这是我的HTML表单:

<form name="myForm" ng-submit="">
    <input ng-model='file' type="file"/>
    <input type="submit" value='Submit'/>
</form>

我想从本地机器上传一个图像,并想读取上传文件的内容。所有这些我都想用AngularJS来做。

当我试图打印$scope的值时。文件是未定义的。


当前回答

以上接受的答案不兼容浏览器。如果有人有兼容性问题,试试这个。

小提琴

视图代码

 <div ng-controller="MyCtrl">
      <input type="file" id="file" name="file"/>
      <br>
      <button ng-click="add()">Add</button>
      <p>{{data}}</p>
    </div>

控制器代码

var myApp = angular.module('myApp',[]);

function MyCtrl($scope) {
    $scope.data = 'none';    
    $scope.add = function(){
      var f = document.getElementById('file').files[0],
          r = new FileReader();
      r.onloadend = function(e){        
          var binary = "";
var bytes = new Uint8Array(e.target.result);
var length = bytes.byteLength;

for (var i = 0; i < length; i++) 
{
    binary += String.fromCharCode(bytes[i]);
}

$scope.data = (binary).toString();

          alert($scope.data);
      }
      r.readAsArrayBuffer(f);
    }
}

其他回答

你可以使用一个安全快速的FormData对象:

// Store the file object when input field is changed
$scope.contentChanged = function(event){
    if (!event.files.length)
        return null;

    $scope.content = new FormData();
    $scope.content.append('fileUpload', event.files[0]); 
    $scope.$apply();
}

// Upload the file over HTTP
$scope.upload = function(){
    $http({
        method: 'POST', 
        url: '/remote/url',
        headers: {'Content-Type': undefined },
        data: $scope.content,
    }).success(function(response) {
        // Uploading complete
        console.log('Request finished', response);
    });
}

简单的指令

Html:

<input type="file" file-upload multiple/>

JS:

app.directive('fileUpload', function () {
return {
    scope: true,        //create a new scope
    link: function (scope, el, attrs) {
        el.bind('change', function (event) {
            var files = event.target.files;
            //iterate files since 'multiple' may be specified on the element
            for (var i = 0;i<files.length;i++) {
                //emit event upward
                scope.$emit("fileSelected", { file: files[i] });
            }                                       
        });
    }
};

在指令中,我们确保创建了一个新的作用域,然后监听对文件输入元素所做的更改。当检测到更改时,以文件对象作为参数向所有祖先作用域(向上)发出事件。

在你的控制器中:

$scope.files = [];

//listen for the file selected event
$scope.$on("fileSelected", function (event, args) {
    $scope.$apply(function () {            
        //add the file object to the scope's files collection
        $scope.files.push(args.file);
    });
});

然后在ajax调用中:

data: { model: $scope.model, files: $scope.files }

http://shazwazza.com/post/uploading-files-and-json-data-in-the-same-request-with-angular-js/

http://jsfiddle.net/vishalvasani/4hqVu/在chrome和IE中运行良好(如果你在background-image中稍微更新CSS)。 用于更新进度条:

 scope.progress = Math.round(evt.loaded * 100 / evt.total)

但是在FireFox中,angular的[percent]数据没有在DOM中成功更新,尽管文件上传成功。

这是

file.html

<html>
   <head>
      <script src = "https://ajax.googleapis.com/ajax/libs/angularjs/1.3.14/angular.min.js"></script>
   </head>
   <body ng-app = "app">
      <div ng-controller = "myCtrl">
         <input type = "file" file-model = "myFile"/>
         <button ng-click = "uploadFile()">upload me</button>
      </div>
   </body>
   <script src="controller.js"></script>
</html>

controller.js

     var app = angular.module('app', []);

     app.service('fileUpload', ['$http', function ($http) {
        this.uploadFileToUrl = function(file, uploadUrl){
           var fd = new FormData();
           fd.append('file', file);

           $http.post(uploadUrl, fd, {
              transformRequest: angular.identity,
              headers: {'Content-Type': undefined}
           }).success(function(res){
                console.log(res);
           }).error(function(error){
                console.log(error);
           });
        }
     }]);

     app.controller('fileCtrl', ['$scope', 'fileUpload', function($scope, fileUpload){
        $scope.uploadFile = function(){
           var file = $scope.myFile;

           console.log('file is ' );
           console.dir(file);

           var uploadUrl = "/fileUpload.php";  // upload url stands for api endpoint to handle upload to directory
           fileUpload.uploadFileToUrl(file, uploadUrl);
        };
     }]);

  </script>

fileupload.php

  <?php
    $ext = pathinfo($_FILES['file']['name'],PATHINFO_EXTENSION);
    $image = time().'.'.$ext;
    move_uploaded_file($_FILES["file"]["tmp_name"],__DIR__. ' \\'.$image);
  ?>

这里的一些答案建议使用FormData(),但不幸的是,这是一个浏览器对象,在Internet Explorer 9及以下版本中不可用。如果您需要支持这些旧浏览器,您将需要一个备份策略,例如使用<iframe>或Flash。

已经有很多Angular.js模块来执行文件上传。这两种浏览器都明确支持旧浏览器:

https://github.com/leon/angular-upload -使用iframes作为备份 https://github.com/danialfarid/ng-file-upload -使用FileAPI/Flash作为备份

还有一些其他的选择:

https://github.com/nervgh/angular-file-upload/ https://github.com/uor/angular-file https://github.com/twilson63/ngUpload https://github.com/uploadcare/angular-uploadcare

其中一个应该适合你的项目,或者可能会给你一些关于如何自己编写代码的见解。