在Python中似乎有很多方法来定义单例对象。对Stack Overflow是否有一致的意见?


当前回答

你可以像这样重写__new__方法:

class Singleton(object):
    _instance = None
    def __new__(cls, *args, **kwargs):
        if not cls._instance:
            cls._instance = super(Singleton, cls).__new__(
                                cls, *args, **kwargs)
        return cls._instance


if __name__ == '__main__':
    s1 = Singleton()
    s2 = Singleton()
    if (id(s1) == id(s2)):
        print "Same"
    else:
        print "Different"

其他回答

作为Python的新手,我不确定最常见的习语是什么,但我能想到的最简单的事情就是使用模块而不是类。类中的实例方法变成了模块中的函数,任何数据都变成了模块中的变量,而不是类的成员。我怀疑这是解决人们使用单例对象的问题的python方法。

如果你真的想要一个单例类,有一个合理的实现描述在谷歌的第一个点击“Python singleton”,具体地说:

class Singleton:
    __single = None
    def __init__( self ):
        if Singleton.__single:
            raise Singleton.__single
        Singleton.__single = self

这似乎奏效了。

这是我自己对单例对象的实现。你所要做的就是布置课堂;为了获得单例,你必须使用Instance方法。这里有一个例子:

@Singleton
class Foo:
   def __init__(self):
       print 'Foo created'

f = Foo() # Error, this isn't how you get the instance of a singleton

f = Foo.instance() # Good. Being explicit is in line with the Python Zen
g = Foo.instance() # Returns already created instance

print f is g # True

下面是代码:

class Singleton:
    """
    A non-thread-safe helper class to ease implementing singletons.
    This should be used as a decorator -- not a metaclass -- to the
    class that should be a singleton.

    The decorated class can define one `__init__` function that
    takes only the `self` argument. Also, the decorated class cannot be
    inherited from. Other than that, there are no restrictions that apply
    to the decorated class.

    To get the singleton instance, use the `instance` method. Trying
    to use `__call__` will result in a `TypeError` being raised.

    """

    def __init__(self, decorated):
        self._decorated = decorated

    def instance(self):
        """
        Returns the singleton instance. Upon its first call, it creates a
        new instance of the decorated class and calls its `__init__` method.
        On all subsequent calls, the already created instance is returned.

        """
        try:
            return self._instance
        except AttributeError:
            self._instance = self._decorated()
            return self._instance

    def __call__(self):
        raise TypeError('Singletons must be accessed through `instance()`.')

    def __instancecheck__(self, inst):
        return isinstance(inst, self._decorated)

好吧,我知道,单胞胎可能是好的,也可能是坏的。这是我的实现,我只是扩展了一个经典的方法,在里面引入一个缓存,并产生许多不同类型的实例,或者许多相同类型的实例,但具有不同的参数。

我称它为Singleton_group,因为它将相似的实例分组在一起,并防止创建具有相同参数的相同类的对象:

# Peppelinux's cached singleton
class Singleton_group(object):
    __instances_args_dict = {}
    def __new__(cls, *args, **kwargs):
        if not cls.__instances_args_dict.get((cls.__name__, args, str(kwargs))):
            cls.__instances_args_dict[(cls.__name__, args, str(kwargs))] = super(Singleton_group, cls).__new__(cls, *args, **kwargs)
        return cls.__instances_args_dict.get((cls.__name__, args, str(kwargs)))


# It's a dummy real world use example:
class test(Singleton_group):
    def __init__(self, salute):
        self.salute = salute

a = test('bye')
b = test('hi')
c = test('bye')
d = test('hi')
e = test('goodbye')
f = test('goodbye')

id(a)
3070148780L

id(b)
3070148908L

id(c)
3070148780L

b == d
True


b._Singleton_group__instances_args_dict

{('test', ('bye',), '{}'): <__main__.test object at 0xb6fec0ac>,
 ('test', ('goodbye',), '{}'): <__main__.test object at 0xb6fec32c>,
 ('test', ('hi',), '{}'): <__main__.test object at 0xb6fec12c>}

每个对象都携带单例缓存…这可能是邪恶的,但对一些人来说很有用:)

Python文档涵盖了这些内容:

class Singleton(object):
    def __new__(cls, *args, **kwds):
        it = cls.__dict__.get("__it__")
        if it is not None:
            return it
        cls.__it__ = it = object.__new__(cls)
        it.init(*args, **kwds)
        return it
    def init(self, *args, **kwds):
        pass

我可能会重写成这样:

class Singleton(object):
    """Use to create a singleton"""
    def __new__(cls, *args, **kwds):
        """
        >>> s = Singleton()
        >>> p = Singleton()
        >>> id(s) == id(p)
        True
        """
        it_id = "__it__"
        # getattr will dip into base classes, so __dict__ must be used
        it = cls.__dict__.get(it_id, None)
        if it is not None:
            return it
        it = object.__new__(cls)
        setattr(cls, it_id, it)
        it.init(*args, **kwds)
        return it

    def init(self, *args, **kwds):
        pass


class A(Singleton):
    pass


class B(Singleton):
    pass


class C(A):
    pass


assert A() is A()
assert B() is B()
assert C() is C()
assert A() is not B()
assert C() is not B()
assert C() is not A()

它应该是相对干净的扩展:

class Bus(Singleton):
    def init(self, label=None, *args, **kwds):
        self.label = label
        self.channels = [Channel("system"), Channel("app")]
        ...

正如公认的答案所说,最常用的方法是只使用一个模块。

考虑到这一点,下面是一个概念的证明:

def singleton(cls):
    obj = cls()
    # Always return the same object
    cls.__new__ = staticmethod(lambda cls: obj)
    # Disable __init__
    try:
        del cls.__init__
    except AttributeError:
        pass
    return cls

有关__new__的更多详细信息,请参阅Python数据模型。

例子:

@singleton
class Duck(object):
    pass

if Duck() is Duck():
    print "It works!"
else:
    print "It doesn't work!"

注:

为此,您必须使用new-style类(派生自object)。 单例在定义时初始化,而不是在第一次使用时初始化。 这只是一个简单的例子。我从未在产品代码中实际使用过它,也不打算这样做。