我目前正在用Xcode 6 (Beta 6)测试我的应用程序。UIActivityViewController在iPhone设备和模拟器上工作得很好，但在iPad模拟器和设备(iOS 8)上崩溃
Terminating app due to uncaught exception 'NSGenericException',
reason: 'UIPopoverPresentationController
(<_UIAlertControllerActionSheetRegularPresentationController: 0x7fc7a874bd90>)
should have a non-nil sourceView or barButtonItem set before the presentation occurs.
我使用以下代码用于iPhone和iPad的iOS 7以及iOS 8
NSData *myData = [NSData dataWithContentsOfFile:_filename];
NSArray *activityItems = [NSArray arrayWithObjects:myData, nil];
UIActivityViewController *activityViewController = [[UIActivityViewController alloc] initWithActivityItems:nil applicationActivities:nil];
activityViewController.excludedActivityTypes = @[UIActivityTypeCopyToPasteboard];
[self presentViewController:activityViewController animated:YES completion:nil];
我得到一个类似的崩溃在我的另一个应用程序以及。你能引导我吗?ios8中的UIActivityViewController有什么变化吗?我查过了，但在这上面什么也没找到
SwiftUI版本
func presentActivityView(items: [Any]){
let activityController = UIActivityViewController(activityItems: items, applicationActivities: nil)
if UIDevice.current.userInterfaceIdiom == .pad{
activityController.popoverPresentationController?.sourceView = UIApplication.shared.windows.first
activityController.popoverPresentationController?.sourceRect = CGRect(x: UIScreen.main.bounds.width / 3, y: UIScreen.main.bounds.height / 1.5, width: 400, height: 400)
}
UIApplication.shared.windows.first?.rootViewController?.present(activityController, animated: true, completion: nil)
}
如果你在点击UIBarButtonItem时显示UIActivityViewController，请使用以下代码:
activityViewController.popoverPresentationController?.barButtonItem = sender
否则，如果你使用另一个控件，例如UIButton，使用以下代码:
activityViewController.popoverPresentationController?.sourceView = sender
activityViewController.popoverPresentationController?.sourceRect = sender.bounds
从文档到UIPopoverPresentationController:
var barButtonItem: UIBarButtonItem? { get set }
为此属性分配一个值，以将弹出窗口锚定到指定的栏按钮项。显示时，弹出窗口的箭头指向指定的项。或者，您可以使用sourceView和sourceRect属性为弹出窗口指定锚点位置。
对于Swift 2.0。我发现，如果你试图将弹出窗口锚定在iPad上的共享按钮上，这种方法是有效的。这假设您已经在工具栏中为共享按钮创建了一个出口。
func share(sender: AnyObject) {
let firstActivityItem = "test"
let activityViewController = UIActivityViewController(activityItems: [firstActivityItem], applicationActivities: nil)
if UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone {
self.presentViewController(activityViewController, animated: true, completion: nil)
}
else {
if activityViewController.respondsToSelector("popoverPresentationController") {
activityViewController.popoverPresentationController!.barButtonItem = sender as? UIBarButtonItem
self.presentViewController(activityViewController, animated: true, completion: nil)
}
}
}
SwiftUI版本
func presentActivityView(items: [Any]){
let activityController = UIActivityViewController(activityItems: items, applicationActivities: nil)
if UIDevice.current.userInterfaceIdiom == .pad{
activityController.popoverPresentationController?.sourceView = UIApplication.shared.windows.first
activityController.popoverPresentationController?.sourceRect = CGRect(x: UIScreen.main.bounds.width / 3, y: UIScreen.main.bounds.height / 1.5, width: 400, height: 400)
}
UIApplication.shared.windows.first?.rootViewController?.present(activityController, animated: true, completion: nil)
}
我看到很多人在使用Swift代码时对iPhone/iPad等进行硬编码。
这是不需要的，你必须使用语言功能。下面的代码假设你将使用一个UIBarButtonItem，并将在iPhone和iPad上工作。
@IBAction func share(sender: AnyObject) {
let vc = UIActivityViewController(activityItems: ["hello"], applicationActivities: nil)
vc.popoverPresentationController?.barButtonItem = sender as? UIBarButtonItem
self.presentViewController(vc, animated: true, completion: nil)
}
注意这里没有If语句或其他疯狂的东西。可选的展开在iPhone上将是nil，所以行vc。popoverpresentationcontroller ?在iphone上没有任何功能。
