我正在运行一个服务器,我想显示我自己的IP地址。

获取计算机自身(如果可能的话,外部)IP地址的语法是什么?

有人编写了以下代码。

IPHostEntry host;
string localIP = "?";
host = Dns.GetHostEntry(Dns.GetHostName());
foreach (IPAddress ip in host.AddressList)
{
    if (ip.AddressFamily.ToString() == "InterNetwork")
    {
        localIP = ip.ToString();
    }
}
return localIP;

然而,我通常不信任作者,我不理解这段代码。有更好的方法吗?


当前回答

namespace NKUtilities 
{
    using System;
    using System.Net;
    using System.Net.Sockets;

    public class DNSUtility
    {
        public static int Main(string [] args)
        {
            string strHostName = "";
            try {

                if(args.Length == 0)
                {
                    // Getting Ip address of local machine...
                    // First get the host name of local machine.
                    strHostName = Dns.GetHostName();
                    Console.WriteLine ("Local Machine's Host Name: " +  strHostName);
                }
                else
                {
                    // Otherwise, get the IP address of the host provided on the command line.
                    strHostName = args[0];
                }

                // Then using host name, get the IP address list..
                IPHostEntry ipEntry = Dns.GetHostEntry (strHostName);
                IPAddress [] addr = ipEntry.AddressList;

                for(int i = 0; i < addr.Length; i++)
                {
                    Console.WriteLine("IP Address {0}: {1} ", i, addr[i].ToString());
                }
                return 0;

            } 
            catch(SocketException se) 
            {
                Console.WriteLine("{0} ({1})", se.Message, strHostName);
                return -1;
            } 
            catch(Exception ex) 
            {
                Console.WriteLine("Error: {0}.", ex.Message);
                return -1;
            }
        }
    }
}

详情请看这里。

你必须记住你的电脑可以有多个IP(实际上它总是这样)-所以你是哪一个。

其他回答

namespace NKUtilities 
{
    using System;
    using System.Net;

    public class DNSUtility
    {
        public static int Main (string [] args)
        {

          String strHostName = new String ("");
          if (args.Length == 0)
          {
              // Getting Ip address of local machine...
              // First get the host name of local machine.
              strHostName = Dns.GetHostName ();
              Console.WriteLine ("Local Machine's Host Name: " +  strHostName);
          }
          else
          {
              strHostName = args[0];
          }

          // Then using host name, get the IP address list..
          IPHostEntry ipEntry = DNS.GetHostByName (strHostName);
          IPAddress [] addr = ipEntry.AddressList;

          for (int i = 0; i < addr.Length; i++)
          {
              Console.WriteLine ("IP Address {0}: {1} ", i, addr[i].ToString ());
          }
          return 0;
        }    
     }
}
return Dns.GetHostEntry(Dns.GetHostName()).AddressList.FirstOrDefault(ip => ip.AddressFamily == AddressFamily.InterNetwork);

简单的一行代码,返回第一个内部IPV4地址,如果没有则返回null。作为上面的注释添加,但可能对某人有用(上面的一些解决方案将返回多个需要进一步过滤的地址)。

它也很容易返回环回而不是null,我猜用:

return Dns.GetHostEntry(Dns.GetHostName()).AddressList.FirstOrDefault(ip => ip.AddressFamily == AddressFamily.InterNetwork) ?? new IPAddress( new byte[] {127, 0, 0, 1} );

我只是想添加我自己的一行代码(尽管已经有许多其他有用的答案)。


string ipAddress = new WebClient().DownloadString("http://icanhazip.com");

不,这几乎是最好的方法。由于一台机器可能有多个IP地址,您需要迭代它们的集合以找到合适的一个。

编辑:我唯一想改变的是改变这个:

if (ip.AddressFamily.ToString() == "InterNetwork")

:

if (ip.AddressFamily == AddressFamily.InterNetwork)

不需要ToString一个枚举进行比较。

了解你的公共IP的唯一方法是让别人告诉你;这段代码可以帮助你:

public string GetPublicIP()
{
    String direction = "";
    WebRequest request = WebRequest.Create("http://checkip.dyndns.org/");
    using (WebResponse response = request.GetResponse())
    using (StreamReader stream = new StreamReader(response.GetResponseStream()))
    {
        direction = stream.ReadToEnd();
    }

    //Search for the ip in the html
    int first = direction.IndexOf("Address: ") + 9;
    int last = direction.LastIndexOf("</body>");
    direction = direction.Substring(first, last - first);

    return direction;
}