我用python计算出如果每7秒出生一个孩子5年内会有多少个孩子出生。问题在我的最后一行。我如何得到一个变量的工作时，我打印文本的任何一方?
这是我的代码:
currentPop = 312032486
oneYear = 365
hours = 24
minutes = 60
seconds = 60
# seconds in a single day
secondsInDay = hours * minutes * seconds
# seconds in a year
secondsInYear = secondsInDay * oneYear
fiveYears = secondsInYear * 5
#Seconds in 5 years
print fiveYears
# fiveYears in seconds, divided by 7 seconds
births = fiveYears // 7
print "If there was a birth every 7 seconds, there would be: " births "births"
当前回答
如果你想使用python 3，这很简单:
print("If there was a birth every 7 second, there would be %d births." % (births))
其他回答
在当前的python版本中，您必须使用括号，如下所示:
print ("If there was a birth every 7 seconds", X)
你可以使用格式化字符串:
print "There are %d births" % (births,)
或者在这个简单的例子中:
print "There are ", births, "births"
使用字符串格式
print("If there was a birth every 7 seconds, there would be: {} births".format(births))
# Will replace "{}" with births
如果你做一个玩具项目，使用:
print('If there was a birth every 7 seconds, there would be:' births'births)
or
print('If there was a birth every 7 seconds, there would be: %d births' %(births))
# Will replace %d with births
如果你使用的是python 3.6或最新版本， f弦是最好的，也是最简单的
print(f"{your_varaible_name}")
从Python-3.8开始，你可以使用带有变量名打印的f-string !
age = 19
vitality = 17
charisma = 16
name = "Alice"
print(f"{name=}, {age=}, {vitality=}, {charisma=}")
# name='Alice', age=19, vitality=17, charisma=16
命名错误在这里几乎是不可能的!如果您添加、重命名或删除一个变量，您的调试打印将保持正确 调试行非常简洁 不要担心对齐。第四个论点是魅力还是活力?好吧，你不在乎，不管它是正确的。
