我如何能找到DIV与某些文本?例如:

<div>
SomeText, text continues.
</div>

试图使用这样的东西:

var text = document.querySelector('div[SomeText*]').innerTEXT;
alert(text);

当然,这是行不通的。我该怎么做呢?


当前回答

由于数据属性中的文本长度没有限制,所以请使用数据属性!然后你可以使用常规的css选择器来选择你的元素(s)像OP想要的。

for (document.querySelectorAll("*")的常量元素){ element.dataset.myInnerText = element.innerText; } 文档。querySelector(“* [data-my-inner-text = '不同的文本。']”).style.color =“蓝色”; <div> . SomeText, text continue .</div> . SomeText, text continue 不同文本< div >。< / div >

理想情况下,您可以在文档加载时完成数据属性设置部分,并缩小querySelectorAll选择器的范围以提高性能。

其他回答

如果你不想使用jquery或类似的东西,那么你可以试试这个:

function findByText(rootElement, text){
    var filter = {
        acceptNode: function(node){
            // look for nodes that are text_nodes and include the following string.
            if(node.nodeType === document.TEXT_NODE && node.nodeValue.includes(text)){
                 return NodeFilter.FILTER_ACCEPT;
            }
            return NodeFilter.FILTER_REJECT;
        }
    }
    var nodes = [];
    var walker = document.createTreeWalker(rootElement, NodeFilter.SHOW_TEXT, filter, false);
    while(walker.nextNode()){
       //give me the element containing the node
       nodes.push(walker.currentNode.parentNode);
    }
    return nodes;
}

//call it like
var nodes = findByText(document.body,'SomeText');
//then do what you will with nodes[];
for(var i = 0; i < nodes.length; i++){ 
    //do something with nodes[i]
} 

在数组中拥有包含文本的节点后,就可以对它们进行操作。比如提醒每个人或打印到控制台。需要注意的是,这可能并不一定会抓取div本身,这将抓取拥有您正在寻找的文本的textnode的父节点。

您最好看看是否有您正在查询的div的父元素。如果是,获取父元素并执行一个element. queryselectorall ("div")。获得nodeList后,在innerText属性上应用一个过滤器。假设我们正在查询的div的父元素的id为container。通常,你可以直接从id访问container,但让我们以正确的方式来做。

var conty = document.getElementById("container"),
     divs = conty.querySelectorAll("div"),
    myDiv = [...divs].filter(e => e.innerText == "SomeText");

就是这样。

这里已经有很多很棒的解决方案了。但是,为了提供一个更精简的解决方案,并且更符合querySelector行为和语法的思想,我选择了一个用几个原型函数扩展Object的解决方案。这两个函数都使用正则表达式来匹配文本,但是,字符串可以作为松散搜索参数提供。

简单地实现以下函数:

// find all elements with inner text matching a given regular expression
// args: 
//      selector: string query selector to use for identifying elements on which we 
//                should check innerText
//      regex: A regular expression for matching innerText; if a string is provided,
//             a case-insensitive search is performed for any element containing the string.
Object.prototype.queryInnerTextAll = function(selector, regex) {
    if (typeof(regex) === 'string') regex = new RegExp(regex, 'i'); 
    const elements = [...this.querySelectorAll(selector)];
    const rtn = elements.filter((e)=>{
        return e.innerText.match(regex);
    });
    
    return rtn.length === 0 ? null : rtn
}

// find the first element with inner text matching a given regular expression
// args: 
//      selector: string query selector to use for identifying elements on which we 
//                should check innerText
//      regex: A regular expression for matching innerText; if a string is provided,
//             a case-insensitive search is performed for any element containing the string.
Object.prototype.queryInnerText = function(selector, text){
    return this.queryInnerTextAll(selector, text)[0];
}

实现了这些函数后,现在可以进行如下调用:

document.queryInnerTextAll('div.link', 'go'); This would find all divs containing the link class with the word go in the innerText (eg. Go Left or GO down or go right or It's Good) document.queryInnerText('div.link', 'go'); This would work exactly as the example above except it would return only the first matching element. document.queryInnerTextAll('a', /^Next$/); Find all links with the exact text Next (case-sensitive). This will exclude links that contain the word Next along with other text. document.queryInnerText('a', /next/i); Find the first link that contains the word next, regardless of case (eg. Next Page or Go to next) e = document.querySelector('#page'); e.queryInnerText('button', /Continue/); This performs a search within a container element for a button containing the text, Continue (case-sensitive). (eg. Continue or Continue to Next but not continue)

下面是XPath方法,但是使用了最少的XPath术语。

基于元素属性值的常规选择(用于比较):

// for matching <element class="foo bar baz">...</element> by 'bar'
var things = document.querySelectorAll('[class*="bar"]');
for (var i = 0; i < things.length; i++) {
    things[i].style.outline = '1px solid red';
}

基于元素内文本的XPath选择。

// for matching <element>foo bar baz</element> by 'bar'
var things = document.evaluate('//*[contains(text(),"bar")]',document,null,XPathResult.ORDERED_NODE_SNAPSHOT_TYPE,null);
for (var i = 0; i < things.snapshotLength; i++) {
    things.snapshotItem(i).style.outline = '1px solid red';
}

这里是不区分大小写的,因为文本更不稳定:

// for matching <element>foo bar baz</element> by 'bar' case-insensitively
var things = document.evaluate('//*[contains(translate(text(),"ABCDEFGHIJKLMNOPQRSTUVWXYZ","abcdefghijklmnopqrstuvwxyz"),"bar")]',document,null,XPathResult.ORDERED_NODE_SNAPSHOT_TYPE,null);
for (var i = 0; i < things.snapshotLength; i++) {
    things.snapshotItem(i).style.outline = '1px solid red';
}

谷歌有这作为顶部结果为那些谁需要找到一个节点与特定的文本。 通过更新,节点列表现在在现代浏览器中是可迭代的,而不必将其转换为数组。

解决方案可以像这样使用forEach。

var elList = document.querySelectorAll(".some .selector");
elList.forEach(function(el) {
    if (el.innerHTML.indexOf("needle") !== -1) {
        // Do what you like with el
        // The needle is case sensitive
    }
});

当一个普通的选择器不能选择一个节点时,我可以在节点列表中查找/替换文本,所以我必须一个接一个地过滤每个节点以检查它是否有针。