有三个表:persons, schools和persons_schools，它将人与他们所学习的学校联系起来。表persons_schools中没有对id=6的person的引用。但是id=6的人显示在左连接的结果网格中。

List<Person> persons = new List<Person>
{
    new Person { id = 1, name = "Alex", phone = "4235234" },
    new Person { id = 2, name = "Bob", phone = "0014352" },
    new Person { id = 3, name = "Sam", phone = "1345" },
    new Person { id = 4, name = "Den", phone = "3453452" },
    new Person { id = 5, name = "Alen", phone = "0353012" },
    new Person { id = 6, name = "Simon", phone = "0353012" }
};

List<School> schools = new List<School>
{
    new School { id = 1, name = "Saint. John's school"},
    new School { id = 2, name = "Public School 200"},
    new School { id = 3, name = "Public School 203"}
};

List<PersonSchool> persons_schools = new List<PersonSchool>
{
    new PersonSchool{id_person = 1, id_school = 1},
    new PersonSchool{id_person = 2, id_school = 2},
    new PersonSchool{id_person = 3, id_school = 3},
    new PersonSchool{id_person = 4, id_school = 1},
    new PersonSchool{id_person = 5, id_school = 2}
    //a relation to the person with id=6 is absent
};

var query = from person in persons
            join person_school in persons_schools on person.id equals person_school.id_person
            into persons_schools_joined
            from person_school_joined in persons_schools_joined.DefaultIfEmpty()
            from school in schools.Where(var_school => person_school_joined == null ? false : var_school.id == person_school_joined.id_school).DefaultIfEmpty()
            select new { Person = person.name, School = school == null ? String.Empty : school.name };

foreach (var elem in query)
{
    System.Console.WriteLine("{0},{1}", elem.Person, elem.School);
}

看一下这个例子。 这个查询应该工作:

var leftFinal = from left in lefts
                join right in rights on left equals right.Left into leftRights
                from leftRight in leftRights.DefaultIfEmpty()
                select new { LeftId = left.Id, RightId = left.Key==leftRight.Key ? leftRight.Id : 0 };

现在作为一个扩展方法:

public static class LinqExt
{
    public static IEnumerable<TResult> LeftOuterJoin<TLeft, TRight, TKey, TResult>(this IEnumerable<TLeft> left, IEnumerable<TRight> right, Func<TLeft, TKey> leftKey, Func<TRight, TKey> rightKey,
        Func<TLeft, TRight, TResult> result)
    {
        return left.GroupJoin(right, leftKey, rightKey, (l, r) => new { l, r })
             .SelectMany(
                 o => o.r.DefaultIfEmpty(),
                 (l, r) => new { lft= l.l, rght = r })
             .Select(o => result.Invoke(o.lft, o.rght));
    }
}

像平常使用join一样使用:

var contents = list.LeftOuterJoin(list2, 
             l => l.country, 
             r => r.name,
            (l, r) => new { count = l.Count(), l.country, l.reason, r.people })

希望这能为您节省一些时间。

看看这个例子

class Person
{
    public int ID { get; set; }
    public string FirstName { get; set; }
    public string LastName { get; set; }
    public string Phone { get; set; }
}

class Pet
{
    public string Name { get; set; }
    public Person Owner { get; set; }
}

public static void LeftOuterJoinExample()
{
    Person magnus = new Person {ID = 1, FirstName = "Magnus", LastName = "Hedlund"};
    Person terry = new Person {ID = 2, FirstName = "Terry", LastName = "Adams"};
    Person charlotte = new Person {ID = 3, FirstName = "Charlotte", LastName = "Weiss"};
    Person arlene = new Person {ID = 4, FirstName = "Arlene", LastName = "Huff"};

    Pet barley = new Pet {Name = "Barley", Owner = terry};
    Pet boots = new Pet {Name = "Boots", Owner = terry};
    Pet whiskers = new Pet {Name = "Whiskers", Owner = charlotte};
    Pet bluemoon = new Pet {Name = "Blue Moon", Owner = terry};
    Pet daisy = new Pet {Name = "Daisy", Owner = magnus};

