我目前正在用Xcode 6 (Beta 6)测试我的应用程序。UIActivityViewController在iPhone设备和模拟器上工作得很好,但在iPad模拟器和设备(iOS 8)上崩溃

Terminating app due to uncaught exception 'NSGenericException', 
reason: 'UIPopoverPresentationController 
(<_UIAlertControllerActionSheetRegularPresentationController: 0x7fc7a874bd90>) 
should have a non-nil sourceView or barButtonItem set before the presentation occurs.

我使用以下代码用于iPhone和iPad的iOS 7以及iOS 8

NSData *myData = [NSData dataWithContentsOfFile:_filename];
NSArray *activityItems = [NSArray arrayWithObjects:myData, nil];
UIActivityViewController *activityViewController = [[UIActivityViewController alloc] initWithActivityItems:nil applicationActivities:nil];
activityViewController.excludedActivityTypes = @[UIActivityTypeCopyToPasteboard];
[self presentViewController:activityViewController animated:YES completion:nil];

我得到一个类似的崩溃在我的另一个应用程序以及。你能引导我吗?ios8中的UIActivityViewController有什么变化吗?我查过了,但在这上面什么也没找到


当前回答

对于Swift 2.0。我发现,如果你试图将弹出窗口锚定在iPad上的共享按钮上,这种方法是有效的。这假设您已经在工具栏中为共享按钮创建了一个出口。

func share(sender: AnyObject) {
    let firstActivityItem = "test"

    let activityViewController = UIActivityViewController(activityItems: [firstActivityItem], applicationActivities: nil)

    if UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone {
        self.presentViewController(activityViewController, animated: true, completion: nil)
    }
    else {            
        if activityViewController.respondsToSelector("popoverPresentationController") {
            activityViewController.popoverPresentationController!.barButtonItem = sender as? UIBarButtonItem
            self.presentViewController(activityViewController, animated: true, completion: nil)
        }

    }
}

其他回答

斯威夫特3:

class func openShareActions(image: UIImage, vc: UIViewController) {
    let activityVC = UIActivityViewController(activityItems: [image], applicationActivities: nil)
    if UIDevice.current.userInterfaceIdiom == .pad {
        if activityVC.responds(to: #selector(getter: UIViewController.popoverPresentationController)) {
            activityVC.popoverPresentationController?.sourceView = vc.view
        }
    }
    vc.present(activityVC, animated: true, completion: nil)
}

在Swift修复这个iPad,最好的方法是这样做,我发现。

    let things = ["Things to share"]
    let avc = UIActivityViewController(activityItems:things, applicationActivities:nil)
    avc.setValue("Subject title", forKey: "subject")
    avc.completionWithItemsHandler = {
        (s: String!, ok: Bool, items: [AnyObject]!, err:NSError!) -> Void in
    }

    self.presentViewController(avc, animated:true, completion:nil)
    if let pop = avc.popoverPresentationController {
        let v = sender as! UIView // sender would be the button view tapped, but could be any view
        pop.sourceView = v
        pop.sourceRect = v.bounds
    }

我使用Swift 5。 当我在iPad上的应用程序中点击“分享按钮”时,我也遇到了同样的问题。找到了这个解。 步骤1:将“view”对象(在对象库中搜索“UIView”)添加到Main.storyboard。 步骤2:在ViewController.swift中创建一个@IBOutlet并分配任意名称(例如:view1)

步骤3:添加上述名称(例如:view1)作为sourceView。这是我的“分享按钮”动作。

@IBAction func Share(_ sender: Any) {
    let activityVC = UIActivityViewController(activityItems: ["www.google.com"], applicationActivities: nil)
    activityVC.popoverPresentationController?.sourceView = view1

    self.present(activityVC, animated: true, completion: nil)


}

我对swift很陌生,在这个问题上耽搁了一个星期。希望这能帮助到一些人。分享这个解。

如果你是在iPad上使用swift进行开发,那么你就得小心了,它在调试时可以正常工作,但在发布时就会崩溃。为了让它与testFlight和AppStore一起工作,禁用swift的优化,使用-none进行发布。

SwiftUI版本

func presentActivityView(items: [Any]){
    let activityController = UIActivityViewController(activityItems: items, applicationActivities: nil)
    if UIDevice.current.userInterfaceIdiom == .pad{
        activityController.popoverPresentationController?.sourceView = UIApplication.shared.windows.first
        activityController.popoverPresentationController?.sourceRect = CGRect(x:  UIScreen.main.bounds.width / 3, y:  UIScreen.main.bounds.height / 1.5, width: 400, height: 400)
    }
    UIApplication.shared.windows.first?.rootViewController?.present(activityController, animated: true, completion: nil)
}