我认为List<KeyValuePair<object object>>可以完成任务。

这也是可能的:

Dictionary<string, string[]> previousAnswers = null;

这样，我们就有了唯一的键。希望这对你有用。

List类实际上适用于包含重复项的键/值集合，在此集合上进行迭代。例子:

List<KeyValuePair<string, string>> list = new List<KeyValuePair<string, string>>();

// add some values to the collection here

for (int i = 0;  i < list.Count;  i++)
{
    Print(list[i].Key, list[i].Value);
}

你可以创建自己的字典包装器，就像这样，作为奖励，它支持空值作为键:

/// <summary>
/// Dictionary which supports duplicates and null entries
/// </summary>
/// <typeparam name="TKey">Type of key</typeparam>
/// <typeparam name="TValue">Type of items</typeparam>
public class OpenDictionary<TKey, TValue>
{
    private readonly Lazy<List<TValue>> _nullStorage = new Lazy<List<TValue>>(
        () => new List<TValue>());

    private readonly Dictionary<TKey, List<TValue>> _innerDictionary =
        new Dictionary<TKey, List<TValue>>();

    /// <summary>
    /// Get all entries
    /// </summary>
    public IEnumerable<TValue> Values =>
        _innerDictionary.Values
            .SelectMany(x => x)
            .Concat(_nullStorage.Value);

    /// <summary>
    /// Add an item
    /// </summary>
    public OpenDictionary<TKey, TValue> Add(TKey key, TValue item)
    {
        if (ReferenceEquals(key, null))
            _nullStorage.Value.Add(item);
        else
        {
            if (!_innerDictionary.ContainsKey(key))
                _innerDictionary.Add(key, new List<TValue>());

            _innerDictionary[key].Add(item);
        }

        return this;
    }

    /// <summary>
    /// Remove an entry by key
    /// </summary>
    public OpenDictionary<TKey, TValue> RemoveEntryByKey(TKey key, TValue entry)
    {
        if (ReferenceEquals(key, null))
        {
            int targetIdx = _nullStorage.Value.FindIndex(x => x.Equals(entry));
            if (targetIdx < 0)
                return this;

            _nullStorage.Value.RemoveAt(targetIdx);
        }
        else
        {
            if (!_innerDictionary.ContainsKey(key))
                return this;

            List<TValue> targetChain = _innerDictionary[key];
            if (targetChain.Count == 0)
                return this;

            int targetIdx = targetChain.FindIndex(x => x.Equals(entry));
            if (targetIdx < 0)
                return this;

            targetChain.RemoveAt(targetIdx);
        }

        return this;
    }

    /// <summary>
    /// Remove all entries by key
    /// </summary>
    public OpenDictionary<TKey, TValue> RemoveAllEntriesByKey(TKey key)
    {
        if (ReferenceEquals(key, null))
        {
            if (_nullStorage.IsValueCreated)
                _nullStorage.Value.Clear();
        }       
        else
        {
            if (_innerDictionary.ContainsKey(key))
                _innerDictionary[key].Clear();
        }

        return this;
    }

    /// <summary>
    /// Try get entries by key
    /// </summary>
    public bool TryGetEntries(TKey key, out IReadOnlyList<TValue> entries)
    {
        entries = null;

        if (ReferenceEquals(key, null))
        {
            if (_nullStorage.IsValueCreated)
            {
                entries = _nullStorage.Value;
                return true;
            }
            else return false;
        }
        else
        {
            if (_innerDictionary.ContainsKey(key))
            {
                entries = _innerDictionary[key];
                return true;
            }
            else return false;
        }
    }
}

用法示例:

var dictionary = new OpenDictionary<string, int>();
dictionary.Add("1", 1); 
// The next line won't throw an exception; 
dictionary.Add("1", 2);

dictionary.TryGetEntries("1", out List<int> result); 
// result is { 1, 2 }

dictionary.Add(null, 42);
dictionary.Add(null, 24);
dictionary.TryGetEntries(null, out List<int> result); 
// result is { 42, 24 }

我使用这个简单的类:

public class ListMap<T,V> : List<KeyValuePair<T, V>>
{
    public void Add(T key, V value) {
        Add(new KeyValuePair<T, V>(key, value));
    }

    public List<V> Get(T key) {
        return FindAll(p => p.Key.Equals(key)).ConvertAll(p=> p.Value);
    }
}

用法:

var fruits = new ListMap<int, string>();
fruits.Add(1, "apple");
fruits.Add(1, "orange");
var c = fruits.Get(1).Count; //c = 2;

回答了最初的问题。像Dictionary<string, List<object>>这样的东西是在Code项目中一个名为MultiMap的类中实现的。

你可以在下面的链接中找到更多信息: http://www.codeproject.com/KB/cs/MultiKeyDictionary.aspx