经过两天的努力，我找到了解决问题的办法。您可以使用ObjectFactory类来解决没有@XmlRootElement的类。ObjectFactory重载了一些方法来将其包装在JAXBElement周围。

方法:1简单地创建对象。

方法:2将使用@JAXBElement包装对象。

总是使用Method:2来避免javax.xml.bind.MarshalException -与链接异常缺少@XmlRootElement注释。

请查看下面的示例代码

方法:1简单地创建对象

public GetCountry createGetCountry() {
        return new GetCountry();
    }

方法:2将使用@JAXBElement包装对象。

 @XmlElementDecl(namespace = "my/name/space", name = "getCountry")
 public JAXBElement<GetCountry> createGetCountry(GetCountry value) {
        return new JAXBElement<GetCountry>(_GetCountry_QNAME, GetCountry.class, null, value);
    }

工作代码示例:

ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");
WebServiceTemplate springWSTemplate = context.getBean(WebServiceTemplate.class);

GetCountry request = new GetCountry();
request.setGuid("test_guid");

JAXBElement<GetCountryResponse> jaxbResponse = (JAXBElement<GetCountryResponse>)springWSTemplate .marshalSendAndReceive(new ObjectFactory().createGetCountry(request));

GetCountryResponse response = jaxbResponse.getValue();

如您所知，答案是使用ObjectFactory()。下面是一个为我工作的代码示例:)

ObjectFactory myRootFactory = new ObjectFactory();

MyRootType myRootType = myRootFactory.createMyRootType();

try {

        File file = new File("./file.xml");
        JAXBContext jaxbContext = JAXBContext.newInstance(MyRoot.class);
        Marshaller jaxbMarshaller = jaxbContext.createMarshaller();

        //output pretty printed
        jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

        JABXElement<MyRootType> myRootElement = myRootFactory.createMyRoot(myRootType);

        jaxbMarshaller.marshal(myRootElement, file);
        jaxbMarshaller.marshal(myRootElement, System.out);

    } catch (JAXBException e) {
        e.printStackTrace();
    }

JAXBElement包装器适用于JAXB没有生成@XmlRootElement的情况。这些包装器在maven-jaxb2-plugin生成的ObjectFactory类中可用。如:

     public class HelloWorldEndpoint {
        @PayloadRoot(namespace = NAMESPACE_URI, localPart = "person")
        @ResponsePayload
        public JAXBElement<Greeting> sayHello(@RequestPayload JAXBElement<Person> request) {

        Person person = request.getValue();

        String greeting = "Hello " + person.getFirstName() + " " + person.getLastName() + "!";

        Greeting greet = new Greeting();
        greet.setGreeting(greeting);

        ObjectFactory factory = new ObjectFactory();
        JAXBElement<Greeting> response = factory.createGreeting(greet);
        return response;
      }
 }

这个主题相当古老，但在企业业务上下文中仍然相关。我尽量避免接触xsds，以便将来可以轻松地更新它们。以下是我的解决方案。

1. 通常xjc:简单就足够了

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<jxb:bindings version="2.0" xmlns:jxb="http://java.sun.com/xml/ns/jaxb"
    xmlns:xjc="http://java.sun.com/xml/ns/jaxb/xjc"
    jxb:extensionBindingPrefixes="xjc">

    <jxb:globalBindings>
        <xjc:simple/> <!-- adds @XmlRootElement annotations -->
    </jxb:globalBindings>

</jxb:bindings>

它将主要创建用于导入xsd定义的XmlRootElements。

2. 划分您的jaxb2-maven-plugin执行

我曾遇到过，如果尝试从多个xsd定义生成类，而不是每个xsd生成一个执行定义，结果会有很大的不同。

因此，如果你有一个定义有多个<source>，那么只需要尝试拆分它们:

          <execution>
            <id>xjc-schema-1</id>
            <goals>
              <goal>xjc</goal>
            </goals>
            <configuration>
              <xjbSources>
                <xjbSource>src/main/resources/xsd/binding.xjb</xjbSource>
              </xjbSources>
              <sources>
                <source>src/main/resources/xsd/definition1/</source>
              </sources>
              <clearOutputDir>false</clearOutputDir>
            </configuration>
          </execution>

          <execution>
            <id>xjc-schema-2</id>
            <goals>
              <goal>xjc</goal>
            </goals>
            <configuration>
              <xjbSources>
                <xjbSource>src/main/resources/xsd/binding.xjb</xjbSource>
              </xjbSources>
              <sources>
                <source>src/main/resources/xsd/definition2/</source>
              </sources>
              <clearOutputDir>false</clearOutputDir>
            </configuration>
          </execution>

生成器不会捕捉到一个类可能就足够了的事实，因此每次执行都会创建自定义类。这正是我所需要的。

Joe's answer (Joe Jun 26 '09 at 17:26) does it for me. The simple answer is that absence of an @XmlRootElement annotation is no problem if you marshal a JAXBElement. The thing that confused me is the generated ObjectFactory has 2 createMyRootElement methods - the first takes no parameters and gives the unwrapped object, the second takes the unwrapped object and returns it wrapped in a JAXBElement, and marshalling that JAXBElement works fine. Here's the basic code I used (I'm new to this, so apologies if the code's not formatted correctly in this reply), largely cribbed from link text:

ObjectFactory objFactory = new ObjectFactory();
MyRootElement root = objFactory.createMyRootElement();
...
// Set root properties
...
if (!writeDocument(objFactory.createMyRootElement(root), output)) {
    System.err.println("Failed to marshal XML document");
}
...

private boolean writeDocument(JAXBElement document, OutputStream output) {

  Class<?> clazz = document.getValue().getClass();
  try {
    JAXBContext context =
        JAXBContext.newInstance(clazz.getPackage().getName());
    Marshaller m = context.createMarshaller();
    m.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);
    m.marshal(document, output);
    return true;

  } catch (JAXBException e) {
    e.printStackTrace(System.err);
    return false;
  }
}

经过两天的努力，我找到了解决问题的办法。您可以使用ObjectFactory类来解决没有@XmlRootElement的类。ObjectFactory重载了一些方法来将其包装在JAXBElement周围。

方法:1简单地创建对象。

方法:2将使用@JAXBElement包装对象。

总是使用Method:2来避免javax.xml.bind.MarshalException -与链接异常缺少@XmlRootElement注释。

请查看下面的示例代码

方法:1简单地创建对象

public GetCountry createGetCountry() {
        return new GetCountry();
    }

方法:2将使用@JAXBElement包装对象。

 @XmlElementDecl(namespace = "my/name/space", name = "getCountry")
 public JAXBElement<GetCountry> createGetCountry(GetCountry value) {
        return new JAXBElement<GetCountry>(_GetCountry_QNAME, GetCountry.class, null, value);
    }

工作代码示例:

ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");
WebServiceTemplate springWSTemplate = context.getBean(WebServiceTemplate.class);

GetCountry request = new GetCountry();
request.setGuid("test_guid");

JAXBElement<GetCountryResponse> jaxbResponse = (JAXBElement<GetCountryResponse>)springWSTemplate .marshalSendAndReceive(new ObjectFactory().createGetCountry(request));

GetCountryResponse response = jaxbResponse.getValue();