我目前正在用Xcode 6 (Beta 6)测试我的应用程序。UIActivityViewController在iPhone设备和模拟器上工作得很好，但在iPad模拟器和设备(iOS 8)上崩溃
Terminating app due to uncaught exception 'NSGenericException',
reason: 'UIPopoverPresentationController
(<_UIAlertControllerActionSheetRegularPresentationController: 0x7fc7a874bd90>)
should have a non-nil sourceView or barButtonItem set before the presentation occurs.
我使用以下代码用于iPhone和iPad的iOS 7以及iOS 8
NSData *myData = [NSData dataWithContentsOfFile:_filename];
NSArray *activityItems = [NSArray arrayWithObjects:myData, nil];
UIActivityViewController *activityViewController = [[UIActivityViewController alloc] initWithActivityItems:nil applicationActivities:nil];
activityViewController.excludedActivityTypes = @[UIActivityTypeCopyToPasteboard];
[self presentViewController:activityViewController animated:YES completion:nil];
我得到一个类似的崩溃在我的另一个应用程序以及。你能引导我吗?ios8中的UIActivityViewController有什么变化吗?我查过了，但在这上面什么也没找到
对于Swift 2.0。我发现，如果你试图将弹出窗口锚定在iPad上的共享按钮上，这种方法是有效的。这假设您已经在工具栏中为共享按钮创建了一个出口。
func share(sender: AnyObject) {
let firstActivityItem = "test"
let activityViewController = UIActivityViewController(activityItems: [firstActivityItem], applicationActivities: nil)
if UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone {
self.presentViewController(activityViewController, animated: true, completion: nil)
}
else {
if activityViewController.respondsToSelector("popoverPresentationController") {
activityViewController.popoverPresentationController!.barButtonItem = sender as? UIBarButtonItem
self.presentViewController(activityViewController, animated: true, completion: nil)
}
}
}
迅速:
let activityViewController = UIActivityViewController(activityItems: sharingItems, applicationActivities: nil)
//if iPhone
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone) {
self.presentViewController(activityViewController, animated: true, completion: nil)
} else { //if iPad
// Change Rect to position Popover
var popoverCntlr = UIPopoverController(contentViewController: activityViewController)
popoverCntlr.presentPopoverFromRect(CGRectMake(self.view.frame.size.width/2, self.view.frame.size.height/4, 0, 0), inView: self.view, permittedArrowDirections: UIPopoverArrowDirection.Any, animated: true)
}
在swift 4下面的代码工作在iphone和ipad。
根据文档
对于给定的设备习惯用法，使用适当的方法来呈现和解散视图控制器是你的责任。在iPad上，你必须在弹出窗口中显示视图控制器。在其他设备上，你必须以模态方式呈现它。
let activityViewController = UIActivityViewController(activityItems: activityitems, applicationActivities: nil)
if UIDevice.current.userInterfaceIdiom == .pad {
if activityViewController.responds(to: #selector(getter: UIViewController.popoverPresentationController)) {
activityViewController.popoverPresentationController?.sourceView = self.view
}
}
self.present(activityViewController, animated: true, completion: nil)
对于Swift 2.0。我发现，如果你试图将弹出窗口锚定在iPad上的共享按钮上，这种方法是有效的。这假设您已经在工具栏中为共享按钮创建了一个出口。
func share(sender: AnyObject) {
let firstActivityItem = "test"
let activityViewController = UIActivityViewController(activityItems: [firstActivityItem], applicationActivities: nil)
if UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone {
self.presentViewController(activityViewController, animated: true, completion: nil)
}
else {
if activityViewController.respondsToSelector("popoverPresentationController") {
activityViewController.popoverPresentationController!.barButtonItem = sender as? UIBarButtonItem
self.presentViewController(activityViewController, animated: true, completion: nil)
}
}
}
在Swift修复这个iPad，最好的方法是这样做，我发现。
let things = ["Things to share"]
let avc = UIActivityViewController(activityItems:things, applicationActivities:nil)
avc.setValue("Subject title", forKey: "subject")
avc.completionWithItemsHandler = {
(s: String!, ok: Bool, items: [AnyObject]!, err:NSError!) -> Void in
}
self.presentViewController(avc, animated:true, completion:nil)
if let pop = avc.popoverPresentationController {
let v = sender as! UIView // sender would be the button view tapped, but could be any view
pop.sourceView = v
pop.sourceRect = v.bounds
}
