我假设您想要将整个单词串的第一个单词大写。例如:“我的猫很胖，我的脂肪很松弛”应该返回“我的猫很胖，我的脂肪很松弛”。

Swift 5:

为此，您可以导入Foundation，然后使用大写的属性。例子:

import Foundation
var x = "my cat is fat, and my fat is flabby"
print(x.capitalized)  //prints "My Cat Is Fat, And My Fat Is Flabby"

如果你想成为一个纯粹主义者，不导入基础，那么你可以创建一个字符串扩展。

extension String {
    func capitalize() -> String {
        let arr = self.split(separator: " ").map{String($0)}
        var result = [String]()
        for element in arr {
            result.append(String(element.uppercased().first ?? " ") + element.suffix(element.count-1))
        }
        return result.joined(separator: " ")
    }
}

然后你可以这样使用:

var x = "my cat is fat, and my fat is flabby"
print(x.capitalize()) //prints "My Cat Is Fat, And My Fat Is Flabby"

Swift 3 (xcode 8.3.3)

大写字符串的所有首字符

let str = "your string"
let capStr = str.capitalized

//Your String

全部大写

let str = "your string"
let upStr = str.uppercased()

//YOUR STRING

字符串的第一个字符只能大写

 var str = "your string"
 let capStr = String(str.characters.prefix(1)).uppercased() + String(str.characters.dropFirst())

//Your string

func helperCapitalizeFirstLetter(stringToBeCapd:String)->String{
    let capString = stringToBeCapd.substringFromIndex(stringToBeCapd.startIndex).capitalizedString
    return capString
}

也工作，只是传递你的字符串，并得到一个大写的回来。

Swift 3更新

replaceRange函数现在是replaceSubrange

nameOfString.replaceSubrange(nameOfString.startIndex...nameOfString.startIndex, with: String(nameOfString[nameOfString.startIndex]).capitalized)

包括与API准则一致的突变和非突变版本。

斯威夫特3:

extension String {
    func capitalizingFirstLetter() -> String {
        let first = String(characters.prefix(1)).capitalized
        let other = String(characters.dropFirst())
        return first + other
    }

    mutating func capitalizeFirstLetter() {
        self = self.capitalizingFirstLetter()
    }
}

斯威夫特4:

extension String {
    func capitalizingFirstLetter() -> String {
      return prefix(1).uppercased() + self.lowercased().dropFirst()
    }

    mutating func capitalizeFirstLetter() {
      self = self.capitalizingFirstLetter()
    }
}

extension String {
    var lowercased:String {
        var result = Array<Character>(self.characters);
        if let first = result.first { result[0] = Character(String(first).uppercaseString) }
        return String(result)
    }
}