我想检查一个字符串是否在文本文件中。如果是,执行x。如果不是,执行y。然而,由于某种原因,这段代码总是返回True。有人能看出哪里不对吗?

def check():
    datafile = file('example.txt')
    found = False
    for line in datafile:
        if blabla in line:
            found = True
            break

check()
if True:
    print "true"
else:
    print "false"

当前回答

如果用户想在给定的文本文件中搜索单词。

 fopen = open('logfile.txt',mode='r+')

  fread = fopen.readlines()

  x = input("Enter the search string: ")

  for line in fread:

      if x in line:

          print(line)

其他回答

如何搜索文件中的文本并返回在其中找到的字的文件路径 (Какискатьчастьтекставфайлеивозвращятьпутькфайлувкоторомэтословонайдено)

import os
import re

class Searcher:
    def __init__(self, path, query):
        self.path   = path

        if self.path[-1] != '/':
            self.path += '/'

        self.path = self.path.replace('/', '\\')
        self.query  = query
        self.searched = {}

    def find(self):
        for root, dirs, files in os.walk( self.path ):
            for file in files:
                if re.match(r'.*?\.txt$', file) is not None:
                    if root[-1] != '\\':
                        root += '\\'           
                    f = open(root + file, 'rt')
                    txt = f.read()
                    f.close()

                    count = len( re.findall( self.query, txt ) )
                    if count > 0:
                        self.searched[root + file] = count

    def getResults(self):
        return self.searched

在Main ()

# -*- coding: UTF-8 -*-

import sys
from search import Searcher

path = 'c:\\temp\\'
search = 'search string'


if __name__ == '__main__':

    if len(sys.argv) == 3:
        # создаем объект поисковика и передаем ему аргументы
        Search = Searcher(sys.argv[1], sys.argv[2])
    else:
        Search = Searcher(path, search)

    # начать поиск
    Search.find()

    # получаем результат
    results = Search.getResults()

    # выводим результат
    print 'Found ', len(results), ' files:'

    for file, count in results.items():
        print 'File: ', file, ' Found entries:' , count
if True:
    print "true"

这种情况经常发生,因为True总是True。

你想要这样的东西:

if check():
    print "true"
else:
    print "false"

好运!

正如Jeffrey所说,您不是在检查check()的值。此外,check()函数没有返回任何东西。注意区别:

def check():
    with open('example.txt') as f:
        datafile = f.readlines()
    found = False  # This isn't really necessary
    for line in datafile:
        if blabla in line:
            # found = True # Not necessary
            return True
    return False  # Because you finished the search without finding

然后你可以测试check()的输出:

if check():
    print('True')
else:
    print('False')

check函数应该返回找到的布尔值,并使用它来确定要打印的内容。

def check():
        datafile = file('example.txt')
        found = False
        for line in datafile:
            if blabla in line:
                found = True
                break

        return found

found = check()
if found:
    print "true"
else:
    print "false"

第二部分也可以压缩为:

if check():
    print "true"
else:
    print "false"

我为此做了一个小函数。它在输入文件中搜索单词,然后将其添加到输出文件中。

def searcher(outf, inf, string):
    with open(outf, 'a') as f1:
        if string in open(inf).read():
            f1.write(string)

Outf是输出文件 Inf是输入文件 String当然是您希望找到并添加到outf的所需字符串。