我想检查一个字符串是否在文本文件中。如果是,执行x。如果不是,执行y。然而,由于某种原因,这段代码总是返回True。有人能看出哪里不对吗?

def check():
    datafile = file('example.txt')
    found = False
    for line in datafile:
        if blabla in line:
            found = True
            break

check()
if True:
    print "true"
else:
    print "false"

当前回答

如何搜索文件中的文本并返回在其中找到的字的文件路径 (Какискатьчастьтекставфайлеивозвращятьпутькфайлувкоторомэтословонайдено)

import os
import re

class Searcher:
    def __init__(self, path, query):
        self.path   = path

        if self.path[-1] != '/':
            self.path += '/'

        self.path = self.path.replace('/', '\\')
        self.query  = query
        self.searched = {}

    def find(self):
        for root, dirs, files in os.walk( self.path ):
            for file in files:
                if re.match(r'.*?\.txt$', file) is not None:
                    if root[-1] != '\\':
                        root += '\\'           
                    f = open(root + file, 'rt')
                    txt = f.read()
                    f.close()

                    count = len( re.findall( self.query, txt ) )
                    if count > 0:
                        self.searched[root + file] = count

    def getResults(self):
        return self.searched

在Main ()

# -*- coding: UTF-8 -*-

import sys
from search import Searcher

path = 'c:\\temp\\'
search = 'search string'


if __name__ == '__main__':

    if len(sys.argv) == 3:
        # создаем объект поисковика и передаем ему аргументы
        Search = Searcher(sys.argv[1], sys.argv[2])
    else:
        Search = Searcher(path, search)

    # начать поиск
    Search.find()

    # получаем результат
    results = Search.getResults()

    # выводим результат
    print 'Found ', len(results), ' files:'

    for file, count in results.items():
        print 'File: ', file, ' Found entries:' , count

其他回答

如果用户想在给定的文本文件中搜索单词。

 fopen = open('logfile.txt',mode='r+')

  fread = fopen.readlines()

  x = input("Enter the search string: ")

  for line in fread:

      if x in line:

          print(line)
if True:
    print "true"

这种情况经常发生,因为True总是True。

你想要这样的东西:

if check():
    print "true"
else:
    print "false"

好运!

"found"需要在函数中作为全局变量创建,因为"if else"语句不在函数中。您也不需要使用“break”来中断循环代码。 下面的方法可以确定文本文件是否有所需的字符串。

with open('text_text.txt') as f:
    datafile = f.readlines()


def check():
    global found
    found = False
    for line in datafile:
        if 'the' in line:
            found = True


check()

if found == True:
    print("True")
else:
    print("False")
found = False
def check():
datafile = file('example.txt')
for line in datafile:
    if "blabla" in line:
        found = True
        break
return found

if check():
    print "found"
else:
    print "not found"

正如Jeffrey所说,您不是在检查check()的值。此外,check()函数没有返回任何东西。注意区别:

def check():
    with open('example.txt') as f:
        datafile = f.readlines()
    found = False  # This isn't really necessary
    for line in datafile:
        if blabla in line:
            # found = True # Not necessary
            return True
    return False  # Because you finished the search without finding

然后你可以测试check()的输出:

if check():
    print('True')
else:
    print('False')