我们没有得到正确的结果，因为任何javascript生成的内容都需要在DOM上呈现。当我们获取一个HTML页面时，我们获取初始的，未经javascript修改的DOM。

因此，我们需要在抓取页面之前呈现javascript内容。

由于selenium已经在本线程中多次提到(有时也提到了它的速度有多慢)，我将列出其他两种可能的解决方案。

解决方案1:这是一个关于如何使用Scrapy抓取javascript生成内容的非常好的教程，我们将遵循这一点。

我们需要:

Docker installed in our machine. This is a plus over other solutions until this point, as it utilizes an OS-independent platform. Install Splash following the instruction listed for our corresponding OS.Quoting from splash documentation: Splash is a javascript rendering service. It’s a lightweight web browser with an HTTP API, implemented in Python 3 using Twisted and QT5. Essentially we are going to use Splash to render Javascript generated content. Run the splash server: sudo docker run -p 8050:8050 scrapinghub/splash. Install the scrapy-splash plugin: pip install scrapy-splash Assuming that we already have a Scrapy project created (if not, let's make one), we will follow the guide and update the settings.py: Then go to your scrapy project’s settings.py and set these middlewares: DOWNLOADER_MIDDLEWARES = { 'scrapy_splash.SplashCookiesMiddleware': 723, 'scrapy_splash.SplashMiddleware': 725, 'scrapy.downloadermiddlewares.httpcompression.HttpCompressionMiddleware': 810, } The URL of the Splash server(if you’re using Win or OSX this should be the URL of the docker machine: How to get a Docker container's IP address from the host?): SPLASH_URL = 'http://localhost:8050' And finally you need to set these values too: DUPEFILTER_CLASS = 'scrapy_splash.SplashAwareDupeFilter' HTTPCACHE_STORAGE = 'scrapy_splash.SplashAwareFSCacheStorage' Finally, we can use a SplashRequest: In a normal spider you have Request objects which you can use to open URLs. If the page you want to open contains JS generated data you have to use SplashRequest(or SplashFormRequest) to render the page. Here’s a simple example: class MySpider(scrapy.Spider): name = "jsscraper" start_urls = ["http://quotes.toscrape.com/js/"] def start_requests(self): for url in self.start_urls: yield SplashRequest( url=url, callback=self.parse, endpoint='render.html' ) def parse(self, response): for q in response.css("div.quote"): quote = QuoteItem() quote["author"] = q.css(".author::text").extract_first() quote["quote"] = q.css(".text::text").extract_first() yield quote SplashRequest renders the URL as html and returns the response which you can use in the callback(parse) method.

解决方案2:我们暂且称之为实验性的(2018年5月)…… 此解决方案仅适用于Python版本3.6(目前)。

你知道请求模块吗(谁不知道呢)? 现在它有了一个网络爬行的小兄弟:requests-HTML:

这个库旨在使解析HTML(例如抓取网页)尽可能简单和直观。

安装请求-html: pipenv 对页面的url进行请求: 导入HTMLSession 会话= HTMLSession() R = session.get(a_page_url) 渲染响应以获得Javascript生成的比特: r.html.render ()

最后，该模块似乎提供了抓取功能。 或者，我们也可以尝试使用我们刚刚渲染的r.html对象来使用BeautifulSoup。

把BeautifulSoup和Selenium混合在一起对我来说效果很好。

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from bs4 import BeautifulSoup as bs

driver = webdriver.Firefox()
driver.get("http://somedomain/url_that_delays_loading")
    try:
        element = WebDriverWait(driver, 10).until(
        EC.presence_of_element_located((By.ID, "myDynamicElement"))) #waits 10 seconds until element is located. Can have other wait conditions  such as visibility_of_element_located or text_to_be_present_in_element

        html = driver.page_source
        soup = bs(html, "lxml")
        dynamic_text = soup.find_all("p", {"class":"class_name"}) #or other attributes, optional
    else:
        print("Couldnt locate element")

附注:你可以在这里找到更多的等待条件

听起来好像你真正要找的数据可以通过主页面上的一些javascript调用的辅助URL访问。

虽然您可以尝试在服务器上运行javascript来处理这个问题，但一种更简单的方法可能是使用Firefox加载页面，并使用Charles或Firebug之类的工具来准确识别辅助URL。然后，您可以直接查询该URL以获得您感兴趣的数据。

如前所述，Selenium是呈现JavaScript结果的好选择:

from selenium.webdriver import Firefox
from selenium.webdriver.firefox.options import Options

options = Options()
options.headless = True
browser = Firefox(executable_path="/usr/local/bin/geckodriver", options=options)

url = "https://www.example.com"
browser.get(url)

gazpacho是一个非常容易解析渲染html的库:

from gazpacho import Soup

soup = Soup(browser.page_source)
soup.find("a").attrs['href']

You'll want to use urllib, requests, beautifulSoup and selenium web driver in your script for different parts of the page, (to name a few). Sometimes you'll get what you need with just one of these modules. Sometimes you'll need two, three, or all of these modules. Sometimes you'll need to switch off the js on your browser. Sometimes you'll need header info in your script. No websites can be scraped the same way and no website can be scraped in the same way forever without having to modify your crawler, usually after a few months. But they can all be scraped! Where there's a will there's a way for sure. If you need scraped data continuously into the future just scrape everything you need and store it in .dat files with pickle. Just keep searching how to try what with these modules and copying and pasting your errors into the Google.

也许硒可以做到。

from selenium import webdriver
import time

driver = webdriver.Firefox()
driver.get(url)
time.sleep(5)
htmlSource = driver.page_source