我有问题添加一个数组的所有元素以及平均它们。我将如何做到这一点，并实现它与我目前的代码?元素的定义如下所示。
<script type="text/javascript">
//<![CDATA[
var i;
var elmt = new Array();
elmt[0] = "0";
elmt[1] = "1";
elmt[2] = "2";
elmt[3] = "3";
elmt[4] = "4";
elmt[5] = "7";
elmt[6] = "8";
elmt[7] = "9";
elmt[8] = "10";
elmt[9] = "11";
// Problem here
for (i = 9; i < 10; i++){
document.write("The sum of all the elements is: " + /* Problem here */ + " The average of all the elements is: " + /* Problem here */ + "<br/>");
}
//]]>
</script>
当前回答
在这种情况下，我推荐D3。它是最易读的(并提供了2种不同的平均值)
let d3 = require('d3');
let array = [1,2,3,4];
let sum = d3.sum(array); //10
let mean = d3.mean(array); //2.5
let median = d3.median(array);
其他回答
ES6
Const average = arr => arr。Reduce ((p, c) => p + c, 0) / arr.length; Const result = average([4,4,5,6,6]);/ / 5 console.log(结果);
这是你的一句台词:
var average = arr.reduce((sum,item,index,arr)=>index !== arr.length-1?sum+item:sum+item/arr.length,0)
一般来说，平均使用一行程序减少是这样的
elements.reduce(function(sum, a,i,ar) { sum += a; return i==ar.length-1?(ar.length==0?0:sum/ar.length):sum},0);
特别是被问到的问题
elements.reduce(function(sum, a,i,ar) { sum += parseFloat(a); return i==ar.length-1?(ar.length==0?0:sum/ar.length):sum},0);
一个有效的版本是
elements.reduce(function(sum, a) { return sum + a },0)/(elements.length||1);
1分钟内理解Javascript数组缩减 http://www.airpair.com/javascript/javascript-array-reduce
正如gotofritz指出的数组。Reduce跳过未定义的值。 所以这里有一个解决方案:
(function average(arr){var finalstate=arr.reduce(function(state,a) { state.sum+=a;state.count+=1; return state },{sum:0,count:0}); return finalstate.sum/finalstate.count})([2,,,6])
我认为这可能是用for循环和函数计算平均值的直接解决方案。
var elmts = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11];
function average(arr) {
var total = 0;
for (var i = 0; i < arr.length; i++) {
total += arr[i];
}
console.log(Math.round(total/arr.length));
}
average(elmts);
var scores =[90, 98, 89, 100, 100, 86, 94];
var sum = 0;
var avg = 0;
for(var i = 0; i < scores.length;i++){
//Taking sum of all the arraylist
sum = sum + scores[i];
}
//Taking average
avg = sum/scores.length;
//this is the function to round a decimal no
var round = avg.toFixed();
console.log(round);
