func helperCapitalizeFirstLetter(stringToBeCapd:String)->String{
    let capString = stringToBeCapd.substringFromIndex(stringToBeCapd.startIndex).capitalizedString
    return capString
}

也工作，只是传递你的字符串，并得到一个大写的回来。

对于swift 5，你可以简单地这样做:

为字符串创建扩展:

extension String {
    var firstUppercased: String {
        let firstChar = self.first?.uppercased() ?? ""
        return firstChar + self.dropFirst()
    }
}

then

yourString.firstUppercased

样本:"abc" -> "abc"

Swift 3 (xcode 8.3.3)

大写字符串的所有首字符

let str = "your string"
let capStr = str.capitalized

//Your String

全部大写

let str = "your string"
let upStr = str.uppercased()

//YOUR STRING

字符串的第一个字符只能大写

 var str = "your string"
 let capStr = String(str.characters.prefix(1)).uppercased() + String(str.characters.dropFirst())

//Your string

下面是我一小步一小步完成的方法，类似于@Kirsteins。

func capitalizedPhrase(phrase:String) -> String {
    let firstCharIndex = advance(phrase.startIndex, 1)
    let firstChar = phrase.substringToIndex(firstCharIndex).uppercaseString
    let firstCharRange = phrase.startIndex..<firstCharIndex
    return phrase.stringByReplacingCharactersInRange(firstCharRange, withString: firstChar)
}

Swift 2.0(单行):

String(nameOfString.characters.prefix(1)).uppercaseString + String(nameOfString.characters.dropFirst())

包括与API准则一致的突变和非突变版本。

斯威夫特3:

extension String {
    func capitalizingFirstLetter() -> String {
        let first = String(characters.prefix(1)).capitalized
        let other = String(characters.dropFirst())
        return first + other
    }

    mutating func capitalizeFirstLetter() {
        self = self.capitalizingFirstLetter()
    }
}

斯威夫特4:

extension String {
    func capitalizingFirstLetter() -> String {
      return prefix(1).uppercased() + self.lowercased().dropFirst()
    }

    mutating func capitalizeFirstLetter() {
      self = self.capitalizingFirstLetter()
    }
}