我试图从FpML(金融产品标记语言)4.5版本生成Java类。生成了大量代码,但我无法使用它。试图序列化一个简单的文档,我得到这个:

javax.xml.bind.MarshalException
  - with linked exception: [com.sun.istack.SAXException2: unable
  to marshal type
  "org.fpml._2008.fpml_4_5.PositionReport"
  as an element because it is missing an
  @XmlRootElement annotation]

事实上,没有任何类具有@XmlRootElement注释,所以我可能做错了什么?我将xjc (JAXB 2.1)指向fpml-main-4-5。Xsd,然后包括所有类型。


当前回答

我只是在同一个问题上挣扎了一段时间,只是想发布我的最终结果,这对我来说很好。 所以基本问题是:

我必须从没有XmlRootElement注释的JAXB类实例生成xml字符串 这些类需要为编组过程绑定其他类

下面的类可以很好地解决这个问题:

public class Object2XmlConverter {

    public static <T> String convertToString(final T jaxbInstance, final Class<?>... additionalClasses)
            throws JAXBException {
        final Class<T> clazz = (Class<T>) jaxbInstance.getClass();

        final JAXBContext jaxbContext;
        if (additionalClasses.length > 0) {
            // this path is only necessary if you need additional classes to be bound
            jaxbContext = JAXBContext.newInstance(addClassesToBeBound(clazz, additionalClasses));
        } else {
            jaxbContext = JAXBContext.newInstance(clazz);
        }

        final QName qname = new QName("", jaxbInstance.getClass().getSimpleName());
        final JAXBElement<T> jaxbElement = new JAXBElement<T>(qname, clazz, null, jaxbInstance);

        final Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
        jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);

        final StringWriter stringWriter = new StringWriter();
        jaxbMarshaller.marshal(jaxbElement, stringWriter);
        return stringWriter.toString();
    }

    private static <T> Class<?>[] addClassesToBeBound(final Class<T> clazz, final Class<?>[] additionalClasses) {
        final Class<?>[] classArray = new Class<?>[additionalClasses.length + 1];
        for (int i = 0; i < additionalClasses.length; i++) {
            classArray[i] = additionalClasses[i];
        }
        classArray[classArray.length - 1] = clazz;
        return classArray;
    }

    public static void main(final String[] args) throws Exception {
        final Ns1TargetHeaderTyp dataTyp = ...;
        System.out.println(convertToString(dataTyp));
    }
}

其他回答

这对我们也没用。但我们确实找到了一篇被广泛引用的文章,增加了一些背景……我将在这里链接到它,以方便下一个人:http://weblogs.java.net/blog/kohsuke/archive/2006/03/why_does_jaxb_p.html

JAXBElement包装器适用于JAXB没有生成@XmlRootElement的情况。这些包装器在maven-jaxb2-plugin生成的ObjectFactory类中可用。如:

     public class HelloWorldEndpoint {
        @PayloadRoot(namespace = NAMESPACE_URI, localPart = "person")
        @ResponsePayload
        public JAXBElement<Greeting> sayHello(@RequestPayload JAXBElement<Person> request) {

        Person person = request.getValue();

        String greeting = "Hello " + person.getFirstName() + " " + person.getLastName() + "!";

        Greeting greet = new Greeting();
        greet.setGreeting(greeting);

        ObjectFactory factory = new ObjectFactory();
        JAXBElement<Greeting> response = factory.createGreeting(greet);
        return response;
      }
 }

经过两天的努力,我找到了解决问题的办法。您可以使用ObjectFactory类来解决没有@XmlRootElement的类。ObjectFactory重载了一些方法来将其包装在JAXBElement周围。

