我们没有得到正确的结果，因为任何javascript生成的内容都需要在DOM上呈现。当我们获取一个HTML页面时，我们获取初始的，未经javascript修改的DOM。

因此，我们需要在抓取页面之前呈现javascript内容。

由于selenium已经在本线程中多次提到(有时也提到了它的速度有多慢)，我将列出其他两种可能的解决方案。

解决方案1:这是一个关于如何使用Scrapy抓取javascript生成内容的非常好的教程，我们将遵循这一点。

我们需要:

Docker installed in our machine. This is a plus over other solutions until this point, as it utilizes an OS-independent platform. Install Splash following the instruction listed for our corresponding OS.Quoting from splash documentation: Splash is a javascript rendering service. It’s a lightweight web browser with an HTTP API, implemented in Python 3 using Twisted and QT5. Essentially we are going to use Splash to render Javascript generated content. Run the splash server: sudo docker run -p 8050:8050 scrapinghub/splash. Install the scrapy-splash plugin: pip install scrapy-splash Assuming that we already have a Scrapy project created (if not, let's make one), we will follow the guide and update the settings.py: Then go to your scrapy project’s settings.py and set these middlewares: DOWNLOADER_MIDDLEWARES = { 'scrapy_splash.SplashCookiesMiddleware': 723, 'scrapy_splash.SplashMiddleware': 725, 'scrapy.downloadermiddlewares.httpcompression.HttpCompressionMiddleware': 810, } The URL of the Splash server(if you’re using Win or OSX this should be the URL of the docker machine: How to get a Docker container's IP address from the host?): SPLASH_URL = 'http://localhost:8050' And finally you need to set these values too: DUPEFILTER_CLASS = 'scrapy_splash.SplashAwareDupeFilter' HTTPCACHE_STORAGE = 'scrapy_splash.SplashAwareFSCacheStorage' Finally, we can use a SplashRequest: In a normal spider you have Request objects which you can use to open URLs. If the page you want to open contains JS generated data you have to use SplashRequest(or SplashFormRequest) to render the page. Here’s a simple example: class MySpider(scrapy.Spider): name = "jsscraper" start_urls = ["http://quotes.toscrape.com/js/"] def start_requests(self): for url in self.start_urls: yield SplashRequest( url=url, callback=self.parse, endpoint='render.html' ) def parse(self, response): for q in response.css("div.quote"): quote = QuoteItem() quote["author"] = q.css(".author::text").extract_first() quote["quote"] = q.css(".text::text").extract_first() yield quote SplashRequest renders the URL as html and returns the response which you can use in the callback(parse) method.

解决方案2:我们暂且称之为实验性的(2018年5月)…… 此解决方案仅适用于Python版本3.6(目前)。

你知道请求模块吗(谁不知道呢)? 现在它有了一个网络爬行的小兄弟:requests-HTML:

这个库旨在使解析HTML(例如抓取网页)尽可能简单和直观。

安装请求-html: pipenv 对页面的url进行请求: 导入HTMLSession 会话= HTMLSession() R = session.get(a_page_url) 渲染响应以获得Javascript生成的比特: r.html.render ()

最后，该模块似乎提供了抓取功能。 或者，我们也可以尝试使用我们刚刚渲染的r.html对象来使用BeautifulSoup。

Playwright-Python

还有一种选择是剧作家- Python，它是微软剧作家(本身是受木偶大师影响的浏览器自动化库)到Python的移植。

下面是选择一个元素并抓取它的文本的最小示例:

from playwright.sync_api import sync_playwright

with sync_playwright() as p:
    browser = p.chromium.launch()
    page = browser.new_page()
    page.goto("http://whatsmyuseragent.org/")
    ua = page.query_selector(".user-agent");
    print(ua.text_content())
    browser.close()

如前所述，Selenium是呈现JavaScript结果的好选择:

from selenium.webdriver import Firefox
from selenium.webdriver.firefox.options import Options

options = Options()
options.headless = True
browser = Firefox(executable_path="/usr/local/bin/geckodriver", options=options)

url = "https://www.example.com"
browser.get(url)

gazpacho是一个非常容易解析渲染html的库:

from gazpacho import Soup

soup = Soup(browser.page_source)
soup.find("a").attrs['href']

