "__" : n.MonDayNote,
MonNote = n == null ? "__" : n.MonDayNote,
TueNote = n == null ? "__" : n.TueDayNote,
WedNote = n == null ? "__" : n.WedDayNote,
ThuNote = n == null ? "__" : n.ThuDayNote,
FriNote = n == null ? "__" : n.FriDayNote,
SatNote = n == null ? "__" : n.SatDayNote,
SunNote = n == null ? "__" : n.SunDayNote,
MonEmpNbr = n == null ? 0 : n.MonEmpNbr,
TueEmpNbr = n == null ? 0 : n.TueEmpNbr,
WedEmpNbr = n == null ? 0 : n.WedEmpNbr,
ThuEmpNbr = n == null ? 0 : n.ThuEmpNbr,
FriEmpNbr = n == null ? 0 : n.FriEmpNbr,
SatEmpNbr = n == null ? 0 : n.SatEmpNbr,
SunEmpNbr = n == null ? 0 : n.SunEmpNbr,
SchedMondayDate = n == null ? dMon : n.MondaySchedDate,
LocNotes = r == null ? "Notes: N/A" : r.LocationNote
}).ToList();
Func<int, string> LambdaManning = (x) => { return x == 0 ? "" : "Manning:" + x.ToString(); };
DataTable dt_ScheduleMaster = PsuedoSchedule.Tables["ScheduleMasterWithNotes"];
var schedLocations2 = schedLocations.Where(x => x.SchedMondayDate == dMon);
看看这个例子
class Person
{
public int ID { get; set; }
public string FirstName { get; set; }
public string LastName { get; set; }
public string Phone { get; set; }
}
class Pet
{
public string Name { get; set; }
public Person Owner { get; set; }
}
public static void LeftOuterJoinExample()
{
Person magnus = new Person {ID = 1, FirstName = "Magnus", LastName = "Hedlund"};
Person terry = new Person {ID = 2, FirstName = "Terry", LastName = "Adams"};
Person charlotte = new Person {ID = 3, FirstName = "Charlotte", LastName = "Weiss"};
Person arlene = new Person {ID = 4, FirstName = "Arlene", LastName = "Huff"};
Pet barley = new Pet {Name = "Barley", Owner = terry};
Pet boots = new Pet {Name = "Boots", Owner = terry};
Pet whiskers = new Pet {Name = "Whiskers", Owner = charlotte};
Pet bluemoon = new Pet {Name = "Blue Moon", Owner = terry};
Pet daisy = new Pet {Name = "Daisy", Owner = magnus};
// Create two lists.
List<Person> people = new List<Person> {magnus, terry, charlotte, arlene};
List<Pet> pets = new List<Pet> {barley, boots, whiskers, bluemoon, daisy};
var query = from person in people
where person.ID == 4
join pet in pets on person equals pet.Owner into personpets
from petOrNull in personpets.DefaultIfEmpty()
select new { Person=person, Pet = petOrNull};
foreach (var v in query )
{
Console.WriteLine("{0,-15}{1}", v.Person.FirstName + ":", (v.Pet == null ? "Does not Exist" : v.Pet.Name));
}
}
// This code produces the following output:
//
// Magnus: Daisy
// Terry: Barley
// Terry: Boots
// Terry: Blue Moon
// Charlotte: Whiskers
// Arlene:
现在你可以从左边包含元素,即使那个元素在右边没有匹配,在我们的例子中,我们检索了Arlene,即使他在右边没有匹配
这是参考资料
如何:执行左外连接(c#编程指南)