你可以做的比下面的回答更简单:

Uri Selected_Image_Uri = data.getData();
ImageView imageView = (ImageView) findViewById(R.id.loadedimg);
imageView.setImageURI(Selected_Image_Uri);

我也有同样的问题，我用这个密码

addIntent

 Intent intent = new Intent();
        intent.setType("image/*");
        intent.setAction(Intent.ACTION_GET_CONTENT);
        startActivityForResult(Intent.createChooser(intent, "Tack Image"), PICK_PHOTO);

添加onActivityResult

 @Override
  public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == PICK_PHOTO && resultCode == Activity.RESULT_OK) {
      if (data == null) {
      //error
        return;
      }
      try {
        Uri uri = data.getData();
        File file = FileUtil.from(currentActivity, uri);
      } catch (IOException e) {
        e.printStackTrace();
      }
    }
  }

FileUtil类

import android.content.Context;
import android.database.Cursor;
import android.net.Uri;
import android.provider.OpenableColumns;
import android.util.Log;

import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;

public class FileUtil {
  private static final int EOF = -1;
  private static final int DEFAULT_BUFFER_SIZE = 1024 * 4;

  private FileUtil() {

  }

  public static File from(Context context, Uri uri) throws IOException {
    InputStream inputStream = context.getContentResolver().openInputStream(uri);
    String fileName = getFileName(context, uri);
    String[] splitName = splitFileName(fileName);
    File tempFile = File.createTempFile(splitName[0], splitName[1]);
    tempFile = rename(tempFile, fileName);
    tempFile.deleteOnExit();
    FileOutputStream out = null;
    try {
      out = new FileOutputStream(tempFile);
    } catch (FileNotFoundException e) {
      e.printStackTrace();
    }
    if (inputStream != null) {
      copy(inputStream, out);
      inputStream.close();
    }

    if (out != null) {
      out.close();
    }
    return tempFile;
  }

  private static String[] splitFileName(String fileName) {
    String name = fileName;
    String extension = "";
    int i = fileName.lastIndexOf(".");
    if (i != -1) {
      name = fileName.substring(0, i);
      extension = fileName.substring(i);
    }

    return new String[]{name, extension};
  }

  private static String getFileName(Context context, Uri uri) {
    String result = null;
    if (uri.getScheme().equals("content")) {
      Cursor cursor = context.getContentResolver().query(uri, null, null, null, null);
      try {
        if (cursor != null && cursor.moveToFirst()) {
          result = cursor.getString(cursor.getColumnIndex(OpenableColumns.DISPLAY_NAME));
        }
      } catch (Exception e) {
        e.printStackTrace();
      } finally {
        if (cursor != null) {
          cursor.close();
        }
      }
    }
    if (result == null) {
      result = uri.getPath();
      int cut = result.lastIndexOf(File.separator);
      if (cut != -1) {
        result = result.substring(cut + 1);
      }
    }
    return result;
  }

  private static File rename(File file, String newName) {
    File newFile = new File(file.getParent(), newName);
    if (!newFile.equals(file)) {
      if (newFile.exists() && newFile.delete()) {
        Log.d("FileUtil", "Delete old " + newName + " file");
      }
      if (file.renameTo(newFile)) {
        Log.d("FileUtil", "Rename file to " + newName);
      }
    }
    return newFile;
  }

  private static long copy(InputStream input, OutputStream output) throws IOException {
    long count = 0;
    int n;
    byte[] buffer = new byte[DEFAULT_BUFFER_SIZE];
    while (EOF != (n = input.read(buffer))) {
      output.write(buffer, 0, n);
      count += n;
    }
    return count;
  }
}

并且必须将provider_paths.xml添加到像image这样的XML文件夹中

provider_paths.xml

<?xml version="1.0" encoding="utf-8"?>
<paths>
    <external-path name="external_files" path="."/>
</paths>

最后在AndroidManifest.xml中添加如下内容

<application
...>

...
      <provider
          android:name="androidx.core.content.FileProvider"
          android:authorities="${applicationId}.provider"
          android:exported="false"
          android:grantUriPermissions="true">
          <meta-data
            android:name="android.support.FILE_PROVIDER_PATHS"
            android:resource="@xml/provider_paths" />
        </provider>
...
</application>

我希望我能帮上忙

如果你只是寻找图像和多重选择。

看一次https://stackoverflow.com/a/15029515/1136023

这对将来很有帮助。我个人觉得使用MultipleImagePick很棒。

下面是kotlin中util方法的工作代码:

fun launchGalleryWithFragment() {
        val intent = Intent(Intent.ACTION_PICK, MediaStore.Images.Media.EXTERNAL_CONTENT_URI)
        intent.type = "image/*"
        startActivityForResult(Intent.createChooser(intent, "Select Picture"), 1001)
    }

现在重写onActivityResult方法:

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
    super.onActivityResult(requestCode, resultCode, data)
var path: Uri? = null
        if (requestCode == PICK_IMAGE_REQUEST && resultCode == Activity.RESULT_OK) {
            if(dataIntent == null || dataIntent.data == null){
                return null
            }
            path = dataIntent.data
        }

}

你可以做的比下面的回答更简单:

Uri Selected_Image_Uri = data.getData();
ImageView imageView = (ImageView) findViewById(R.id.loadedimg);
imageView.setImageURI(Selected_Image_Uri);

Kotlin:当你想提示用户时，打开ACTION_GET_CONTENT事件:

val intent = Intent(Intent.ACTION_GET_CONTENT).apply { type = "image/*" }
startActivityForResult(intent, 9998)

当用户选择了一张图片后，在Activity的onActivityResult函数中处理该事件。作为一个例子，我在一个ImageView中显示它，并将它存储在应用程序缓存中:

override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
    super.onActivityResult(requestCode, resultCode, data)
    if (requestCode == 9998) {
        val uri: Uri = data?.data ?: return
        val bytes = contentResolver.openInputStream(uri)?.readBytes() ?: return
        imageView.setImageBitmap(BitmapFactory.decodeByteArray(bytes, 0, bytes.size))
        File("$cacheDir/imgPicked").writeBytes(bytes)  // if needed: store to cache
    }
}

理想情况下，将9998替换为应用程序使用的一些内部请求代码。这只是为了区分回调与您自己的请求。

与getParcelable("data")不同，它不需要任何权限。

注意，这不会处理设置它的图像上的Exif旋转位，因此一些图像最终会出现不正确的方向(Kotlin解决方案)。