.NET基类库中是否存在允许使用重复键的字典类?我找到的唯一解决方案是创建,例如,一个类:
Dictionary<string, List<object>>
但实际上用起来很烦人。在Java中,我相信MultiMap可以实现这一点,但在. net中找不到类似的东西。
.NET基类库中是否存在允许使用重复键的字典类?我找到的唯一解决方案是创建,例如,一个类:
Dictionary<string, List<object>>
但实际上用起来很烦人。在Java中,我相信MultiMap可以实现这一点,但在. net中找不到类似的东西。
当前回答
“滚动您自己的”版本的字典,允许“重复键”条目,这很容易。下面是一个粗略的简单实现。您可能需要考虑添加对dictionary <T>的基本大部分(如果不是全部)的支持。
public class MultiMap<TKey,TValue>
{
private readonly Dictionary<TKey,IList<TValue>> storage;
public MultiMap()
{
storage = new Dictionary<TKey,IList<TValue>>();
}
public void Add(TKey key, TValue value)
{
if (!storage.ContainsKey(key)) storage.Add(key, new List<TValue>());
storage[key].Add(value);
}
public IEnumerable<TKey> Keys
{
get { return storage.Keys; }
}
public bool ContainsKey(TKey key)
{
return storage.ContainsKey(key);
}
public IList<TValue> this[TKey key]
{
get
{
if (!storage.ContainsKey(key))
throw new KeyNotFoundException(
string.Format(
"The given key {0} was not found in the collection.", key));
return storage[key];
}
}
}
一个关于如何使用它的简单例子:
const string key = "supported_encodings";
var map = new MultiMap<string,Encoding>();
map.Add(key, Encoding.ASCII);
map.Add(key, Encoding.UTF8);
map.Add(key, Encoding.Unicode);
foreach (var existingKey in map.Keys)
{
var values = map[existingKey];
Console.WriteLine(string.Join(",", values));
}
其他回答
我将@Hector Correa的答案更改为具有泛型类型的扩展,并添加了一个自定义TryGetValue。
public static class ListWithDuplicateExtensions
{
public static void Add<TKey, TValue>(this List<KeyValuePair<TKey, TValue>> collection, TKey key, TValue value)
{
var element = new KeyValuePair<TKey, TValue>(key, value);
collection.Add(element);
}
public static int TryGetValue<TKey, TValue>(this List<KeyValuePair<TKey, TValue>> collection, TKey key, out IEnumerable<TValue> values)
{
values = collection.Where(pair => pair.Key.Equals(key)).Select(pair => pair.Value);
return values.Count();
}
}
如果你正在使用>= .NET 4,那么你可以使用元组类:
// declaration
var list = new List<Tuple<string, List<object>>>();
// to add an item to the list
var item = Tuple<string, List<object>>("key", new List<object>);
list.Add(item);
// to iterate
foreach(var i in list)
{
Console.WriteLine(i.Item1.ToString());
}
你可以创建自己的字典包装器,就像这样,作为奖励,它支持空值作为键:
/// <summary>
/// Dictionary which supports duplicates and null entries
/// </summary>
/// <typeparam name="TKey">Type of key</typeparam>
/// <typeparam name="TValue">Type of items</typeparam>
public class OpenDictionary<TKey, TValue>
{
private readonly Lazy<List<TValue>> _nullStorage = new Lazy<List<TValue>>(
() => new List<TValue>());
private readonly Dictionary<TKey, List<TValue>> _innerDictionary =
new Dictionary<TKey, List<TValue>>();
/// <summary>
/// Get all entries
/// </summary>
public IEnumerable<TValue> Values =>
_innerDictionary.Values
.SelectMany(x => x)
.Concat(_nullStorage.Value);
/// <summary>
/// Add an item
/// </summary>
public OpenDictionary<TKey, TValue> Add(TKey key, TValue item)
{
if (ReferenceEquals(key, null))
_nullStorage.Value.Add(item);
else
{
if (!_innerDictionary.ContainsKey(key))
_innerDictionary.Add(key, new List<TValue>());
_innerDictionary[key].Add(item);
}
return this;
}
/// <summary>
/// Remove an entry by key
/// </summary>
public OpenDictionary<TKey, TValue> RemoveEntryByKey(TKey key, TValue entry)
{
if (ReferenceEquals(key, null))
{
int targetIdx = _nullStorage.Value.FindIndex(x => x.Equals(entry));
if (targetIdx < 0)
return this;
_nullStorage.Value.RemoveAt(targetIdx);
}
else
{
if (!_innerDictionary.ContainsKey(key))
return this;
List<TValue> targetChain = _innerDictionary[key];
if (targetChain.Count == 0)
return this;
int targetIdx = targetChain.FindIndex(x => x.Equals(entry));
if (targetIdx < 0)
return this;
targetChain.RemoveAt(targetIdx);
}
return this;
}
/// <summary>
/// Remove all entries by key
/// </summary>
public OpenDictionary<TKey, TValue> RemoveAllEntriesByKey(TKey key)
{
if (ReferenceEquals(key, null))
{
if (_nullStorage.IsValueCreated)
_nullStorage.Value.Clear();
}
else
{
if (_innerDictionary.ContainsKey(key))
_innerDictionary[key].Clear();
}
return this;
}
/// <summary>
/// Try get entries by key
/// </summary>
public bool TryGetEntries(TKey key, out IReadOnlyList<TValue> entries)
{
entries = null;
if (ReferenceEquals(key, null))
{
if (_nullStorage.IsValueCreated)
{
entries = _nullStorage.Value;
return true;
}
else return false;
}
else
{
if (_innerDictionary.ContainsKey(key))
{
entries = _innerDictionary[key];
return true;
}
else return false;
}
}
}
用法示例:
var dictionary = new OpenDictionary<string, int>();
dictionary.Add("1", 1);
// The next line won't throw an exception;
dictionary.Add("1", 2);
dictionary.TryGetEntries("1", out List<int> result);
// result is { 1, 2 }
dictionary.Add(null, 42);
dictionary.Add(null, 24);
dictionary.TryGetEntries(null, out List<int> result);
// result is { 42, 24 }
你是说完全一致而不是完全重复吗?否则哈希表将无法工作。
同余意味着两个单独的键可以哈希到等价的值,但键不相等。
例如:假设你的哈希表的哈希函数是hashval = key mod 3。1和4都映射到1,但是是不同的值。这就是列表的概念发挥作用的地方。
当需要查找1时,该值被哈希为1,遍历列表,直到找到Key = 1。
如果允许插入重复的键,则无法区分哪些键映射到哪些值。
如果同时使用字符串作为键和值,则可以使用System.Collections.Specialized。它将通过GetValues(string key)方法返回一个字符串值数组。