如何在c#中通过反射获得命名空间中的所有类?


当前回答

在一行中通过Namespace名称的一部分获取所有类:

var allClasses = Assembly.GetExecutingAssembly().GetTypes().Where(a => a.IsClass && a.Namespace != null && a.Namespace.Contains(@"..your namespace...")).ToList();

其他回答

Namespaces are actually rather passive in the design of the runtime and serve primarily as organizational tools. The Full Name of a type in .NET consists of the Namespace and Class/Enum/Etc. combined. If you only wish to go through a specific assembly, you would simply loop through the types returned by assembly.GetExportedTypes() checking the value of type.Namespace. If you were trying to go through all assemblies loaded in the current AppDomain it would involve using AppDomain.CurrentDomain.GetAssemblies()

您将无法获得一个名称空间中的所有类型,因为一个名称空间可以桥接多个程序集,但是您可以获得一个程序集中的所有类并检查它们是否属于该名称空间。

assembly .GetTypes()在本地程序集上工作,或者您可以先加载一个程序集,然后在其上调用GetTypes()。

就像@aku的答案,但使用扩展方法:

string @namespace = "...";

var types = Assembly.GetExecutingAssembly().GetTypes()
    .Where(t => t.IsClass && t.Namespace == @namespace)
    .ToList();

types.ForEach(t => Console.WriteLine(t.Name));

在一行中通过Namespace名称的一部分获取所有类:

var allClasses = Assembly.GetExecutingAssembly().GetTypes().Where(a => a.IsClass && a.Namespace != null && a.Namespace.Contains(@"..your namespace...")).ToList();

对于特定的程序集,命名空间和ClassName:

var assemblyName = "Some.Assembly.Name"
var nameSpace = "Some.Namespace.Name";
var className = "ClassNameFilter";

var asm = Assembly.Load(assemblyName);
var classes = asm.GetTypes().Where(p =>
     p.Namespace == nameSpace &&
     p.Name.Contains(className) 
).ToList();

注意:项目必须引用程序集