方法:1简单地创建对象。

方法:2将使用@JAXBElement包装对象。

总是使用Method:2来避免javax.xml.bind.MarshalException -与链接异常缺少@XmlRootElement注释。

请查看下面的示例代码

方法:1简单地创建对象

public GetCountry createGetCountry() {
        return new GetCountry();
    }

方法:2将使用@JAXBElement包装对象。

 @XmlElementDecl(namespace = "my/name/space", name = "getCountry")
 public JAXBElement<GetCountry> createGetCountry(GetCountry value) {
        return new JAXBElement<GetCountry>(_GetCountry_QNAME, GetCountry.class, null, value);
    }

工作代码示例:

ClassPathXmlApplicationContext context = new ClassPathXmlApplicationContext("applicationContext.xml");
WebServiceTemplate springWSTemplate = context.getBean(WebServiceTemplate.class);

GetCountry request = new GetCountry();
request.setGuid("test_guid");

JAXBElement<GetCountryResponse> jaxbResponse = (JAXBElement<GetCountryResponse>)springWSTemplate .marshalSendAndReceive(new ObjectFactory().createGetCountry(request));

GetCountryResponse response = jaxbResponse.getValue();

我只是在同一个问题上挣扎了一段时间,只是想发布我的最终结果,这对我来说很好。 所以基本问题是:

我必须从没有XmlRootElement注释的JAXB类实例生成xml字符串 这些类需要为编组过程绑定其他类

下面的类可以很好地解决这个问题:

public class Object2XmlConverter {

    public static <T> String convertToString(final T jaxbInstance, final Class<?>... additionalClasses)
            throws JAXBException {
        final Class<T> clazz = (Class<T>) jaxbInstance.getClass();

        final JAXBContext jaxbContext;
        if (additionalClasses.length > 0) {
            // this path is only necessary if you need additional classes to be bound
            jaxbContext = JAXBContext.newInstance(addClassesToBeBound(clazz, additionalClasses));
        } else {
            jaxbContext = JAXBContext.newInstance(clazz);
        }

        final QName qname = new QName("", jaxbInstance.getClass().getSimpleName());
        final JAXBElement<T> jaxbElement = new JAXBElement<T>(qname, clazz, null, jaxbInstance);

        final Marshaller jaxbMarshaller = jaxbContext.createMarshaller();
        jaxbMarshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, Boolean.TRUE);

        final StringWriter stringWriter = new StringWriter();
        jaxbMarshaller.marshal(jaxbElement, stringWriter);
        return stringWriter.toString();
    }

    private static <T> Class<?>[] addClassesToBeBound(final Class<T> clazz, final Class<?>[] additionalClasses) {
        final Class<?>[] classArray = new Class<?>[additionalClasses.length + 1];
        for (int i = 0; i < additionalClasses.length; i++) {
            classArray[i] = additionalClasses[i];
        }
        classArray[classArray.length - 1] = clazz;
        return classArray;
    }

    public static void main(final String[] args) throws Exception {
        final Ns1TargetHeaderTyp dataTyp = ...;
        System.out.println(convertToString(dataTyp));
    }
}

为了将其他人已经陈述或暗示的内容联系在一起,JAXB XJC决定是否将@XmlRootElement注释放在生成的类上的规则非常重要(请参阅本文)。

@XmlRootElement的存在是因为JAXB运行时需要某些信息才能封送/解封送给定对象,特别是XML元素名称和名称空间。你不能直接把任何旧对象传递给Marshaller。@XmlRootElement提供此信息。

然而,注释只是一种方便,JAXB并不需要它。另一种方法是使用JAXBElement包装器对象,它提供与@XmlRootElement相同的信息,但是以对象的形式,而不是注释的形式。

但是,JAXBElement对象构造起来很麻烦,因为您需要知道XML元素名称和名称空间,而业务逻辑通常不知道这些。

Thankfully, when XJC generates a class model, it also generates a class called ObjectFactory. This is partly there for backwards compatibility with JAXB v1, but it's also there as a place for XJC to put generated factory methods which create JAXBElement wrappers around your own objects. It handles the XML name and namespace for you, so you don't need to worry about it. You just need to look through the ObjectFactory methods (and for large schema, there can be hundreds of them) to find the one you need.