我正在运行一个服务器，我想显示我自己的IP地址。
获取计算机自身(如果可能的话，外部)IP地址的语法是什么?
有人编写了以下代码。
IPHostEntry host;
string localIP = "?";
host = Dns.GetHostEntry(Dns.GetHostName());
foreach (IPAddress ip in host.AddressList)
{
if (ip.AddressFamily.ToString() == "InterNetwork")
{
localIP = ip.ToString();
}
}
return localIP;
然而，我通常不信任作者，我不理解这段代码。有更好的方法吗?
当前回答
private static string GetLocalIpAdresse()
{
var host = Dns.GetHostEntry(Dns.GetHostName());
foreach(var ip in host.AddressList)
{
if (ip.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork)
{
return ip.ToString();
}
}
throw new Exception ("No network adapters with an IPv4 address in the system");
}
其他回答
如果你想避免使用DNS:
List<IPAddress> ipList = new List<IPAddress>();
foreach (var netInterface in NetworkInterface.GetAllNetworkInterfaces())
{
foreach (var address in netInterface.GetIPProperties().UnicastAddresses)
{
if (address.Address.AddressFamily == AddressFamily.InterNetwork)
{
Console.WriteLine("found IP " + address.Address.ToString());
ipList.Add(address.Address);
}
}
}
private static string GetLocalIpAdresse()
{
var host = Dns.GetHostEntry(Dns.GetHostName());
foreach(var ip in host.AddressList)
{
if (ip.AddressFamily == System.Net.Sockets.AddressFamily.InterNetwork)
{
return ip.ToString();
}
}
throw new Exception ("No network adapters with an IPv4 address in the system");
}
我只是想添加我自己的一行代码(尽管已经有许多其他有用的答案)。
string ipAddress = new WebClient().DownloadString("http://icanhazip.com");
试试这个:
IPAddress[] localIPs = Dns.GetHostAddresses(Dns.GetHostName());
String MyIp = localIPs[0].ToString();
这是我解决它的方法。我知道如果你有几个物理接口，这可能不会选择你想要的确切的eth。
private string FetchIP()
{
//Get all IP registered
List<string> IPList = new List<string>();
IPHostEntry host;
host = Dns.GetHostEntry(Dns.GetHostName());
foreach (IPAddress ip in host.AddressList)
{
if (ip.AddressFamily == AddressFamily.InterNetwork)
{
IPList.Add(ip.ToString());
}
}
//Find the first IP which is not only local
foreach (string a in IPList)
{
Ping p = new Ping();
string[] b = a.Split('.');
string ip2 = b[0] + "." + b[1] + "." + b[2] + ".1";
PingReply t = p.Send(ip2);
p.Dispose();
if (t.Status == IPStatus.Success && ip2 != a)
{
return a;
}
}
return null;
}
