在JavaScript中实现堆栈和队列的最佳方法是什么?
我想做调车场算法我需要这些数据结构。
在JavaScript中实现堆栈和队列的最佳方法是什么?
我想做调车场算法我需要这些数据结构。
当前回答
使用两个堆栈构造一个队列。
O(1)用于入队和出队操作。
class Queue {
constructor() {
this.s1 = []; // in
this.s2 = []; // out
}
enqueue(val) {
this.s1.push(val);
}
dequeue() {
if (this.s2.length === 0) {
this._move();
}
return this.s2.pop(); // return undefined if empty
}
_move() {
while (this.s1.length) {
this.s2.push(this.s1.pop());
}
}
}
其他回答
Javascript数组shift()很慢,特别是当包含很多元素时。我知道两种方法来实现平摊O(1)复杂度的队列。
首先是使用循环缓冲区和表加倍。我以前实现过这个。你可以在这里看到我的源代码 https://github.com/kevyuu/rapid-queue
第二种方法是使用两个堆栈。这是带有两个堆栈的队列的代码
function createDoubleStackQueue() {
var that = {};
var pushContainer = [];
var popContainer = [];
function moveElementToPopContainer() {
while (pushContainer.length !==0 ) {
var element = pushContainer.pop();
popContainer.push(element);
}
}
that.push = function(element) {
pushContainer.push(element);
};
that.shift = function() {
if (popContainer.length === 0) {
moveElementToPopContainer();
}
if (popContainer.length === 0) {
return null;
} else {
return popContainer.pop();
}
};
that.front = function() {
if (popContainer.length === 0) {
moveElementToPopContainer();
}
if (popContainer.length === 0) {
return null;
}
return popContainer[popContainer.length - 1];
};
that.length = function() {
return pushContainer.length + popContainer.length;
};
that.isEmpty = function() {
return (pushContainer.length + popContainer.length) === 0;
};
return that;}
这是使用jsPerf进行的性能比较
CircularQueue.shift() vs Array.shift()
http://jsperf.com/rapidqueue-shift-vs-array-shift
正如你所看到的,大数据集的速度要快得多
/*------------------------------------------------------------------
Defining Stack Operations using Closures in Javascript, privacy and
state of stack operations are maintained
@author:Arijt Basu
Log: Sun Dec 27, 2015, 3:25PM
-------------------------------------------------------------------
*/
var stackControl = true;
var stack = (function(array) {
array = [];
//--Define the max size of the stack
var MAX_SIZE = 5;
function isEmpty() {
if (array.length < 1) console.log("Stack is empty");
};
isEmpty();
return {
push: function(ele) {
if (array.length < MAX_SIZE) {
array.push(ele)
return array;
} else {
console.log("Stack Overflow")
}
},
pop: function() {
if (array.length > 1) {
array.pop();
return array;
} else {
console.log("Stack Underflow");
}
}
}
})()
// var list = 5;
// console.log(stack(list))
if (stackControl) {
console.log(stack.pop());
console.log(stack.push(3));
console.log(stack.push(2));
console.log(stack.pop());
console.log(stack.push(1));
console.log(stack.pop());
console.log(stack.push(38));
console.log(stack.push(22));
console.log(stack.pop());
console.log(stack.pop());
console.log(stack.push(6));
console.log(stack.pop());
}
//End of STACK Logic
/* Defining Queue operations*/
var queue = (function(array) {
array = [];
var reversearray;
//--Define the max size of the stack
var MAX_SIZE = 5;
function isEmpty() {
if (array.length < 1) console.log("Queue is empty");
};
isEmpty();
return {
insert: function(ele) {
if (array.length < MAX_SIZE) {
array.push(ele)
reversearray = array.reverse();
return reversearray;
} else {
console.log("Queue Overflow")
}
},
delete: function() {
if (array.length > 1) {
//reversearray = array.reverse();
array.pop();
return array;
} else {
console.log("Queue Underflow");
}
}
}
})()
console.log(queue.insert(5))
console.log(queue.insert(3))
console.log(queue.delete(3))
很抱歉碰到这个话题,但我滚动了许多答案,没有看到任何基于对象的队列的实现,它可以用O(1)执行排队和出队列,并且没有浪费内存。
Dmitri Pavlutin在他的博客https://dmitripavlutin.com/javascript-queue/上有一个很好的入门代码
它只遗漏了一个长度为0的检查,这是很容易添加的。
这个解决方案的最大和唯一的问题是不断增长的索引可能会在某一点上达到一些数量限制,如果队列运行很长时间和/或高速(我的意图是处理音频=高速)。
这个问题没有完美的解决方案……最简单的方法是在队列为空时将索引重置为0。
最后,我添加了一个重构方法,它将所有索引移回开始,以在队列永远不为空的情况下使用。
性能无疑是更好的(以毫秒为单位的时间,排队10000个号码然后退出它们):
class QueueObject {
constructor () {
this.data = {}
this.head = 0
this.tail = 0
this.length = 0
}
enqueue (value) {
this.data[this.tail++] = value
this.length++
}
dequeue () {
let value
if (this.length > 0) {
this.length--
value = this.data[this.head]
delete this.data[this.head++]
} else {
this.head = 0
this.tail = 0
value = null
}
return value
}
refactor () {
if (this.head > 0) {
for (let i = this.head; i < this.tail; i++) {
this.data[i - this.head] = this.data[i]
delete this.data[i]
}
this.tail = this.length
this.head = 0
}
}
}
Javascript有push和pop方法,它们操作在普通的Javascript数组对象上。
关于排队,请看这里:
http://safalra.com/web-design/javascript/queues/
Queues can be implemented in JavaScript using either the push and shift methods or unshift and pop methods of the array object. Although this is a simple way to implement queues, it is very inefficient for large queues — because of the methods operate on arrays, the shift and unshift methods move every element in the array each time they are called. Queue.js is a simple and efficient queue implementation for JavaScript whose dequeue function runs in amortized constant time. As a result, for larger queues, it can be significantly faster than using arrays.
没有数组(年代)
//Javascript stack linked list data structure (no array)
function node(value, noderef) {
this.value = value;
this.next = noderef;
}
function stack() {
this.push = function (value) {
this.next = this.first;
this.first = new node(value, this.next);
}
this.pop = function () {
var popvalue = this.first.value;
this.first = this.first.next;
return popvalue;
}
this.hasnext = function () {
return this.next != undefined;
}
this.isempty = function () {
return this.first == undefined;
}
}
//Javascript stack linked list data structure (no array)
function node(value, noderef) {
this.value = value;
this.next = undefined;
}
function queue() {
this.enqueue = function (value) {
this.oldlast = this.last;
this.last = new node(value);
if (this.isempty())
this.first = this.last;
else
this.oldlast.next = this.last;
}
this.dequeue = function () {
var queuvalue = this.first.value;
this.first = this.first.next;
return queuvalue;
}
this.hasnext = function () {
return this.first.next != undefined;
}
this.isempty = function () {
return this.first == undefined;
}
}