我在Android O操作系统上使用服务类。
我计划在后台使用服务。
Android文档指出
如果你的应用程序的API级别为26或更高，系统会对使用或创建后台服务施加限制，除非应用程序本身在前台。如果应用程序需要创建前台服务，应用程序应该调用startForegroundService()。
如果使用startForegroundService()，服务抛出以下错误。
Context.startForegroundService() did not then call
Service.startForeground()
这有什么问题?
当前回答
请不要在onCreate()方法中调用任何StartForgroundServices，你必须在onStartCommand()中调用StartForground services，否则你将总是得到ANR，所以请不要在onStartCommand()的主线程中编写复杂的登录;
public class Services extends Service {
private static final String ANDROID_CHANNEL_ID = "com.xxxx.Location.Channel";
@Nullable
@Override
public IBinder onBind(Intent intent) {
return null;
}
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
Notification.Builder builder = new Notification.Builder(this, ANDROID_CHANNEL_ID)
.setContentTitle(getString(R.string.app_name))
.setContentText("SmartTracker Running")
.setAutoCancel(true);
Notification notification = builder.build();
startForeground(1, notification);
Log.e("home_button","home button");
} else {
NotificationCompat.Builder builder = new NotificationCompat.Builder(this)
.setContentTitle(getString(R.string.app_name))
.setContentText("SmartTracker is Running...")
.setPriority(NotificationCompat.PRIORITY_DEFAULT)
.setAutoCancel(true);
Notification notification = builder.build();
startForeground(1, notification);
Log.e("home_button_value","home_button_value");
}
return super.onStartCommand(intent, flags, startId);
}
}
编辑:小心!start前台函数不能以0作为第一个参数，它将引发异常!这个例子包含错误的函数调用，将0更改为你自己的const，它不能为0或大于Max(Int32)
其他回答
我一直在研究这个问题，这是我目前为止的发现。如果我们有类似这样的代码，就会发生崩溃:
MyForegroundService.java
public class MyForegroundService extends Service {
@Override
public void onCreate() {
super.onCreate();
startForeground(...);
}
}
MainActivity.java
Intent serviceIntent = new Intent(this, MyForegroundService.class);
startForegroundService(serviceIntent);
...
stopService(serviceIntent);
异常在以下代码块中抛出:
ActiveServices.java
private final void bringDownServiceLocked(ServiceRecord r) {
...
if (r.fgRequired) {
Slog.w(TAG_SERVICE, "Bringing down service while still waiting for start foreground: "
+ r);
r.fgRequired = false;
r.fgWaiting = false;
mAm.mAppOpsService.finishOperation(AppOpsManager.getToken(mAm.mAppOpsService),
AppOpsManager.OP_START_FOREGROUND, r.appInfo.uid, r.packageName);
mAm.mHandler.removeMessages(
ActivityManagerService.SERVICE_FOREGROUND_TIMEOUT_MSG, r);
if (r.app != null) {
Message msg = mAm.mHandler.obtainMessage(
ActivityManagerService.SERVICE_FOREGROUND_CRASH_MSG);
msg.obj = r.app;
msg.getData().putCharSequence(
ActivityManagerService.SERVICE_RECORD_KEY, r.toString());
mAm.mHandler.sendMessage(msg);
}
}
...
}
这个方法在MyForegroundService的onCreate()之前执行，因为Android在主线程处理程序上安排了服务的创建，但在BinderThread上调用了bringdownservicelock，这是一个竞争条件。这意味着MyForegroundService没有机会调用start前台，这将导致崩溃。
为了解决这个问题，我们必须确保在MyForegroundService的onCreate()之前不调用bringdownservicellocked。
public class MyForegroundService extends Service {
private static final String ACTION_STOP = "com.example.MyForegroundService.ACTION_STOP";
private final BroadcastReceiver stopReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
context.removeStickyBroadcast(intent);
stopForeground(true);
stopSelf();
}
};
@Override
public void onCreate() {
super.onCreate();
startForeground(...);
registerReceiver(
stopReceiver, new IntentFilter(ACTION_STOP));
}
@Override
public void onDestroy() {
super.onDestroy();
unregisterReceiver(stopReceiver);
}
public static void stop(Context context) {
context.sendStickyBroadcast(new Intent(ACTION_STOP));
}
}
通过使用粘性广播，我们确保广播不会丢失，stopReceiver在MyForegroundService的onCreate()中注册后立即接收到停止意图。此时我们已经调用了startForeground(…)。我们还必须删除这个粘滞的广播，以防止下一次stopReceiver被通知。
请注意，sendStickyBroadcast方法已弃用，我仅将其用作解决此问题的临时方法。
https://developer.android.com/reference/android/content/Context.html startForegroundService (android.content.Intent)
类似于startService(Intent)，但是有一个隐含的承诺 Service将调用start前台(int, android.app.Notification)一次 它开始运行。该服务被赋予了相当的时间 到ANR区间做这个，否则系统会 自动停止服务并声明应用程序ANR。 与普通的startService(Intent)不同，这个方法可以在 任何时候，不管托管服务的应用程序是否在 前景的国家。
