你可以像这样重写__new__方法:

class Singleton(object):
    _instance = None
    def __new__(cls, *args, **kwargs):
        if not cls._instance:
            cls._instance = super(Singleton, cls).__new__(
                                cls, *args, **kwargs)
        return cls._instance


if __name__ == '__main__':
    s1 = Singleton()
    s2 = Singleton()
    if (id(s1) == id(s2)):
        print "Same"
    else:
        print "Different"

这是我自己对单例对象的实现。你所要做的就是布置课堂;为了获得单例，你必须使用Instance方法。这里有一个例子:

@Singleton
class Foo:
   def __init__(self):
       print 'Foo created'

f = Foo() # Error, this isn't how you get the instance of a singleton

f = Foo.instance() # Good. Being explicit is in line with the Python Zen
g = Foo.instance() # Returns already created instance

print f is g # True

下面是代码:

class Singleton:
    """
    A non-thread-safe helper class to ease implementing singletons.
    This should be used as a decorator -- not a metaclass -- to the
    class that should be a singleton.

    The decorated class can define one `__init__` function that
    takes only the `self` argument. Also, the decorated class cannot be
    inherited from. Other than that, there are no restrictions that apply
    to the decorated class.

    To get the singleton instance, use the `instance` method. Trying
    to use `__call__` will result in a `TypeError` being raised.

    """

    def __init__(self, decorated):
        self._decorated = decorated

    def instance(self):
        """
        Returns the singleton instance. Upon its first call, it creates a
        new instance of the decorated class and calls its `__init__` method.
        On all subsequent calls, the already created instance is returned.

        """
        try:
            return self._instance
        except AttributeError:
            self._instance = self._decorated()
            return self._instance

    def __call__(self):
        raise TypeError('Singletons must be accessed through `instance()`.')

    def __instancecheck__(self, inst):
        return isinstance(inst, self._decorated)

有一次我用Python写了一个单例，我使用了一个类，其中所有成员函数都有classmethod装饰器。

class Foo:
    x = 1
  
    @classmethod
    def increment(cls, y=1):
        cls.x += y

作为Python的新手，我不确定最常见的习语是什么，但我能想到的最简单的事情就是使用模块而不是类。类中的实例方法变成了模块中的函数，任何数据都变成了模块中的变量，而不是类的成员。我怀疑这是解决人们使用单例对象的问题的python方法。

如果你真的想要一个单例类，有一个合理的实现描述在谷歌的第一个点击“Python singleton”，具体地说:

class Singleton:
    __single = None
    def __init__( self ):
        if Singleton.__single:
            raise Singleton.__single
        Singleton.__single = self

这似乎奏效了。

由ActiveState提供的Python实现的单例模式。

看起来窍门是把应该只有一个实例的类放在另一个类中。

正如公认的答案所说，最常用的方法是只使用一个模块。

考虑到这一点，下面是一个概念的证明:

def singleton(cls):
    obj = cls()
    # Always return the same object
    cls.__new__ = staticmethod(lambda cls: obj)
    # Disable __init__
    try:
        del cls.__init__
    except AttributeError:
        pass
    return cls

有关__new__的更多详细信息，请参阅Python数据模型。

例子:

@singleton
class Duck(object):
    pass

if Duck() is Duck():
    print "It works!"
else:
    print "It doesn't work!"

注:

为此，您必须使用new-style类(派生自object)。 单例在定义时初始化，而不是在第一次使用时初始化。 这只是一个简单的例子。我从未在产品代码中实际使用过它，也不打算这样做。