截断长字符串的聪明方法

有没有人有一个更复杂的解决方案/库，用JavaScript截断字符串，并在末尾放一个省略号，比明显的一个:

if (string.length > 25) {
  string = string.substring(0, 24) + "...";
}

当前回答

以下是我的解决方案，与其他建议相比有一些改进:

String.prototype.truncate = function(){
    var re = this.match(/^.{0,25}[\S]*/);
    var l = re[0].length;
    var re = re[0].replace(/\s$/,'');
    if(l < this.length)
        re = re + "&hellip;";
    return re;
}

// "This is a short string".truncate();
"This is a short string"

// "Thisstringismuchlongerthan25characters".truncate();
"Thisstringismuchlongerthan25characters"

// "This string is much longer than 25 characters and has spaces".truncate();
"This string is much longer&hellip;"

It:

在25之后的第一个空格上截断字符扩展JavaScript字符串对象，因此它可以用于(并链接到) 任何字符串。如果截断将修剪字符串结果在一个尾随空间中; 是否添加unicode hellip实体 (省略号)如果截断的字符串长于25个字符

2009-07-29 11:37:43

其他回答

这里是我的解决方案与字边界。

let s = "At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Temporibus autem quibusdam et aut officiis debitis aut rerum necessitatibus saepe eveniet ut et voluptates repudiandae sint et molestiae non recusandae. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat." let s_split = s.split(/\s+/); let word_count = 0; let result = ""; //1 for(let i = 0; word_count < 100; i++){ word_count += s_split[i].length+1; result += (s_split[i] + " "); } console.log(result); // 2 word_count = 0; result = s_split.reduce((x,y)=>{ word_count+=(y.length+1); if(word_count>=100) return x; else return x+" "+y;}, "").substring(1); console.log(result);

2020-12-03 16:34:40

在我看来，C_harm的答案是最好的。请注意，如果你想使用

"My string".truncate(n)

您将不得不使用regexp对象构造函数而不是文字。此外，在转换\S时还必须转义它。

String.prototype.truncate =
    function(n){
        var p  = new RegExp("^.{0," + n + "}[\\S]*", 'g');
        var re = this.match(p);
        var l  = re[0].length;
        var re = re[0].replace(/\s$/,'');

        if (l < this.length) return re + '&hellip;';
    };

2013-02-27 09:11:22

聪明的地方:D

//My Huge Huge String let tooHugeToHandle = `It is a long established fact that a reader will be distracted by the readable content of a page when looking at its layout. The point of using Lorem Ipsum is that it has a more-or-less normal distribution of letters, as opposed to using 'Content here, content here', making it look like readable English. Many desktop publishing packages and web page editors now use Lorem Ipsum as their default model text, and a search for 'lorem ipsum' will uncover many web sites still in their infancy. Various versions have evolved over the years, sometimes by accident, sometimes on purpose (injected humour and the like).` //Trim Max Length const maxValue = 50 // The barber. const TrimMyString = (string, maxLength, start = 0) => { //Note - `start` is if I want to start after some point of the string if (string.length > maxLength) { let trimmedString = string.substr(start, maxLength) return ( trimmedString.substr( start, Math.min(trimmedString.length, trimmedString.lastIndexOf(' ')) ) + ' ...' ) } return string } console.log(TrimMyString(tooHugeToHandle, maxValue))

2019-02-22 07:41:42

我总是使用cutr .js库来截断字符串并添加自定义省略号:

new Cuttr（'.container'， { 此处的选项截断：“单词”，长度： 8，结尾：“...►' }); <script src=“https://unpkg.com/cuttr@1.1.1/dist/cuttr.min.js”></script> <p class=“container”>Lorem ipsum dolor sit amet， consetetur sadipscing elitr， sed diam nonumy eirmod tempor invidunt ut labore et dolore magna aliquyam erat， sed diam voluptua.在vero eos et accusam et justo duo dolores et ea rebum.Stet clita kasd gubergren， no sea takimata sanctus est lorem ipsum dolor sit amet.</p>

这是迄今为止我所知道的用JS切割字符串的最简单的方法(并且没有任何依赖关系)，它也可以作为jQuery插件使用。

2020-08-06 18:44:15

本质上，检查给定字符串的长度。如果它比给定的长度n长，剪辑到长度n (substr或slice)，并添加html实体…(…)到剪短的字符串。

这样的方法看起来像

function truncate(str, n){
  return (str.length > n) ? str.slice(0, n-1) + '&hellip;' : str;
};

如果你所说的“更复杂”是指在字符串的最后一个单词边界处截断，那么你需要额外的检查。首先将字符串剪辑到所需的长度，然后将其结果剪辑到最后一个单词边界

function truncate( str, n, useWordBoundary ){
  if (str.length <= n) { return str; }
  const subString = str.slice(0, n-1); // the original check
  return (useWordBoundary 
    ? subString.slice(0, subString.lastIndexOf(" ")) 
    : subString) + "&hellip;";
};

您可以用您的函数扩展本机String原型。在这种情况下，str形参应该被删除，函数中的str应该被替换为:

String.prototype.truncate = String.prototype.truncate || 
function ( n, useWordBoundary ){
  if (this.length <= n) { return this; }
  const subString = this.slice(0, n-1); // the original check
  return (useWordBoundary 
    ? subString.slice(0, subString.lastIndexOf(" ")) 
    : subString) + "&hellip;";
};

更教条的开发人员可能会因此强烈地责备你(“不要修改你不拥有的对象”)。不过我不介意)。

一种不扩展String原型的方法是创建您自己的helper对象，包含您提供的(长)字符串和前面提到的截断方法。这就是代码片段下面。

最后，您可以使用css仅截断HTML节点中的长字符串。它给你较少的控制，但可能是可行的解决方案。

body { font: normal 12px/15px verdana, arial; margin: 2rem; } .truncate { white-space: nowrap; overflow: hidden; text-overflow: ellipsis; width: 30vw; } .truncate:before{ content: attr(data-longstring); } .truncate:hover::before { content: attr(data-longstring); width: auto; height: auto; overflow: initial; text-overflow: initial; white-space: initial; background-color: white; display: inline-block; } <div class="truncate" data-longstring="Lorem ipsum dolor sit amet, consectetur adipiscing elit, sed do eiusmod tempor incididunt ut labore et dolore magna aliqua. Ut enim ad minim veniam, quis nostrud exercitation ullamco laboris nisi ut aliquip ex ea commodo consequat. Duis aute irure dolor in reprehenderit in voluptate velit esse cillum dolore eu fugiat nulla pariatur. Excepteur sint occaecat cupidatat non proident, sunt in culpa qui officia deserunt mollit anim id est laborum."></div>

2009-07-29 10:56:50

截断长字符串的聪明方法

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