这是我使用的LeftJoin实现。注意，resultSelector表达式接受2个参数:来自连接两端的一个实例。在我看到的大多数其他实现中，结果选择器只接受一个参数，这是一个具有左/右或外部/内部属性的“连接模型”。我更喜欢这个实现，因为它具有与内置Join方法相同的方法签名。它也适用于IQueryables和EF。

 var results = DbContext.Categories
      .LeftJoin(
            DbContext.Products, c => c.Id, p => p.CategoryId,
            (c, p) => new { Category = c, ProductName = p == null ? "(No Products)" : p.ProductName })
      .ToList();

public static class QueryableExtensions
{
    public static IQueryable<TResult> LeftJoin<TOuter, TInner, TKey, TResult>(
           this IQueryable<TOuter> outer, 
           IEnumerable<TInner> inner, Expression<Func<TOuter, TKey>> outerKeySelector, 
           Expression<Func<TInner, TKey>> innerKeySelector, 
           Expression<Func<TOuter, TInner, TResult>> resultSelector)
    {
        var query = outer
            .GroupJoin(inner, outerKeySelector, innerKeySelector, (o, i) => new { o, i })
            .SelectMany(o => o.i.DefaultIfEmpty(), (x, i) => new { x.o, i });
        return ApplySelector(query, x => x.o, x => x.i, resultSelector);
    }

    private static IQueryable<TResult> ApplySelector<TSource, TOuter, TInner, TResult>(
        IQueryable<TSource> source,
        Expression<Func<TSource, TOuter>> outerProperty,
        Expression<Func<TSource, TInner>> innerProperty,
        Expression<Func<TOuter, TInner, TResult>> resultSelector)
    {
        var p = Expression.Parameter(typeof(TSource), $"param_{Guid.NewGuid()}".Replace("-", string.Empty));
        Expression body = resultSelector?.Body
            .ReplaceParameter(resultSelector.Parameters[0], outerProperty.Body.ReplaceParameter(outerProperty.Parameters[0], p))
            .ReplaceParameter(resultSelector.Parameters[1], innerProperty.Body.ReplaceParameter(innerProperty.Parameters[0], p));
        var selector = Expression.Lambda<Func<TSource, TResult>>(body, p);
        return source.Select(selector);
    }
}

public static class ExpressionExtensions
{
    public static Expression ReplaceParameter(this Expression source, ParameterExpression toReplace, Expression newExpression)
        => new ReplaceParameterExpressionVisitor(toReplace, newExpression).Visit(source);
}

public class ReplaceParameterExpressionVisitor : ExpressionVisitor
{
    public ReplaceParameterExpressionVisitor(ParameterExpression toReplace, Expression replacement)
    {
        this.ToReplace = toReplace;
        this.Replacement = replacement;
    }

    public ParameterExpression ToReplace { get; }
    public Expression Replacement { get; }
    protected override Expression VisitParameter(ParameterExpression node)
        => (node == ToReplace) ? Replacement : base.VisitParameter(node);
}

看一下这个例子。 这个查询应该工作:

var leftFinal = from left in lefts
                join right in rights on left equals right.Left into leftRights
                from leftRight in leftRights.DefaultIfEmpty()
                select new { LeftId = left.Id, RightId = left.Key==leftRight.Key ? leftRight.Id : 0 };

如“Perform left outer joins”中所述:

var q =
    from c in categories
    join pt in products on c.Category equals pt.Category into ps_jointable
    from p in ps_jointable.DefaultIfEmpty()
    select new { Category = c, ProductName = p == null ? "(No products)" : p.ProductName };

如果需要连接和筛选某些东西，可以在连接之外完成。可以在创建集合之后进行筛选。

在这种情况下，如果我在连接条件中这样做，我减少了返回的行。

使用三元条件(= n == null ?"__": n.MonDayNote，)

如果对象为空(因此不匹配)，则返回?后面的内容。__，在这种情况下。 否则，返回:，n.MonDayNote后面的内容。

感谢其他贡献者，这是我开始自己的问题。

        var schedLocations = (from f in db.RAMS_REVENUE_LOCATIONS
              join n in db.RAMS_LOCATION_PLANNED_MANNING on f.revenueCenterID equals

                  n.revenueCenterID into lm

              from n in lm.DefaultIfEmpty()

              join r in db.RAMS_LOCATION_SCHED_NOTE on f.revenueCenterID equals r.revenueCenterID
              into locnotes

              from r in locnotes.DefaultIfEmpty()
              where f.LocID == nLocID && f.In_Use == true && f.revenueCenterID > 1000

              orderby f.Areano ascending, f.Locname ascending
              select new
              {
                  Facname = f.Locname,
                  f.Areano,
                  f.revenueCenterID,
                  f.Locabbrev,

