在JavaScript中实现堆栈和队列的最佳方法是什么?

我想做调车场算法我需要这些数据结构。


当前回答

/*------------------------------------------------------------------ 
 Defining Stack Operations using Closures in Javascript, privacy and
 state of stack operations are maintained

 @author:Arijt Basu
 Log: Sun Dec 27, 2015, 3:25PM
 ------------------------------------------------------------------- 
 */
var stackControl = true;
var stack = (function(array) {
        array = [];
        //--Define the max size of the stack
        var MAX_SIZE = 5;

        function isEmpty() {
            if (array.length < 1) console.log("Stack is empty");
        };
        isEmpty();

        return {

            push: function(ele) {
                if (array.length < MAX_SIZE) {
                    array.push(ele)
                    return array;
                } else {
                    console.log("Stack Overflow")
                }
            },
            pop: function() {
                if (array.length > 1) {
                    array.pop();
                    return array;
                } else {
                    console.log("Stack Underflow");
                }
            }

        }
    })()
    // var list = 5;
    // console.log(stack(list))
if (stackControl) {
    console.log(stack.pop());
    console.log(stack.push(3));
    console.log(stack.push(2));
    console.log(stack.pop());
    console.log(stack.push(1));
    console.log(stack.pop());
    console.log(stack.push(38));
    console.log(stack.push(22));
    console.log(stack.pop());
    console.log(stack.pop());
    console.log(stack.push(6));
    console.log(stack.pop());
}
//End of STACK Logic

/* Defining Queue operations*/

var queue = (function(array) {
    array = [];
    var reversearray;
    //--Define the max size of the stack
    var MAX_SIZE = 5;

    function isEmpty() {
        if (array.length < 1) console.log("Queue is empty");
    };
    isEmpty();

    return {
        insert: function(ele) {
            if (array.length < MAX_SIZE) {
                array.push(ele)
                reversearray = array.reverse();
                return reversearray;
            } else {
                console.log("Queue Overflow")
            }
        },
        delete: function() {
            if (array.length > 1) {
                //reversearray = array.reverse();
                array.pop();
                return array;
            } else {
                console.log("Queue Underflow");
            }
        }
    }



})()

console.log(queue.insert(5))
console.log(queue.insert(3))
console.log(queue.delete(3))

其他回答

下面是一个相当简单的队列实现,有两个目标:

与array.shift()不同,您知道这个出队列方法需要常数时间(O(1))。 为了提高速度,这种方法使用的分配比链表方法少得多。

堆栈实现只共享第二个目标。

// Queue
function Queue() {
        this.q = new Array(5);
        this.first = 0;
        this.size = 0;
}
Queue.prototype.enqueue = function(a) {
        var other;
        if (this.size == this.q.length) {
                other = new Array(this.size*2);
                for (var i = 0; i < this.size; i++) {
                        other[i] = this.q[(this.first+i)%this.size];
                }
                this.first = 0;
                this.q = other;
        }
        this.q[(this.first+this.size)%this.q.length] = a;
        this.size++;
};
Queue.prototype.dequeue = function() {
        if (this.size == 0) return undefined;
        this.size--;
        var ret = this.q[this.first];
        this.first = (this.first+1)%this.q.length;
        return ret;
};
Queue.prototype.peek = function() { return this.size > 0 ? this.q[this.first] : undefined; };
Queue.prototype.isEmpty = function() { return this.size == 0; };

// Stack
function Stack() {
        this.s = new Array(5);
        this.size = 0;
}
Stack.prototype.push = function(a) {
        var other;
    if (this.size == this.s.length) {
            other = new Array(this.s.length*2);
            for (var i = 0; i < this.s.length; i++) other[i] = this.s[i];
            this.s = other;
    }
    this.s[this.size++] = a;
};
Stack.prototype.pop = function() {
        if (this.size == 0) return undefined;
        return this.s[--this.size];
};
Stack.prototype.peek = function() { return this.size > 0 ? this.s[this.size-1] : undefined; };

使用两个堆栈构造一个队列。

O(1)用于入队和出队操作。

class Queue {
  constructor() {
    this.s1 = []; // in
    this.s2 = []; // out
  }

  enqueue(val) {
    this.s1.push(val);
  }

  dequeue() {
    if (this.s2.length === 0) {
      this._move();
    }

    return this.s2.pop(); // return undefined if empty
  }

  _move() {
    while (this.s1.length) {
      this.s2.push(this.s1.pop());
    }
  }
}

你可以基于这个概念使用你自己的自定义类,这里是你可以用来做这些事情的代码片段

/*
*   Stack implementation in JavaScript
*/



function Stack() {
  this.top = null;
  this.count = 0;

  this.getCount = function() {
    return this.count;
  }

  this.getTop = function() {
    return this.top;
  }

  this.push = function(data) {
    var node = {
      data: data,
      next: null
    }

    node.next = this.top;
    this.top = node;

    this.count++;
  }

  this.peek = function() {
    if (this.top === null) {
      return null;
    } else {
      return this.top.data;
    }
  }

  this.pop = function() {
    if (this.top === null) {
      return null;
    } else {
      var out = this.top;
      this.top = this.top.next;
      if (this.count > 0) {
        this.count--;
      }

      return out.data;
    }
  }

  this.displayAll = function() {
    if (this.top === null) {
      return null;
    } else {
      var arr = new Array();

      var current = this.top;
      //console.log(current);
      for (var i = 0; i < this.count; i++) {
        arr[i] = current.data;
        current = current.next;
      }

      return arr;
    }
  }
}

要检查这一点,请使用控制台,并逐一尝试这些行。

>> var st = new Stack();

