我尝试了这个精简版的@RobinL，效果很好:

try:
    do_something_that_might_raise_an_exception()
except ValueError as e:
    raise ValueError(f'Custom text {e}')

上面提出的许多解决方案再次引发异常，这被认为是一种糟糕的做法。像这样简单的东西就可以了

try:
    import settings
except ModuleNotFoundError:
    print("Something meaningfull\n")
    raise 

因此，您将首先打印错误消息，然后引发堆栈跟踪，或者您可以简单地通过sys.exit(1)退出，而根本不显示错误消息。

try:
    try:
        int('a')
    except ValueError as e:
        raise ValueError('There is a problem: {0}'.format(e))
except ValueError as err:
    print err

打印:

There is a problem: invalid literal for int() with base 10: 'a'

这是我在Python 2.7和3中用来修改异常消息的函数。X，同时保留原始的回溯。需要6个

def reraise_modify(caught_exc, append_msg, prepend=False):
    """Append message to exception while preserving attributes.

    Preserves exception class, and exception traceback.

    Note:
        This function needs to be called inside an except because
        `sys.exc_info()` requires the exception context.

    Args:
        caught_exc(Exception): The caught exception object
        append_msg(str): The message to append to the caught exception
        prepend(bool): If True prepend the message to args instead of appending

    Returns:
        None

    Side Effects:
        Re-raises the exception with the preserved data / trace but
        modified message
    """
    ExceptClass = type(caught_exc)
    # Keep old traceback
    traceback = sys.exc_info()[2]
    if not caught_exc.args:
        # If no args, create our own tuple
        arg_list = [append_msg]
    else:
        # Take the last arg
        # If it is a string
        # append your message.
        # Otherwise append it to the
        # arg list(Not as pretty)
        arg_list = list(caught_exc.args[:-1])
        last_arg = caught_exc.args[-1]
        if isinstance(last_arg, str):
            if prepend:
                arg_list.append(append_msg + last_arg)
            else:
                arg_list.append(last_arg + append_msg)
        else:
            arg_list += [last_arg, append_msg]
    caught_exc.args = tuple(arg_list)
    six.reraise(ExceptClass,
                caught_exc,
                traceback)

上面的解决方案都没有完全满足我的要求，即在错误消息的第一部分添加一些信息，即我希望我的用户首先看到我的自定义消息。

这招对我很管用:

exception_raised = False
try:
    do_something_that_might_raise_an_exception()
except ValueError as e:
    message = str(e)
    exception_raised = True

if exception_raised:
    message_to_prepend = "Custom text"
    raise ValueError(message_to_prepend + message)

使用的错误消息引发新的异常

raise Exception('your error message')

or

raise ValueError('your error message')

在你想要引发它或使用'from'将错误消息附加(替换)到当前异常的地方(Python 3。只支持X):

except ValueError as e:
  raise ValueError('your message') from e