                  //  MonNote = n == null ? "__" : n.MonDayNote,
                  MonNote = n == null ? "__" : n.MonDayNote,
                  TueNote = n == null ? "__" : n.TueDayNote,
                  WedNote = n == null ? "__" : n.WedDayNote,
                  ThuNote = n == null ? "__" : n.ThuDayNote,

                  FriNote = n == null ? "__" : n.FriDayNote,
                  SatNote = n == null ? "__" : n.SatDayNote,
                  SunNote = n == null ? "__" : n.SunDayNote,
                  MonEmpNbr = n == null ? 0 : n.MonEmpNbr,
                  TueEmpNbr = n == null ? 0 : n.TueEmpNbr,
                  WedEmpNbr = n == null ? 0 : n.WedEmpNbr,
                  ThuEmpNbr = n == null ? 0 : n.ThuEmpNbr,
                  FriEmpNbr = n == null ? 0 : n.FriEmpNbr,
                  SatEmpNbr = n == null ? 0 : n.SatEmpNbr,
                  SunEmpNbr = n == null ? 0 : n.SunEmpNbr,
                  SchedMondayDate = n == null ? dMon : n.MondaySchedDate,
                  LocNotes = r == null ? "Notes: N/A" : r.LocationNote

              }).ToList();
                Func<int, string> LambdaManning = (x) => { return x == 0 ? "" : "Manning:" + x.ToString(); };
        DataTable dt_ScheduleMaster = PsuedoSchedule.Tables["ScheduleMasterWithNotes"];
        var schedLocations2 = schedLocations.Where(x => x.SchedMondayDate == dMon);

扩展方法，类似于使用join语法的左连接

public static class LinQExtensions
{
    public static IEnumerable<TResult> LeftJoin<TOuter, TInner, TKey, TResult>(
        this IEnumerable<TOuter> outer, IEnumerable<TInner> inner, 
        Func<TOuter, TKey> outerKeySelector, 
        Func<TInner, TKey> innerKeySelector, 
        Func<TOuter, TInner, TResult> resultSelector)
    {
        return outer.GroupJoin(
            inner, 
            outerKeySelector, 
            innerKeySelector,
            (outerElement, innerElements) => resultSelector(outerElement, innerElements.FirstOrDefault()));
    }
}

我刚刚在。net内核中编写了它，它看起来像预期的那样工作。

小测试:

        var Ids = new List<int> { 1, 2, 3, 4};
        var items = new List<Tuple<int, string>>
        {
            new Tuple<int, string>(1,"a"),
            new Tuple<int, string>(2,"b"),
            new Tuple<int, string>(4,"d"),
            new Tuple<int, string>(5,"e"),
        };

        var result = Ids.LeftJoin(
            items,
            id => id,
            item => item.Item1,
            (id, item) => item ?? new Tuple<int, string>(id, "not found"));

        result.ToList()
        Count = 4
        [0]: {(1, a)}
        [1]: {(2, b)}
        [2]: {(3, not found)}
        [3]: {(4, d)}

根据我对类似问题的回答，在这里:

Linq到SQL左外连接使用Lambda语法和连接2列(复合连接键)

获得代码在这里，或克隆我的github回购，并发挥!

查询:

        var petOwners =
            from person in People
            join pet in Pets
            on new
            {
                person.Id,
                person.Age,
            }
            equals new
            {
                pet.Id,
                Age = pet.Age * 2, // owner is twice age of pet
            }
            into pets
            from pet in pets.DefaultIfEmpty()
            select new PetOwner
            {
                Person = person,
                Pet = pet,
            };

λ:

        var petOwners = People.GroupJoin(
            Pets,
            person => new { person.Id, person.Age },
            pet => new { pet.Id, Age = pet.Age * 2 },
            (person, pet) => new
            {
                Person = person,
                Pets = pet,
            }).SelectMany(
            pet => pet.Pets.DefaultIfEmpty(),
            (people, pet) => new
            {
                people.Person,
                Pet = pet,
            });