经过两天的努力，我找到了解决问题的办法。您可以使用ObjectFactory类来解决没有@XmlRootElement的类。ObjectFactory重载了一些方法来将其包装在JAXBElement周围。

方法:1简单地创建对象。

方法:2将使用@JAXBElement包装对象。

总是使用Method:2来避免javax.xml.bind.MarshalException -与链接异常缺少@XmlRootElement注释。

请查看下面的示例代码

方法:1简单地创建对象

public GetCountry createGetCountry() {
        return new GetCountry();
    }

方法:2将使用@JAXBElement包装对象。

 @XmlElementDecl(namespace = "my/name/space", name = "getCountry")
 public JAXBElement<GetCountry> createGetCountry(GetCountry value) {
        return new JAXBElement<GetCountry>(_GetCountry_QNAME, GetCountry.class, null, value);
    }

工作代码示例:

ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");
WebServiceTemplate springWSTemplate = context.getBean(WebServiceTemplate.class);

GetCountry request = new GetCountry();
request.setGuid("test_guid");

JAXBElement<GetCountryResponse> jaxbResponse = (JAXBElement<GetCountryResponse>)springWSTemplate .marshalSendAndReceive(new ObjectFactory().createGetCountry(request));

GetCountryResponse response = jaxbResponse.getValue();

Joe's answer (Joe Jun 26 '09 at 17:26) does it for me. The simple answer is that absence of an @XmlRootElement annotation is no problem if you marshal a JAXBElement. The thing that confused me is the generated ObjectFactory has 2 createMyRootElement methods - the first takes no parameters and gives the unwrapped object, the second takes the unwrapped object and returns it wrapped in a JAXBElement, and marshalling that JAXBElement works fine. Here's the basic code I used (I'm new to this, so apologies if the code's not formatted correctly in this reply), largely cribbed from link text:

ObjectFactory objFactory = new ObjectFactory();
MyRootElement root = objFactory.createMyRootElement();
...
// Set root properties
...
if (!writeDocument(objFactory.createMyRootElement(root), output)) {
    System.err.println("Failed to marshal XML document");
}
...

private boolean writeDocument(JAXBElement document, OutputStream output) {

  Class<?> clazz = document.getValue().getClass();
  try {
    JAXBContext context =
        JAXBContext.newInstance(clazz.getPackage().getName());
    Marshaller m = context.createMarshaller();
    m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
    m.marshal(document, output);
    return true;

  } catch (JAXBException e) {
    e.printStackTrace(System.err);
    return false;
  }
}

为了解决这个问题，你应该在使用wsimport编译之前配置一个xml绑定，将generateElementProperty设置为false。

     <jaxws:bindings wsdlLocation="LOCATION_OF_WSDL"
      xmlns:jaxws="http://java.sun.com/xml/ns/jaxws"
      xmlns:xjc="http://java.sun.com/xml/ns/jaxb/xjc" 
      xmlns:xs="http://www.w3.org/2001/XMLSchema"
      xmlns:jxb="http://java.sun.com/xml/ns/jaxb"
      xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/">
         <jaxws:enableWrapperStyle>false</jaxws:enableWrapperStyle>
    <jaxws:bindings  node="wsdl:definitions/wsdl:types/xs:schema[@targetNamespace='NAMESPACE_OF_WSDL']">
      <jxb:globalBindings xmlns:jxb="http://java.sun.com/xml/ns/jaxb" xmlns:xs="http://www.w3.org/2001/XMLSchema">
            <xjc:generateElementProperty>false</xjc:generateElementProperty> 
      </jxb:globalBindings>
  </jaxws:bindings>
</jaxws:bindings>

正如上面的答案之一所暗示的，如果在XSD中根元素的类型定义为命名类型，则根元素上不会有XMLRootElement，因为该命名类型可以在XSD中的其他地方使用。尝试将其转换为匿名类型，即:

<xsd:element name="myRootElement" type="MyRootElementType" />

<xsd:complexType name="MyRootElementType">
...
</xsd:complexType>

你会:

<xsd:element name="myRootElement">
    <xsd:complexType>
    ...
    <xsd:complexType>
</xsd:element>

这对我们也没用。但我们确实找到了一篇被广泛引用的文章，增加了一些背景……我将在这里链接到它，以方便下一个人:http://weblogs.java.net/blog/kohsuke/archive/2006/03/why_does_jaxb_p.html

上面已经链接的博客文章底部提到了这一点，但这对我来说就像一种享受:

Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
marshaller.marshal(new JAXBElement<MyClass>(new QName("uri","local"), MyClass.class, myClassInstance), System.out);