我有问题添加一个数组的所有元素以及平均它们。我将如何做到这一点，并实现它与我目前的代码?元素的定义如下所示。
<script type="text/javascript">
//<![CDATA[
var i;
var elmt = new Array();
elmt[0] = "0";
elmt[1] = "1";
elmt[2] = "2";
elmt[3] = "3";
elmt[4] = "4";
elmt[5] = "7";
elmt[6] = "8";
elmt[7] = "9";
elmt[8] = "10";
elmt[9] = "11";
// Problem here
for (i = 9; i < 10; i++){
document.write("The sum of all the elements is: " + /* Problem here */ + " The average of all the elements is: " + /* Problem here */ + "<br/>");
}
//]]>
</script>
当前回答
var scores =[90, 98, 89, 100, 100, 86, 94];
var sum = 0;
var avg = 0;
for(var i = 0; i < scores.length;i++){
//Taking sum of all the arraylist
sum = sum + scores[i];
}
//Taking average
avg = sum/scores.length;
//this is the function to round a decimal no
var round = avg.toFixed();
console.log(round);
其他回答
在这种情况下，我推荐D3。它是最易读的(并提供了2种不同的平均值)
let d3 = require('d3');
let array = [1,2,3,4];
let sum = d3.sum(array); //10
let mean = d3.mean(array); //2.5
let median = d3.median(array);
无刷疤痕 = [1，2，3，4，5]
function avg(arr){
var sum = 0;
for (var i = 0; i < arr.length; i++) {
sum += parseFloat(arr[i])
}
return sum / i;
}
======>>>> 3
这适用于字符串作为数字或数组中的数字。
只是为了好玩:
var elmt = [0, 1, 2,3, 4, 7, 8, 9, 10, 11], l = elmt.length, i = -1, sum = 0;
for (; ++i < l; sum += elmt[i])
;
document.body.appendChild(document.createTextNode('The sum of all the elements is: ' + sum + ' The average of all the elements is: ' + (sum / l)));
一种狡猾的方法可以做到这一点，尽管它确实需要使用(非常讨厌的)eval()。
var sum = eval(elmt.join('+')), avg = sum / elmt.length;
document.write("The sum of all the elements is: " + sum + " The average of all the elements is: " + avg + "<br/>");
我只是想把这个作为“盒子外”的选项之一。你永远不知道，狡猾可能会给你加分(或扣分)。
var scores =[90, 98, 89, 100, 100, 86, 94];
var sum = 0;
var avg = 0;
for(var i = 0; i < scores.length;i++){
//Taking sum of all the arraylist
sum = sum + scores[i];
}
//Taking average
avg = sum/scores.length;
//this is the function to round a decimal no
var round = avg.toFixed();
console.log(round);