    // Create two lists.
    List<Person> people = new List<Person> {magnus, terry, charlotte, arlene};
    List<Pet> pets = new List<Pet> {barley, boots, whiskers, bluemoon, daisy};

    var query = from person in people
        where person.ID == 4
        join pet in pets on person equals pet.Owner  into personpets
        from petOrNull in personpets.DefaultIfEmpty()
        select new { Person=person, Pet = petOrNull}; 



    foreach (var v in query )
    {
        Console.WriteLine("{0,-15}{1}", v.Person.FirstName + ":", (v.Pet == null ? "Does not Exist" : v.Pet.Name));
    }
}

// This code produces the following output:
//
// Magnus:        Daisy
// Terry:         Barley
// Terry:         Boots
// Terry:         Blue Moon
// Charlotte:     Whiskers
// Arlene:

现在你可以从左边包含元素，即使那个元素在右边没有匹配，在我们的例子中，我们检索了Arlene，即使他在右边没有匹配

这是参考资料

如何:执行左外连接(c#编程指南)

下面是使用方法语法的一个相当容易理解的版本:

IEnumerable<JoinPair> outerLeft =
    lefts.SelectMany(l => 
        rights.Where(r => l.Key == r.Key)
              .DefaultIfEmpty(new Item())
              .Select(r => new JoinPair { LeftId = l.Id, RightId = r.Id }));

这是我使用的LeftJoin实现。注意，resultSelector表达式接受2个参数:来自连接两端的一个实例。在我看到的大多数其他实现中，结果选择器只接受一个参数，这是一个具有左/右或外部/内部属性的“连接模型”。我更喜欢这个实现，因为它具有与内置Join方法相同的方法签名。它也适用于IQueryables和EF。

 var results = DbContext.Categories
      .LeftJoin(
            DbContext.Products, c => c.Id, p => p.CategoryId,
            (c, p) => new { Category = c, ProductName = p == null ? "(No Products)" : p.ProductName })
      .ToList();

public static class QueryableExtensions
{
    public static IQueryable<TResult> LeftJoin<TOuter, TInner, TKey, TResult>(
           this IQueryable<TOuter> outer, 
           IEnumerable<TInner> inner, Expression<Func<TOuter, TKey>> outerKeySelector, 
           Expression<Func<TInner, TKey>> innerKeySelector, 
           Expression<Func<TOuter, TInner, TResult>> resultSelector)
    {
        var query = outer
            .GroupJoin(inner, outerKeySelector, innerKeySelector, (o, i) => new { o, i })
            .SelectMany(o => o.i.DefaultIfEmpty(), (x, i) => new { x.o, i });
        return ApplySelector(query, x => x.o, x => x.i, resultSelector);
    }

    private static IQueryable<TResult> ApplySelector<TSource, TOuter, TInner, TResult>(
        IQueryable<TSource> source,
        Expression<Func<TSource, TOuter>> outerProperty,
        Expression<Func<TSource, TInner>> innerProperty,
        Expression<Func<TOuter, TInner, TResult>> resultSelector)
    {
        var p = Expression.Parameter(typeof(TSource), $"param_{Guid.NewGuid()}".Replace("-", string.Empty));
        Expression body = resultSelector?.Body
            .ReplaceParameter(resultSelector.Parameters[0], outerProperty.Body.ReplaceParameter(outerProperty.Parameters[0], p))
            .ReplaceParameter(resultSelector.Parameters[1], innerProperty.Body.ReplaceParameter(innerProperty.Parameters[0], p));
        var selector = Expression.Lambda<Func<TSource, TResult>>(body, p);
        return source.Select(selector);
    }
}

public static class ExpressionExtensions
{
    public static Expression ReplaceParameter(this Expression source, ParameterExpression toReplace, Expression newExpression)
        => new ReplaceParameterExpressionVisitor(toReplace, newExpression).Visit(source);
}

public class ReplaceParameterExpressionVisitor : ExpressionVisitor
{
    public ReplaceParameterExpressionVisitor(ParameterExpression toReplace, Expression replacement)
    {
        this.ToReplace = toReplace;
        this.Replacement = replacement;
    }

    public ParameterExpression ToReplace { get; }
    public Expression Replacement { get; }
    protected override Expression VisitParameter(ParameterExpression node)
        => (node == ToReplace) ? Replacement : base.VisitParameter(node);
}