我目前正在用Xcode 6 (Beta 6)测试我的应用程序。UIActivityViewController在iPhone设备和模拟器上工作得很好,但在iPad模拟器和设备(iOS 8)上崩溃

Terminating app due to uncaught exception 'NSGenericException', 
reason: 'UIPopoverPresentationController 
(<_UIAlertControllerActionSheetRegularPresentationController: 0x7fc7a874bd90>) 
should have a non-nil sourceView or barButtonItem set before the presentation occurs.

我使用以下代码用于iPhone和iPad的iOS 7以及iOS 8

NSData *myData = [NSData dataWithContentsOfFile:_filename];
NSArray *activityItems = [NSArray arrayWithObjects:myData, nil];
UIActivityViewController *activityViewController = [[UIActivityViewController alloc] initWithActivityItems:nil applicationActivities:nil];
activityViewController.excludedActivityTypes = @[UIActivityTypeCopyToPasteboard];
[self presentViewController:activityViewController animated:YES completion:nil];

我得到一个类似的崩溃在我的另一个应用程序以及。你能引导我吗?ios8中的UIActivityViewController有什么变化吗?我查过了,但在这上面什么也没找到


当前回答

斯威夫特3:

class func openShareActions(image: UIImage, vc: UIViewController) {
    let activityVC = UIActivityViewController(activityItems: [image], applicationActivities: nil)
    if UIDevice.current.userInterfaceIdiom == .pad {
        if activityVC.responds(to: #selector(getter: UIViewController.popoverPresentationController)) {
            activityVC.popoverPresentationController?.sourceView = vc.view
        }
    }
    vc.present(activityVC, animated: true, completion: nil)
}

其他回答

我使用Swift 5。 当我在iPad上的应用程序中点击“分享按钮”时,我也遇到了同样的问题。找到了这个解。 步骤1:将“view”对象(在对象库中搜索“UIView”)添加到Main.storyboard。 步骤2:在ViewController.swift中创建一个@IBOutlet并分配任意名称(例如:view1)

步骤3:添加上述名称(例如:view1)作为sourceView。这是我的“分享按钮”动作。

@IBAction func Share(_ sender: Any) {
    let activityVC = UIActivityViewController(activityItems: ["www.google.com"], applicationActivities: nil)
    activityVC.popoverPresentationController?.sourceView = view1

    self.present(activityVC, animated: true, completion: nil)


}

我对swift很陌生,在这个问题上耽搁了一个星期。希望这能帮助到一些人。分享这个解。

Swift = ios7/ ios8

let activityViewController = UIActivityViewController(activityItems: sharingItems, applicationActivities: nil)

//if iPhone
if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone) {
    // go on..
} else {
    //if iPad
    if activityViewController.respondsToSelector(Selector("popoverPresentationController")) {
        // on iOS8
        activityViewController.popoverPresentationController!.barButtonItem = self.shareButtonItem;
    }
}
self.presentViewController(activityViewController, animated: true, completion: nil)

修复了Swift 2.0

    if UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiom.Phone {
        self.presentViewController(activityVC, animated: true, completion: nil)
    }
    else {
        let popup: UIPopoverController = UIPopoverController(contentViewController: activityVC)
        popup.presentPopoverFromRect(CGRectMake(self.view.frame.size.width / 2, self.view.frame.size.height / 4, 0, 0), inView: self.view, permittedArrowDirections: UIPopoverArrowDirection.Any, animated: true)
    }

斯威夫特3:

class func openShareActions(image: UIImage, vc: UIViewController) {
    let activityVC = UIActivityViewController(activityItems: [image], applicationActivities: nil)
    if UIDevice.current.userInterfaceIdiom == .pad {
        if activityVC.responds(to: #selector(getter: UIViewController.popoverPresentationController)) {
            activityVC.popoverPresentationController?.sourceView = vc.view
        }
    }
    vc.present(activityVC, animated: true, completion: nil)
}

在iPad上,活动视图控制器将显示为一个弹出窗口使用新的UIPopoverPresentationController,它要求你指定一个锚点为弹出窗口的表示使用以下三个属性之一:

栏按钮项 源视图 源矩形

为了指定锚点,你需要获得UIActivityController的UIPopoverPresentationController的引用,并设置其中一个属性如下所示:

if ( [activityViewController respondsToSelector:@selector(popoverPresentationController)] ) { 
// iOS8
 activityViewController.popoverPresentationController.sourceView =
parentView;
 }