最简单的是使用HTML5 API，即FileReader

HTML非常简单:

<input type="file" id="file" name="file"/>
<button ng-click="add()">Add</button>

在你的控制器中定义'add'方法:

$scope.add = function() {
    var f = document.getElementById('file').files[0],
        r = new FileReader();

    r.onloadend = function(e) {
      var data = e.target.result;
      //send your binary data via $http or $resource or do anything else with it
    }

    r.readAsBinaryString(f);
}

浏览器兼容性

桌面浏览器

Edge 12, Firefox(Gecko) 3.6(1.9.2)， Chrome 7, Opera* 12.02, Safari 6.0.2

移动浏览器

Firefox(壁虎)32, Chrome 3, 歌剧* 11.5, Safari 6.1

注意:readAsBinaryString()方法已弃用，应该使用readAsArrayBuffer()代替。

简单的指令

Html:

<input type="file" file-upload multiple/>

JS:

app.directive('fileUpload', function () {
return {
    scope: true,        //create a new scope
    link: function (scope, el, attrs) {
        el.bind('change', function (event) {
            var files = event.target.files;
            //iterate files since 'multiple' may be specified on the element
            for (var i = 0;i<files.length;i++) {
                //emit event upward
                scope.$emit("fileSelected", { file: files[i] });
            }                                       
        });
    }
};

在指令中，我们确保创建了一个新的作用域，然后监听对文件输入元素所做的更改。当检测到更改时，以文件对象作为参数向所有祖先作用域(向上)发出事件。

在你的控制器中:

$scope.files = [];

//listen for the file selected event
$scope.$on("fileSelected", function (event, args) {
    $scope.$apply(function () {            
        //add the file object to the scope's files collection
        $scope.files.push(args.file);
    });
});

然后在ajax调用中:

data: { model: $scope.model, files: $scope.files }

http://shazwazza.com/post/uploading-files-and-json-data-in-the-same-request-with-angular-js/

我能够通过使用下面的代码使用AngularJS上传文件:

函数ngUploadFileUpload需要传递的参数的文件是$scope。按你的问题归档。

这里的关键点是使用transformRequest:[]。这将防止$http与文件内容混淆。

       function getFileBuffer(file) {
            var deferred = new $q.defer();
            var reader = new FileReader();
            reader.onloadend = function (e) {
                deferred.resolve(e.target.result);
            }
            reader.onerror = function (e) {
                deferred.reject(e.target.error);
            }

            reader.readAsArrayBuffer(file);
            return deferred.promise;
        }

        function ngUploadFileUpload(endPointUrl, file) {

            var deferred = new $q.defer();
            getFileBuffer(file).then(function (arrayBuffer) {

                $http({
                    method: 'POST',
                    url: endPointUrl,
                    headers: {
                        "accept": "application/json;odata=verbose",
                        'X-RequestDigest': spContext.securityValidation,
                        "content-length": arrayBuffer.byteLength
                    },
                    data: arrayBuffer,
                    transformRequest: []
                }).then(function (data) {
                    deferred.resolve(data);
                }, function (error) {
                    deferred.reject(error);
                    console.error("Error", error)
                });
            }, function (error) {
                console.error("Error", error)
            });

            return deferred.promise;

        }

我知道这是一个较晚的条目，但我已经创建了一个简单的上传指令。你可以在任何时间工作!

<input type="file" multiple ng-simple-upload web-api-url="/api/Upload" callback-fn="myCallback" />

在Github上上传更多使用Web API的示例。

<form id="csv_file_form" ng-submit="submit_import_csv()" method="POST" enctype="multipart/form-data">
    <input ng-model='file' type="file"/>
    <input type="submit" value='Submit'/>
</form>

在angularJS控制器中

$scope.submit_import_csv = function(){

        var formData = new FormData(document.getElementById("csv_file_form"));
        console.log(formData);

        $.ajax({
            url: "import",
            type: 'POST',
            data:  formData,
            mimeType:"multipart/form-data",
            contentType: false,
            cache: false,
            processData:false,
            success: function(result, textStatus, jqXHR)
            {
            console.log(result);
            }
        });

        return false;
    }

您的文件和json数据同时上传。

// FIRST SOLUTION var _post = function (file, jsonData) { $http({ url: your url, method: "POST", headers: { 'Content-Type': undefined }, transformRequest: function (data) { var formData = new FormData(); formData.append("model", angular.toJson(data.model)); formData.append("file", data.files); return formData; }, data: { model: jsonData, files: file } }).then(function (response) { ; }); } // END OF FIRST SOLUTION // SECOND SOLUTION // If you can add plural file and If above code give an error. // You can try following code var _post = function (file, jsonData) { $http({ url: your url, method: "POST", headers: { 'Content-Type': undefined }, transformRequest: function (data) { var formData = new FormData(); formData.append("model", angular.toJson(data.model)); for (var i = 0; i < data.files.length; i++) { // add each file to // the form data and iteratively name them formData.append("file" + i, data.files[i]); } return formData; }, data: { model: jsonData, files: file } }).then(function (response) { ; }); } // END OF SECOND SOLUTION