引发相同的错误，并在前面添加自定义文本消息。 (编辑-抱歉，实际上和https://stackoverflow.com/a/65494175/15229310一样，为什么有10个(好评)“解决方案”只是不回答张贴的问题?)

    try:
       <code causing exception>
    except Exception as e:
        e.args = (f"My custom text. Original Exception text: {'-'.join(e.args)}",)
        raise

It seems all the answers are adding info to e.args[0], thereby altering the existing error message. Is there a downside to extending the args tuple instead? I think the possible upside is, you can leave the original error message alone for cases where parsing that string is needed; and you could add multiple elements to the tuple if your custom error handling produced several messages or error codes, for cases where the traceback would be parsed programmatically (like via a system monitoring tool).

## Approach #1, if the exception may not be derived from Exception and well-behaved:

def to_int(x):
    try:
        return int(x)
    except Exception as e:
        e.args = (e.args if e.args else tuple()) + ('Custom message',)
        raise

>>> to_int('12')
12

>>> to_int('12 monkeys')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 3, in to_int
ValueError: ("invalid literal for int() with base 10: '12 monkeys'", 'Custom message')

or

## Approach #2, if the exception is always derived from Exception and well-behaved:

def to_int(x):
    try:
        return int(x)
    except Exception as e:
        e.args += ('Custom message',)
        raise

>>> to_int('12')
12

>>> to_int('12 monkeys')
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 3, in to_int
ValueError: ("invalid literal for int() with base 10: '12 monkeys'", 'Custom message')

你能看出这种方法的缺点吗?

上面提出的许多解决方案再次引发异常，这被认为是一种糟糕的做法。像这样简单的东西就可以了

try:
    import settings
except ModuleNotFoundError:
    print("Something meaningfull\n")
    raise 

因此，您将首先打印错误消息，然后引发堆栈跟踪，或者您可以简单地通过sys.exit(1)退出，而根本不显示错误消息。

更新:对于Python 3，检查Ben的答案

将一条消息附加到当前异常并重新引发: (外面的try/except只是为了展示效果)

对于python 2。其中X >=6:

try:
    try:
      raise ValueError  # something bad...
    except ValueError as err:
      err.message=err.message+" hello"
      raise              # re-raise current exception
except ValueError as e:
    print(" got error of type "+ str(type(e))+" with message " +e.message)

如果err是从ValueError派生的，这也会做正确的事情。例如UnicodeDecodeError。

请注意，您可以添加任何您喜欢的错误。例如err.problematic_array=[1,2,3]。

编辑:@Ducan在注释中指出，上述内容不适用于python 3，因为.message不是ValueError的成员。相反，你可以使用这个(有效的python 2.6或更高版本或3.x):

try:
    try:
      raise ValueError
    except ValueError as err:
       if not err.args: 
           err.args=('',)
       err.args = err.args + ("hello",)
       raise 
except ValueError as e:
    print(" error was "+ str(type(e))+str(e.args))

Edit2:

根据目的，您还可以选择在自己的变量名下添加额外的信息。对于python2和python3:

try:
    try:
      raise ValueError
    except ValueError as err:
       err.extra_info = "hello"
       raise 
except ValueError as e:
    print(" error was "+ str(type(e))+str(e))
    if 'extra_info' in dir(e):
       print e.extra_info

我尝试了这个精简版的@RobinL，效果很好:

try:
    do_something_that_might_raise_an_exception()
except ValueError as e:
    raise ValueError(f'Custom text {e}')

使用的错误消息引发新的异常

raise Exception('your error message')

or

raise ValueError('your error message')

在你想要引发它或使用'from'将错误消息附加(替换)到当前异常的地方(Python 3。只支持X):

except ValueError as e:
  raise ValueError('your message') from e