一定要打电话给服务处。在onCreate()上的start前台(int, android.app.Notification)，所以你确保它将被调用..如果你有任何条件，可能会阻止你这样做，那么你最好使用正常的Context.startService(意图)并调用服务。start前台(int, android.app.Notification)你自己。
似乎Context.startForegroundService()添加了一个看门狗来确保你调用了服务。start前台(int, android.app.Notification)在它被销毁之前…
请不要在onCreate()方法中调用任何StartForgroundServices，你必须在onStartCommand()中调用StartForground services，否则你将总是得到ANR，所以请不要在onStartCommand()的主线程中编写复杂的登录;
public class Services extends Service {
private static final String ANDROID_CHANNEL_ID = "com.xxxx.Location.Channel";
@Nullable
@Override
public IBinder onBind(Intent intent) {
return null;
}
@Override
public int onStartCommand(Intent intent, int flags, int startId) {
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.O) {
Notification.Builder builder = new Notification.Builder(this, ANDROID_CHANNEL_ID)
.setContentTitle(getString(R.string.app_name))
.setContentText("SmartTracker Running")
.setAutoCancel(true);
Notification notification = builder.build();
startForeground(1, notification);
Log.e("home_button","home button");
} else {
NotificationCompat.Builder builder = new NotificationCompat.Builder(this)
.setContentTitle(getString(R.string.app_name))
.setContentText("SmartTracker is Running...")
.setPriority(NotificationCompat.PRIORITY_DEFAULT)
.setAutoCancel(true);
Notification notification = builder.build();
startForeground(1, notification);
Log.e("home_button_value","home_button_value");
}
return super.onStartCommand(intent, flags, startId);
}
}
编辑:小心!start前台函数不能以0作为第一个参数，它将引发异常!这个例子包含错误的函数调用，将0更改为你自己的const，它不能为0或大于Max(Int32)
我在@humazed答案中添加了一些代码。所以没有初始通知。这可能是个变通办法，但对我来说很管用。
@Override
public void onCreate() {
super.onCreate();
if (Build.VERSION.SDK_INT >= 26) {
String CHANNEL_ID = "my_channel_01";
NotificationChannel channel = new NotificationChannel(CHANNEL_ID,
"Channel human readable title",
NotificationManager.IMPORTANCE_DEFAULT);
((NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE)).createNotificationChannel(channel);
Notification notification = new NotificationCompat.Builder(this, CHANNEL_ID)
.setContentTitle("")
.setContentText("")
.setColor(ContextCompat.getColor(this, R.color.transparentColor))
.setSmallIcon(ContextCompat.getColor(this, R.color.transparentColor)).build();
startForeground(1, notification);
}
}
我在小图标和通知上添加了transparentColor。 它会起作用的。
服务
class TestService : Service() {
override fun onCreate() {
super.onCreate()
Log.d(TAG, "onCreate")
val nBuilder = NotificationCompat.Builder(this, "all")
.setSmallIcon(R.drawable.ic_launcher_foreground)
.setContentTitle("TestService")
.setPriority(NotificationCompat.PRIORITY_DEFAULT)
startForeground(1337, nBuilder.build())
}
override fun onStartCommand(intent: Intent?, flags: Int, startId: Int): Int {
val rtn = super.onStartCommand(intent, flags, startId)
if (intent?.action == STOP_ACTION) {
Log.d(TAG, "onStartCommand -> STOP")
stopForeground(true)
stopSelf()
} else {
Log.d(TAG, "onStartCommand -> START")
}
return rtn
}
override fun onDestroy() {
Log.d(TAG, "onDestroy")
super.onDestroy()
}
override fun onBind(intent: Intent?): IBinder? = null
companion object {
private val TAG = "TestService"
private val STOP_ACTION = "ly.zen.test.TestService.ACTION_STOP"
fun start(context: Context) {
ContextCompat.startForegroundService(context, Intent(context, TestService::class.java))
}
fun stop(context: Context) {
val intent = Intent(context, TestService::class.java)
intent.action = STOP_ACTION
ContextCompat.startForegroundService(context, intent)
}
}
}
测试人员
val nChannel = NotificationChannel("all", "All", NotificationManager.IMPORTANCE_NONE)
val nManager = getSystemService(Context.NOTIFICATION_SERVICE) as NotificationManager
nManager.createNotificationChannel(nChannel)
start_test_service.setOnClickListener {
TestService.start(this@MainActivity)
TestService.stop(this@MainActivity)
}
结果
D/TestService: onCreate
D/TestService: onStartCommand -> START
D/TestService: onStartCommand -> STOP
D/TestService: onDestroy