使用PyQt5

from PyQt5.QtWidgets import QApplication
from PyQt5.QtCore import QUrl
from PyQt5.QtWebEngineWidgets import QWebEnginePage
import sys
import bs4 as bs
import urllib.request


class Client(QWebEnginePage):
    def __init__(self,url):
        global app
        self.app = QApplication(sys.argv)
        QWebEnginePage.__init__(self)
        self.html = ""
        self.loadFinished.connect(self.on_load_finished)
        self.load(QUrl(url))
        self.app.exec_()

    def on_load_finished(self):
        self.html = self.toHtml(self.Callable)
        print("Load Finished")

    def Callable(self,data):
        self.html = data
        self.app.quit()

# url = ""
# client_response = Client(url)
# print(client_response.html)

你也可以使用webdriver执行javascript。

from selenium import webdriver

driver = webdriver.Firefox()
driver.get(url)
driver.execute_script('document.title')

或者将值存储在变量中

result = driver.execute_script('var text = document.title ; return text')

我们没有得到正确的结果，因为任何javascript生成的内容都需要在DOM上呈现。当我们获取一个HTML页面时，我们获取初始的，未经javascript修改的DOM。

因此，我们需要在抓取页面之前呈现javascript内容。

由于selenium已经在本线程中多次提到(有时也提到了它的速度有多慢)，我将列出其他两种可能的解决方案。

解决方案1:这是一个关于如何使用Scrapy抓取javascript生成内容的非常好的教程，我们将遵循这一点。

我们需要:

Docker installed in our machine. This is a plus over other solutions until this point, as it utilizes an OS-independent platform. Install Splash following the instruction listed for our corresponding OS.Quoting from splash documentation: Splash is a javascript rendering service. It’s a lightweight web browser with an HTTP API, implemented in Python 3 using Twisted and QT5. Essentially we are going to use Splash to render Javascript generated content. Run the splash server: sudo docker run -p 8050:8050 scrapinghub/splash. Install the scrapy-splash plugin: pip install scrapy-splash Assuming that we already have a Scrapy project created (if not, let's make one), we will follow the guide and update the settings.py: Then go to your scrapy project’s settings.py and set these middlewares: DOWNLOADER_MIDDLEWARES = { 'scrapy_splash.SplashCookiesMiddleware': 723, 'scrapy_splash.SplashMiddleware': 725, 'scrapy.downloadermiddlewares.httpcompression.HttpCompressionMiddleware': 810, } The URL of the Splash server(if you’re using Win or OSX this should be the URL of the docker machine: How to get a Docker container's IP address from the host?): SPLASH_URL = 'http://localhost:8050' And finally you need to set these values too: DUPEFILTER_CLASS = 'scrapy_splash.SplashAwareDupeFilter' HTTPCACHE_STORAGE = 'scrapy_splash.SplashAwareFSCacheStorage' Finally, we can use a SplashRequest: In a normal spider you have Request objects which you can use to open URLs. If the page you want to open contains JS generated data you have to use SplashRequest(or SplashFormRequest) to render the page. Here’s a simple example: class MySpider(scrapy.Spider): name = "jsscraper" start_urls = ["http://quotes.toscrape.com/js/"] def start_requests(self): for url in self.start_urls: yield SplashRequest( url=url, callback=self.parse, endpoint='render.html' ) def parse(self, response): for q in response.css("div.quote"): quote = QuoteItem() quote["author"] = q.css(".author::text").extract_first() quote["quote"] = q.css(".text::text").extract_first() yield quote SplashRequest renders the URL as html and returns the response which you can use in the callback(parse) method.

解决方案2:我们暂且称之为实验性的(2018年5月)…… 此解决方案仅适用于Python版本3.6(目前)。

你知道请求模块吗(谁不知道呢)? 现在它有了一个网络爬行的小兄弟:requests-HTML:

这个库旨在使解析HTML(例如抓取网页)尽可能简单和直观。

安装请求-html: pipenv 对页面的url进行请求: 导入HTMLSession 会话= HTMLSession() R = session.get(a_page_url) 渲染响应以获得Javascript生成的比特: r.html.render ()

最后，该模块似乎提供了抓取功能。 或者，我们也可以尝试使用我们刚刚渲染的r.html对象来使用BeautifulSoup。