>> st.push("BP");

>> st.push("NK");

>> st.getTop();

>> st.getCount();

>> st.displayAll();

>> st.pop();

>> st.displayAll();

>> st.getTop();

>> st.peek();

单端队列

这是一个使用映射的队列。由于插入顺序得到了保证,所以可以像迭代数组一样迭代它。除此之外,它的思想与Queue.js非常相似。

我做了一些简单的测试,但还没有进行广泛的测试。我还添加了一些我认为很好的功能(通过数组构造)或易于实现(例如last()和first())。

它背后的简单版本/直觉如下:

class Queue {
    constructor() {
        this.offset = 0
        this.data = new Map()
    }

    enqueue(item) {
        const current = this.offset + this.length()
        this.data.set(current, item)
    }

    dequeue() {
        if (this.length() > 0) {
            this.data.delete(this.offset)
            this.offset += 1
        }
    }

    first() {
        return this.data.get(this.offset)
    }

    last() {
        return this.data.get(this.offset + this.length() - 1)
    }

    length() {
        return this.data.size
    }
}

简单版本的问题是,当内存索引超过9千万亿(Number.MAX_SAFE_INTEGER的值)时,需要重新映射内存。此外,我认为它可能很好有数组构造,它很高兴看到值正在进入队列和退出队列返回。可以通过编写以下代码来解释这一点:

class Queue {
    constructor() {
        this.offset = 0
        this.data = new Map()
        if (arguments.length === 1) this._initializeFromArray(arguments[0])
    }

    enqueue(item) {
        const current = this.offset + this.length()
        this.data.set(current, item)
        let result = this.data.get(current)
        this._remapDataIfMaxMemoryViolation(current, Number.MAX_SAFE_INTEGER)
        return result
    }

    dequeue() {
        let result = undefined
        if (this.length() > 0) {
            result = this.data.get(this.offset)
            this.data.delete(this.offset)
            this.offset += 1
        }
        if (this.length() === 0) this.offset = 0
        return result
    }

    first() {
        return this.data.get(this.offset)
    }

    last() {
        return this.data.get(this.offset + this.length() - 1)
    }

    length() {
        return this.data.size
    }

    _remapDataIfMaxMemoryViolation(current, threshhold) {
        if (current+1 === threshhold) {
            const length = this.length()
            this.offset = 0
            for (const [key, value] of this.data) {
                this.data.set(this.offset, value)
                this.data.delete(key, value)
                this.offset += 1
                if (this.offset === length) break
            }       
        }
    }

    _initializeFromArray(array) {
        for (const value of array) {
            this.data.set(this.offset, value)
            this.offset += 1
        }
    }
}

我在Chrome开发控制台进行了一些测试,对完整版本进行了以下调用。

l = console.log // I'm lazy with typing
q = new Queue()
l('enqueue', q.enqueue(1))
l('enqueue', q.enqueue(2))
l('enqueue', q.enqueue(3))
l('enqueue', q.enqueue("hello"))
l('enqueue', q.enqueue("monkey"))
l('show 5 elements: ', q.data)
l('length', q.length())
l('first', q.first())
l('last', q.last())
l('dequeue', q.dequeue())
l('dequeue', q.dequeue())
l('show 3 elements', q.data)
q._remapDataIfMaxMemoryViolation(q.length()+q.offset-1, 5)
l('show 3 remapped elements', q.data)

l(queue = new Queue([3,4,5,6,7,8,9]))
l(queue.data)

Javascript数组shift()很慢,特别是当包含很多元素时。我知道两种方法来实现平摊O(1)复杂度的队列。

首先是使用循环缓冲区和表加倍。我以前实现过这个。你可以在这里看到我的源代码 https://github.com/kevyuu/rapid-queue

第二种方法是使用两个堆栈。这是带有两个堆栈的队列的代码

function createDoubleStackQueue() {
var that = {};
var pushContainer = [];
var popContainer = [];

function moveElementToPopContainer() {
    while (pushContainer.length !==0 ) {
        var element = pushContainer.pop();
        popContainer.push(element);
    }
}

that.push = function(element) {
    pushContainer.push(element);
};

that.shift = function() {
    if (popContainer.length === 0) {
        moveElementToPopContainer();
    }
    if (popContainer.length === 0) {
        return null;
    } else {
        return popContainer.pop();
    }
};

that.front = function() {
    if (popContainer.length === 0) {
        moveElementToPopContainer();
    }
    if (popContainer.length === 0) {
        return null;
    }
    return popContainer[popContainer.length - 1];
};

that.length = function() {
    return pushContainer.length + popContainer.length;
};

that.isEmpty = function() {
    return (pushContainer.length + popContainer.length) === 0;
};

return that;}

这是使用jsPerf进行的性能比较

CircularQueue.shift() vs Array.shift()

http://jsperf.com/rapidqueue-shift-vs-array-shift

正如你所看到的,大数据集的速度要快得多